제출 #919855

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
919855		JakobZorz	서열 (APIO23_sequence)	C++17	63 / 100	2044 ms	44180 KiB

sequence

#include"sequence.h"
#include<vector>
#include<iostream>
using namespace std;

const int TREE_SIZE=1<<19;

int n;
vector<int>arr[500000];
int tree_lazy[2*TREE_SIZE];
int tree_min[2*TREE_SIZE];
int tree_max[2*TREE_SIZE];

void push_lazy(int node){
    if(tree_lazy[node]!=0){
        tree_min[node]+=tree_lazy[node];
        tree_max[node]+=tree_lazy[node];
        if(node<TREE_SIZE){
            tree_lazy[2*node]+=tree_lazy[node];
            tree_lazy[2*node+1]+=tree_lazy[node];
        }
        tree_lazy[node]=0;
    }
}

int get_min(int node,int rl,int rr,int l,int r){
    push_lazy(node);
    if(r<=rl||rr<=l)
        return 1e8;
    if(l<=rl&&rr<=r)
        return tree_min[node];
    int mid=(rl+rr)/2;
    return min(get_min(2*node,rl,mid,l,r),get_min(2*node+1,mid,rr,l,r));
}

int get_max(int node,int rl,int rr,int l,int r){
    push_lazy(node);
    if(r<=rl||rr<=l)
        return -1e8;
    if(l<=rl&&rr<=r)
        return tree_max[node];
    int mid=(rl+rr)/2;
    return max(get_max(2*node,rl,mid,l,r),get_max(2*node+1,mid,rr,l,r));
}

int get_min(int l,int r){
    return get_min(1,0,TREE_SIZE,l,r);
}

int get_max(int l,int r){
    return get_max(1,0,TREE_SIZE,l,r);
}

void add(int node,int rl,int rr,int l,int r,int v){
    push_lazy(node);
    if(r<=rl||rr<=l)
        return;
    if(l<=rl&&rr<=r){
        tree_lazy[node]+=v;
        push_lazy(node);
        return;
    }
    int mid=(rl+rr)/2;
    add(2*node,rl,mid,l,r,v);
    add(2*node+1,mid,rr,l,r,v);
    tree_min[node]=min(tree_min[2*node],tree_min[2*node+1]);
    tree_max[node]=max(tree_max[2*node],tree_max[2*node+1]);
}

void add(int l,int r,int v){
    add(1,0,TREE_SIZE,l,r,v);
}

int sequence(int N,vector<int>A){
    n=N;
    for(int i=0;i<n;i++)
        arr[A[i]-1].push_back(i);
    /*for(int i=0;i<=n;i++)
        tree[i]=-i;*/
    for(int i=0;i<=n;i++)
        add(i,i+1,-i);
    
    int res=1;
    for(int v=0;v<n;v++){
        for(int idx:arr[v])
            /*for(int i=idx+1;i<=n;i++)
                tree[i]++;*/
            add(idx+1,n+1,1);
        
        vector<int>mn1,mn2,mx1,mx2;
        for(int i:arr[v]){
            mn1.push_back(get_min(0,i+1));
            mn2.push_back(get_min(i,n+1));
            mx1.push_back(get_max(0,i+1));
            mx2.push_back(get_max(i,n+1));
        }
        
        for(int r=0;r<(int)arr[v].size();r++){
            int l1=0,l2=0;
            while(l1<r&&mx1[l1]-l1+1<mn2[r]-r)
                l1++;
            while(l2<r&&mx2[r]+r+1<mn1[l2]+l2)
                l2++;
            int l=max(l1,l2);
            res=max(res,r-l+1);
        }
        
        for(int idx:arr[v])
            /*for(int i=idx+1;i<=n;i++)
                tree[i]++;*/
            add(idx+1,n+1,1);
    }
    
    return res;
}

• Subtask 1: 11 / 11
• Subtask 2: 17 / 17
• Subtask 3: 0 / 7
• Subtask 4: 0 / 12
• Subtask 5: 13 / 13
• Subtask 6: 22 / 22
• Subtask 7: 0 / 18