Submission #918363

#	Time	Username	Problem	Language	Result	Execution time	Memory
918363		phamducminh	Bali Sculptures (APIO15_sculpture)	C++17	9 / 100	74 ms	2396 KiB

sculpture

//******************/
//*   I<3   C++    */
//*  I WANT ANY AC */
//* I LOVE PROGRAM!*/
//*IT'S long longERESTING*/
//* I LOVE PROGRAM!*/
//*  IN CONTESTS   */
//*   GET SCORE    */
//*    AC CODE     */
//*     LET'S      */
//*      GO        */
//*  Written by:   */
//*   Duc Minh     */






#include <bits/stdc++.h>
#include <iostream>
#include <cmath>
#include <vector>
#include <map>
#include <set>
#include <stack>
#include <algorithm>
#include <string>
#include <queue>
#include <cctype>
#include <cstring>
#include <iomanip>
#include <deque>
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/tree_policy.hpp>

using namespace std;
// using namespace __gnu_pbds;

#define  file(name)  freopen(name".inp", "r", stdin);\
                     freopen(name".out", "w", stdout);
#define ordered_set tree<ll, null_type,less_equal<ll>, rb_tree_tag,tree_order_statistics_node_update>
#define TIME        (1.0 * clock() / CLOCKS_PER_SEC)
#define all(a)      a.begin(),a.end()
#define endl        "\n"
#define all1(a)     a+1,a+n+1
#define unordered_map  map
#define Accepted 0      
// #define push_back   emplace_back
// #define gcd(a,b)    __gcd(a,b);
// #define lcm(a,b)    (a*b)/gcd(a,b);

const long long INF = (long long)1e18;
const long long MOD = (long long)1e9+7;
const long long MODD = 14062008; /// 998244353
const long long maxN = 2e5+9;
const long long LOG = 30;







///--------------------------------


void solve();

signed main(){

    ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);


    // file("tbrackets");







    long long t;


    // cin >> t;

    t=1;



    while (t--){




        solve();


    }





    cerr << "Time elapsed: " << TIME << "s.\n";
    cerr << "ducminh" << "\n";
    return Accepted;
}



///--------------------[PROBLEM SOLUTION]--------------------///



long long a[2009], dp[2009][2009], pre[2009];

long long ans=INF,n,L,R;


void sub1(){



    for (long long mask=0; mask<(1<<n); mask++){

        long long sum=0,g=0;
        for (long long i=0; i<n; i++){
            sum+=a[i];
            if ((mask>>i)&1){
                g|=sum;
                sum=0;
            }
        }

        g|=sum;

        long long bits=__builtin_popcount(mask) + ((mask & (1 << (n - 1))) == 0);

        if (L<=bits && bits<=R) ans=min(ans,g);
    }

    cout << ans;
    exit(0);
}


void sub2(){

    long long dp[59][29][509];

    memset(dp, false ,sizeof dp);

    dp[0][0][0] = true; 

    const int N=500;

    for (long long i=0; i<n; i++){

        for (long long k=0; k<=min(i,R-1); k++){

            for (long long j=0; j<=N; j++){

                if (!dp[i][k][j]) continue; 

                for (long long t=i+1; t<n; t++){

                    dp[t][k+1][j|(pre[t-1]-pre[i-1])] |= dp[i][k][j];
                }

            }
        }
    }

    long long ans = INF; 
    for (long long j = L ; j <= R ; j++) 
        for (long long t = 0; t <= N; t++){
            if (dp[n-1][j][t]) ans=min(ans,t);
        }


    cout << ans;


    exit(0);
}

void sub3(){

    for (long long i=0; i<=n+1; i++){
        for (long long j=0; j<=R+1; j++){
            dp[i][j]=INF;
        }
    }

    sort(a,a+n);

    pre[0]=a[0];
    for (int i=1; i<n; i++){
        pre[i]=pre[i-1]+a[i];
    }

    dp[0][0]=0;
    // dp[i][j][or]
    for (long long i=1; i<=n; i++){

        for (long long k=1; k<=R; k++){

            for (long long j=0; j<i; j++){

                long long sum=pre[i-1]-pre[j-1];

                if (j==0) sum=pre[i-1];

                // sum=0;
                // for (long long ii=j; ii<i; ii++){
                //     sum+=a[ii];
                // }

                // cout << sum << ' ' << j << ' ' << i << "\n";


                dp[i][k]=min(dp[i][k],dp[j][k-1]|sum);

            }
        }
    }

    for (long long i=L; i<=R; i++){
        ans=min(ans,dp[n][i]);

        // cout << dp[n][i] << "\n";
    }

    cout << ans;
    exit(0);
}

void solve(){



    cin >> n >> L >> R;


    for (long long i=0; i<n; i++){

        cin >> a[i]; if (i==0) pre[i]=a[i]; else pre[i]=pre[i-1]+a[i];


    }


    // cout << pre[2]-pre[0] << "\n";


    if (n<=20) sub1();
    else sub3();

    sub3();

}

• Subtask 1: 9 / 9
• Subtask 2: 0 / 16
• Subtask 3: 0 / 21
• Subtask 4: 0 / 25
• Subtask 5: 0 / 29