This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define f first
#define s second
const int N = 3e5 + 69;
const int M = 21;
int a[N], cnt[M], n, m;
int t[M];
pair<int, int> bst[1 << M];
signed main() {
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int tt = 1;
//cin >> tt;
while (tt--) {
cin >> n >> m;
for (int i = 1;i <= n;i++) {
for (int j = 0;j < m;j++) {
int x;
cin >> x;
if (x > 0) {
a[i] += (1 << j);
cnt[j]++;
}
}
}
for (int i = 0;i < (1 << m);i++)
bst[i] = {i, i};
for (int i = 0;i < (1 << m);i++) {
for (int j = 1;j <= n;j++) {
int k = __builtin_popcount(a[j] & i);
if (k <= __builtin_popcount(bst[i].f & i)) {
bst[i].s = bst[i].f;
bst[i].f = a[j];
}
else if (k <= __builtin_popcount(bst[i].s & i))
bst[i].s = a[j];
}
}
for (int i = 1;i <= n;i++) {
int b = 0, ans = 0, c = 0;
for (int j = 0;j < m;j++) {
t[j] = cnt[j];
if (a[i] & (1 << j))
t[j]--;
if (t[j] == n / 2)
b += (1 << j), c++;
else if (t[j] > n / 2)
ans++;
}
if (bst[b].f == a[i])
ans += c - (__builtin_popcount(bst[b].s & b));
else
ans += c - (__builtin_popcount(bst[b].f & b));
cout << ans << '\n';
}
}
return 0;
}
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