Submission #920155

#	Time	Username	Problem	Language	Result	Execution time	Memory
920155		Bzslayed	Sterilizing Spray (JOI15_sterilizing)	C++17	15 / 100	5037 ms	12792 KiB

sterilizing

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp> 
#include <ext/pb_ds/tree_policy.hpp> 

using namespace std;
using namespace __gnu_pbds; 

#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")

#define ll long long
#define pll pair<ll, ll>
#define pii pair<int, int>
#define coutpair(p) cout << p.first << " " << p.second << "\n"

typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
typedef tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_multiset;

struct node{
    int s, e, m; //range is [s,e], m is the middle point
    ll val; //sum of [s,e]
    node *l, *r; //create two children l and r, where l is [s,m] and [m+1,e]
    node (int S, int E){ //constructor called node
        s = S, e = E, m = (s+e)/2;
        val = 0; //initially all values are 0
	    if (s != e){ //node is not yet a leaf, so create two children
		    l = new node(s, m); //create left child
            r = new node(m+1, e); //create right child
		}
	}

    void spray(int S, int E, ll V){ //increment [S,E] by V
        if (V == 0 || V == 1) return;
        if (s == e){
            val /= V;
            return;
        }
        if (E <= m) l->spray(S, E, V); //[S,E] is in the left child
        else if (S > m) r->spray(S, E, V); //[S,E] is in the right child
        else l->spray(S, m, V), r->spray(m+1, E, V);
        val = l->val + r->val; //update the range sum
    }

    void adjust(int X, ll V){
        if (s == e){
            val = V;
            return;
        }
        else{
            if (X <= m) l->adjust(X, V);
            else r->adjust(X, V);
        }
        val = l->val + r->val; //update the range sum
    }

    ll sum(int S, int E){
        if (s == S && e == E) return val; //case 1
        if (E <= m) return l->sum(S, E); //case 2, recurse to left child
        else if (S >= m+1) return r->sum(S, E); //case 3, recurse to right child
        else return l->sum(S, m) + r->sum(m+1, E); //case 4, split the query range, recurse to both childs
    }
} *root;

int main(){
    ios_base::sync_with_stdio(0); 
    cin.tie(0); 
    cout.tie(0);

    ll n, q, k, c, s, t, u; cin >> n >> q >> k;
    root = new node(1, n);

    for (int i=1; i<=n; i++){
        cin >> c;
        root->adjust(i, c);
    }

    for (int i=0; i<q; i++){
        cin >> s >> t >> u;
        if (s == 1){
            root->adjust(t, u);
        }
        else if (s == 2){
            root->spray(t, u, k);
        }
        else cout << root->sum(t, u) << "\n";
    }

    return 0;
}

• Subtask 1: 5 / 5
• Subtask 2: 10 / 10
• Subtask 3: 0 / 10
• Subtask 4: 0 / 75