이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#pragma GCC optimize("O3,unroll-loops")
// #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
// Ofast, O0, O1, O2, O3, unroll-loops, fast-math, trapv
typedef long long ll;
typedef pair<ll, ll> pll;
typedef pair<int, int> pii;
#define Mp make_pair
#define sep ' '
#define endl '\n'
#define F first
#define S second
#define pb push_back
#define all(x) (x).begin(),(x).end()
#define kill(res) cout << res << '\n', exit(0);
#define set_dec(x) cout << fixed << setprecision(x);
#define fast_io ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define file_io freopen("input.txt", "r", stdin) ; freopen("output.txt", "w", stdout);
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const ll A = 27;
const ll N = 1e5 + 50;
const ll Mod = 1e9 + 7;
ll n, last[N];
string s;
vector<int> vec;
bool ok(int a, int b, int c, int d){
return (b * c <= a * d);
}
int main(){
fast_io;
cin >> n >> s;
s = "$" + s;
for(int i = 0; i < A; i++) vec.pb(0);
int l = 0, r = 0, d = A;
for(int i = 1; i <= n; i++){
vec.erase(find(all(vec), last[s[i] - 'a']));
last[s[i] - 'a'] = i;
vec.pb(last[s[i] - 'a']); sort(all(vec));
for(int j = 0; j < A-1; j++){
if(!vec[j+1]) continue;
if(ok(i - vec[j], A - j - 1, r - l + 1, d)){
l = vec[j] + 1; r = i; d = A - j - 1;
//cout << l << sep << r << sep << d << endl;
}
}
}
cout << l << sep << r;
}
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