Submission #922377

#TimeUsernameProblemLanguageResultExecution timeMemory
922377chrislaiisme앨리스, 밥, 서킷 (APIO23_abc)C++17
12 / 100
125 ms9944 KiB
#include "abc.h" #include<vector> using namespace std; // you may find the definitions useful const int OP_ZERO = 0; // f(OP_ZERO, x0, x1) = 0 const int OP_NOR = 1; // f(OP_NOR, x0, x1) = !(x0 || x1) const int OP_GREATER = 2; // f(OP_GREATER, x0, x1) = (x0 > x1) const int OP_NOT_X1 = 3; // f(OP_NOT_X1, x0, x1) = !x1 const int OP_LESS = 4; // f(OP_LESS, x0, x1) = (x0 < x1) const int OP_NOT_X0 = 5; // f(OP_NOT_X0, x0, x1) = !x0 const int OP_XOR = 6; // f(OP_XOR, x0, x1) = (x0 ^ x1) const int OP_NAND = 7; // f(OP_NAND, x0, x1) = !(x0 && x1) const int OP_AND = 8; // f(OP_AND, x0, x1) = (x0 && x1) const int OP_EQUAL = 9; // f(OP_EQUAL, x0, x1) = (x0 == x1) const int OP_X0 = 10; // f(OP_X0, x0, x1) = x0 const int OP_GEQ = 11; // f(OP_GEQ, x0, x1) = (x0 >= x1) const int OP_X1 = 12; // f(OP_X1, x0, x1) = x1 const int OP_LEQ = 13; // f(OP_LEQ, x0, x1) = (x0 <= x1) const int OP_OR = 14; // f(OP_OR, x0, x1) = (x0 || x1) const int OP_ONE = 15; // f(OP_ONE, x0, x1) = 1 const int NUM_LEN = 16; #define FOR(i) for(int i=0; i<NUM_LEN; i++) // Alice int // returns la alice( /* in */ const int n, /* in */ const char names[][5], /* in */ const unsigned short numbers[], /* out */ bool outputs_alice[] ) { for (int i = 0; i < NUM_LEN; i ++ ) { outputs_alice[i] = (numbers[0] >> i) & 1; } return NUM_LEN; } // Bob int // returns lb bob( /* in */ const int m, /* in */ const char senders[][5], /* in */ const char recipients[][5], /* out */ bool outputs_bob[] ) { for (int i = 0; i < NUM_LEN; i ++ ) { outputs_bob[i] = (m >> i) & 1; } return NUM_LEN; } // Circuit int // returns l circuit( /* in */ const int la, /* in */ const int lb, /* out */ int operations[], /* out */ int operands[][2], /* out */ int outputs_circuit[][16] ) { // =============== Initializations =============== int cur = la + lb; // =============== Functions =============== auto op = [&](int o, int a, int b) { operations[cur] = o; operands[cur][0] = a, operands[cur][1] = b; return cur ++ ; }; int zero = op(OP_ZERO, 0, 0); auto ADD = [&](int a, int b) { vector<int> carry = {zero}, digit; FOR(i) { int d = op(OP_XOR, a+i, b+i); int c1 = op(OP_AND, a+i, b+i); int c2 = op(OP_AND, d, carry[i]); if(i != NUM_LEN-1) carry.push_back(op(OP_OR, c1, c2)); digit.push_back(d); } int ret = cur; FOR(i) op(OP_XOR, digit[i], carry[i]); return ret; }; // ================ Solve =============== int a = 0, b = la, ans = cur; FOR(i) op(OP_ZERO, 0, 0); FOR(i) { int p = cur; FOR(j) op(OP_AND, b+i, a+j); ans = ADD(ans, p); a = ADD(a, a); } FOR(i) outputs_circuit[0][i] = ans+i; return cur; }
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