// Success consists of going from failure to failure without loss of enthusiasm
#include <bits/stdc++.h>
using namespace std;
#define nl '\n'
#define pb push_back
#define sz(x) int(x.size())
using ll = long long;
template<class T> using V = vector<T>;
using vl = V<ll>;
using vi = V<int>;
int main() {
cin.tie(0)->sync_with_stdio(0);
int N, K; cin >> N >> K;
vi A(N); for(auto& x : A) cin >> x;
vl P(N);
V<vi> adj(N); for(int i = 0; i < N - 1; i++) {
int u, v; cin >> u >> v; --u, --v;
adj[u].pb(v);
adj[v].pb(u);
P[u] += A[v], P[v] += A[u];
}
ll ans = 0;
V<V<vl>> up(N, V<vl>(K + 1, vl(2, 0))), dwn(N, V<vl>(K + 1, vl(2, 0)));
function<void(int, int)> gen = [&](int u, int p) {
if (K) up[u][1][1] = dwn[u][1][1] = P[u];
vl mx0(K + 1), mx1(K + 1);
for(auto& v : adj[u]) if (v != p) {
gen(v, u);
for(int k = 0; k <= K; k++) {
// cout << u << " " << v << " " << k << " => 0 => " << mx0[k] << " " << up[u][K - k][0] << endl;
// if (k) cout << u << " " << v << " " << k << " => 1 => " << mx1[k] << " " << up[u][K + 1 - k][1] - P[u] << endl;
ans = max(ans, mx0[k] + up[u][K - k][0]);
if (k) ans = max(ans, mx1[k] + up[u][K + 1 - k][1] - P[u]);
}
for(int k = 0; k <= K; k++) {
mx0[k] = max(mx0[k], dwn[u][k][0]);
mx1[k] = max(mx1[k], dwn[u][k][1]);
if (k) mx0[k] = max(mx0[k], mx0[k - 1]), mx0[k] = max(mx0[k], mx0[k - 1]);
up[u][k][0] = max({up[u][k][0], up[v][k][0], up[v][k][1]});
if (k) up[u][k][1] = max({up[u][k][1], up[v][k - 1][0] + P[u] - A[v], up[v][k - 1][1] + P[u] - A[v]});
dwn[u][k][0] = max({dwn[u][k][0], dwn[v][k][1] - A[u], dwn[v][k][0]});
if (k) dwn[u][k][1] = max({dwn[u][k][1], dwn[v][k - 1][1] - A[u] + P[u], dwn[v][k - 1][0] + P[u]});
}
}
for(int k = 0; k <= K; k++) ans = max({ans, up[u][k][0], up[u][k][1], dwn[u][k][0], dwn[u][k][1]});
// cout << "NODE: " << u << " | CUR ANS: " << ans << endl;
// for(int k = 0; k <= K; k++) for(int x = 0; x < 2; x++) cout << k << " " << x << " => " << up[u][k][x] << " " << dwn[u][k][x] << endl;
// for(int x = 0; x < 2; x++) {
// vl mx(K + 1); mx[0] = up[u][0][x];
// for(int i = 1; i <= K; i++) mx[i] = max(up[u][i][x], mx[i - 1]);
// for(int i = 0; i <= K; i++) {
// cout << i << " => " << mx[K - i] << " " << dwn[u][i][x] << " " << x * P[u] << endl;
// ans = max(ans, mx[K - i] + dwn[u][i][x] - x * P[u]);
// }
// }
};
gen(0, -1);
cout << ans << nl;
exit(0-0);
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
0 ms |
344 KB |
Output is correct |
2 |
Incorrect |
0 ms |
500 KB |
Output isn't correct |
3 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
0 ms |
344 KB |
Output is correct |
2 |
Incorrect |
0 ms |
500 KB |
Output isn't correct |
3 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Runtime error |
410 ms |
524288 KB |
Execution killed with signal 9 |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
0 ms |
344 KB |
Output is correct |
2 |
Incorrect |
0 ms |
500 KB |
Output isn't correct |
3 |
Halted |
0 ms |
0 KB |
- |