제출 #922121

#제출 시각아이디문제언어결과실행 시간메모리
922121406다리 (APIO19_bridges)C++17
100 / 100
1785 ms106616 KiB
#include "bits/stdc++.h" #define FOR(i, a, b) for (int i = (a); i < (b); i++) using namespace std; const long long INF = 1ll << 60; const int N = 1e5 + 5; int dpr[N]; vector<array<int, 3>> undo; int gpr(int x) { while (dpr[x] >= 0) x = dpr[x]; return x; } bool merge(int u, int v) { u = gpr(u), v = gpr(v); if (u == v) return false; if (dpr[u] < dpr[v]) swap(u, v); //v is bigger now undo.push_back({u, v, dpr[u]}); dpr[v] += dpr[u]; dpr[u] = v; return true; } void rollback() { const auto &a = undo.back(); dpr[a[0]] = a[2]; dpr[a[1]] -= a[2]; undo.pop_back(); } const int SQ = 1000; const int SQ2 = N / SQ + 5; int a[N], b[N], U[N], W[N], V[N], n, m, q, ans[N]; short t[N]; void solve() { //t = 1 CHANGE //t = 2 SOAL FOR(i, 0, SQ2) { int L = i * SQ, R = min(q, (i + 1) * SQ); if (L >= q) break; memset(dpr, -1, sizeof dpr); bitset<N> change = 0, mark = 0; vector<int> Q, E, NE; FOR(j, L, R) { if (t[j] == 1) change[a[j]] = true; else Q.push_back(j); } FOR(j, 0, m) (change[j] ? NE : E).push_back(j); sort(E.rbegin(), E.rend(), [&](const int x, const int y) {return W[x] < W[y];}); sort(Q.begin(), Q.end(), [&](const int x, const int y) {return b[x] < b[y];}); for (auto qid: Q) { while (E.size() && W[E.back()] <= b[qid]) { merge(U[E.back()], V[E.back()]); E.pop_back(); } int cnt = 0; for (int j = qid; j >= L; j--) if (t[j] == 1 && !mark[a[j]]) { if (b[j] <= b[qid]) { cnt += merge(U[a[j]], V[a[j]]); mark[a[j]] = true; } mark[a[j]] = true; } for (auto e: NE) if (!mark[e]) { mark[e] = true; if (W[e] <= b[qid]) { cnt += merge(U[e], V[e]); mark[e] = true; } } ans[qid] = dpr[gpr(a[qid])]; while (cnt--) rollback(); FOR(j, L, qid) mark[a[j]] = false; for (auto e: NE) mark[e] = false; } FOR(j, L, R) if (t[j] == 1) W[a[j]] = b[j]; } FOR(i, 0, q) if (t[i] == 2) cout << -ans[i] << '\n'; } signed main() { ios::sync_with_stdio(0), cin.tie(0); cin >> n >> m; FOR(i, 0, m) { cin >> U[i] >> V[i] >> W[i]; U[i]--, V[i]--; W[i] = -W[i]; } cin >> q; FOR(i, 0, q) { cin >> t[i] >> a[i] >> b[i]; a[i]--; b[i] = -b[i]; } solve(); return 0; }
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