Submission #917728

#TimeUsernameProblemLanguageResultExecution timeMemory
917728tarcheFeast (NOI19_feast)C++17
4 / 100
612 ms24212 KiB
// @tarche // Feast // OJUZ // Singapore NOI 2019 // https://oj.uz/problem/view/NOI19_feast // 2024-01-28 #include <bits/stdc++.h> #define forn(i, n) for (tint i = 0; i < tint(n); i++) #define forsn(i, s, n) for (tint i = s; i < tint(n); i++) #define dforn(i, n) for (tint i = tint(n) - 1; i >= 0; i--) #define dforsn(i, s, n) for (tint i = tint(n) - 1; i >= s; i--) #define sz(x) tint(x.size()) #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(), x.rend() #define DBG(x) cerr << #x << " = " << x << endl using namespace std; #ifndef SMALL_TINT using tint = long long; #else using tint = int; #endif using vi = vector<tint>; using pii = pair<tint, tint>; inline void fastIO() { ios_base::sync_with_stdio(false); cin.tie(NULL); } inline string YN(bool x, string y = "YES", string n = "NO") { return (x ? y : n); } template <typename T> inline void chmax(T &lhs, T rhs) { lhs = max(lhs, rhs); } template <typename T> inline void chmin(T &lhs, T rhs) { lhs = min(lhs, rhs); } template <typename T, typename U> ostream &operator<<(ostream &os, const pair<T, U> &p) { os << "(" << p.first << ", " << p.second << ")"; return os; } template <typename T> ostream &operator<<(ostream &os, const vector<T> &v) { os << "["; forn(i, sz(v)) { if (i > 0) os << ", "; os << v[i]; } os << "]"; return os; } template <typename T, size_t N> ostream &operator<<(ostream &os, const array<T, N> &v) { os << "["; forn(i, N) { if (i > 0) os << ", "; os << v[i]; } os << "]"; return os; } const tint INF = 1e18; pii solve(const vi &nums, tint lambda) { tint n = sz(nums); vector<vector<pii>> dp(n + 1, vector<pii>(2, {-INF, 0})); dp[0][0].first = 0; forn(i, n) { chmax(dp[i + 1][0], dp[i][0]); chmax(dp[i + 1][0], dp[i][1]); chmax(dp[i + 1][1], {dp[i][1].first + nums[i], dp[i][1].second}); if (dp[i + 1][0].first > -INF) { chmax(dp[i + 1][1], {dp[i][0].first + nums[i] - lambda, dp[i][0].second - 1}); } } pii ans = max(dp[n][0], dp[n][1]); ans.second = -ans.second; ans.first += lambda * ans.second; return ans; } int main() { fastIO(); tint n, k; cin >> n >> k; vi nums(n); forn(i, n) cin >> nums[i]; tint lo = 0, hi = *max_element(all(nums)); while (hi - lo > 1) { tint lambda = (hi + lo) / 2; if (solve(nums, lambda).second <= k) { hi = lambda; } else { lo = lambda; } } cout << solve(nums, hi).first << '\n'; }
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