Submission #920070

#	Time	Username	Problem	Language	Result	Execution time	Memory
920070		coding_snorlax	Boxes with souvenirs (IOI15_boxes)	C++14	0 / 100	3 ms	600 KiB

boxes

#include "boxes.h"
#include<bits/stdc++.h>
#define ll long long int
using namespace std;
vector<ll> P;
vector<ll> Le,R,Ri;
ll n,k,l;
void pre_L(){
    Le.push_back(0);
    for(int i=0;i<k;i++) Le.push_back(2*P[i]);
    for(int i=k;i<n;i++){
        Le.push_back(2*P[i]+Le[i-k]);
    }
    Le.push_back(0);
}
void pre_R(){
    for(int i=n-1;i>=n-k;i--) R.push_back(2*(l-P[i]));
    for(int i=n-k-1;i>=0;i--){
        R.push_back(2*(l-P[i])+R[n-k-1-i]);
    }
    Ri.push_back(0);
    for(int i=n-1;i>=0;i--) Ri.push_back(R[i]);
    Ri.push_back(0);
}
long long cal(int lb,int rb){
    ll answer = ((rb-lb+1)/k)*l;
    if((rb-lb+1)%k) answer += l;
    answer += Le[lb-1];
    answer += Ri[rb+1];
    //cout << lb << " " << rb << " " << answer << "\n";
    return answer;
}
long long delivery(int N, int K, int L, int p[]) {
    for(int i=0;i<N;i++) P.push_back((ll)p[i]);
    sort(P.begin(),P.end());
    ll answer = 1000000000000000;
    n=N;k=K;l=L;
    pre_L();pre_R();
    for(int i=1;i<=N;i++){
        for(int j=i-1;j<=N;j++){
            answer = min(answer,cal(i,j));
        }
    }
    return answer;
}

Compilation message (stderr)

boxes.cpp: In function 'void pre_L()':
boxes.cpp:11:15: warning: conversion from 'long long int' to 'int' may change value [-Wconversion]
   11 |     for(int i=k;i<n;i++){
      |               ^
boxes.cpp: In function 'void pre_R()':
boxes.cpp:17:16: warning: conversion from 'long long int' to 'int' may change value [-Wconversion]
   17 |     for(int i=n-1;i>=n-k;i--) R.push_back(2*(l-P[i]));
      |               ~^~
boxes.cpp:18:18: warning: conversion from 'long long int' to 'int' may change value [-Wconversion]
   18 |     for(int i=n-k-1;i>=0;i--){
      |               ~~~^~
boxes.cpp:22:16: warning: conversion from 'long long int' to 'int' may change value [-Wconversion]
   22 |     for(int i=n-1;i>=0;i--) Ri.push_back(R[i]);
      |               ~^~

• Subtask 1: 0 / 10
• Subtask 2: 0 / 10
• Subtask 3: 0 / 15
• Subtask 4: 0 / 15
• Subtask 5: 0 / 20
• Subtask 6: 0 / 30