제출 #920303

#제출 시각아이디문제언어결과실행 시간메모리
920303PringAlice, Bob, and Circuit (APIO23_abc)C++17
54 / 100
74 ms11556 KiB
#include <bits/stdc++.h> #include "abc.h" using namespace std; #define fs first #define sc second #define mp make_pair #define FOR(i, j, k) for (int i = j, Z = k; i < Z; i++) typedef pair<int, int> pii; // you may find the definitions useful const int OP_ZERO = 0; // f(OP_ZERO, x0, x1) = 0 const int OP_NOR = 1; // f(OP_NOR, x0, x1) = !(x0 || x1) const int OP_GREATER = 2; // f(OP_GREATER, x0, x1) = (x0 > x1) const int OP_NOT_X1 = 3; // f(OP_NOT_X1, x0, x1) = !x1 const int OP_LESS = 4; // f(OP_LESS, x0, x1) = (x0 < x1) const int OP_NOT_X0 = 5; // f(OP_NOT_X0, x0, x1) = !x0 const int OP_XOR = 6; // f(OP_XOR, x0, x1) = (x0 ^ x1) const int OP_NAND = 7; // f(OP_NAND, x0, x1) = !(x0 && x1) const int OP_AND = 8; // f(OP_AND, x0, x1) = (x0 && x1) const int OP_EQUAL = 9; // f(OP_EQUAL, x0, x1) = (x0 == x1) const int OP_X0 = 10; // f(OP_X0, x0, x1) = x0 const int OP_GEQ = 11; // f(OP_GEQ, x0, x1) = (x0 >= x1) const int OP_X1 = 12; // f(OP_X1, x0, x1) = x1 const int OP_LEQ = 13; // f(OP_LEQ, x0, x1) = (x0 <= x1) const int OP_OR = 14; // f(OP_OR, x0, x1) = (x0 || x1) const int OP_ONE = 15; // f(OP_ONE, x0, x1) = 1 const int LEN = 16; // Alice int // returns la alice( /* in */ const int n, /* in */ const char names[][5], /* in */ const unsigned short numbers[], /* out */ bool outputs_alice[] ) { if (n == 1) { FOR(i, 0, LEN) outputs_alice[i] = ((numbers[0] >> i) & 1); return LEN; } vector<pair<string, int>> v(n); FOR(i, 0, n) v[i] = mp(string(names[i]), i); sort(v.begin(), v.end()); int cnt = 0; FOR(i, 0, n) { int id = v[i].sc; FOR(j, 0, LEN) { outputs_alice[cnt] = ((numbers[id] >> j) & 1); cnt++; } } FOR(i, 0, n) { int id = v[i].sc; FOR(j, 0, n) { outputs_alice[cnt] = (j == id); cnt++; } } return cnt; } // Bob int // returns lb bob( /* in */ const int m, /* in */ const char senders[][5], /* in */ const char recipients[][5], /* out */ bool outputs_bob[] ) { set<string> S; map<string, int> M; bitset<32> b[32]; FOR(i, 0, m) { S.insert(string(senders[i])); S.insert(string(recipients[i])); } int n = S.size(); if (n == 1) { FOR(i, 0, LEN) outputs_bob[i] = ((m >> i) & 1); return LEN; } { int cnt = 0; for (auto it = S.begin(); it != S.end(); it++) { M[*it] = cnt; cnt++; } } FOR(i, 0, m) { b[M[senders[i]]][M[recipients[i]]] = true; } int cnt = 0; FOR(i, 0, n) { FOR(j, 0, n) { outputs_bob[cnt] = b[i][j]; cnt++; } } return cnt; } // Circuit int // returns l circuit( /* in */ const int la, /* in */ const int lb, /* out */ int operations[], /* out */ int operands[][2], /* out */ int outputs_circuit[][16] ) { int cnt = la + lb; int n = sqrt(lb); auto add_op = [&](int input_a, int input_b, int op) { operations[cnt] = op; operands[cnt][0] = input_a, operands[cnt][1] = input_b; return cnt++; }; auto add_ops = [&](int inputs_a, int inputs_b, int op) { int pos = cnt; FOR(i, 0, LEN) { add_op(inputs_a + i, inputs_b + i, op); } return pos; }; int zero = add_ops(0, 0, OP_ZERO); auto LEFT = [&](int inputs, int p, int b, int op) { int pos = cnt; FOR(i, 0, LEN) { if (i < p) add_op(0, 0, OP_ZERO); else add_op(inputs + i - p, b, op); } return pos; }; auto adder = [&](int inputs_a, int inputs_b) { int c = zero, c1, c2, g1; vector<int> vc, vg; FOR(i, 0, LEN) { int a = inputs_a + i, b = inputs_b + i; c1 = add_op(a, b, OP_AND); g1 = add_op(a, b, OP_XOR); c2 = add_op(c, g1, OP_AND); vc.push_back(c); vg.push_back(g1); c = add_op(c1, c2, OP_OR); } int pos = cnt; FOR(i, 0, LEN) { add_op(vg[i], vc[i], OP_XOR); } return pos; }; auto muler = [&](int inputs_a, int inputs_b) { int now = zero; FOR(i, 0, LEN) { now = adder(now, LEFT(inputs_a, i, inputs_b + i, OP_AND)); } return now; }; if (la == LEN && lb == LEN) { int a = 0, b = LEN; int ans = muler(a, b); FOR(i, 0, LEN) outputs_circuit[0][i] = ans + i; return cnt; } vector<int> pos(n); FOR(i, 0, n) pos[i] = add_ops(0, 0, OP_ZERO); FOR(i, 0, n) { FOR(j, 0, n) { int a = i * LEN; int b = la + i * n + j; int tmp = LEFT(a, 0, b, OP_AND); pos[j] = adder(pos[j], tmp); } } vector<int> ans(n); FOR(i, 0, n) ans[i] = add_ops(0, 0, OP_ZERO); FOR(i, 0, n) { FOR(j, 0, n) { int b = n * LEN + i * n + j; ans[j] = add_ops(ans[j], LEFT(pos[i], 0, b, OP_AND), OP_OR); } } FOR(i, 0, n) { FOR(j, 0, LEN) outputs_circuit[i][j] = ans[i] + j; } return cnt; }
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