oj.uz

Submission #917345

# Submission time Handle Problem Language Result Execution time Memory
917345 2024-01-27T22:22:25 Z rainboy None (KOI17_cut) C++17
0 / 100
 2 ms 8840 KB 
#include <stdio.h>

#define N	1000000

unsigned int X = 12345;

int rand_() {
	return (X *= 3) >> 1;
}

int ll[N], rr[N], hh[N];

void sort(int *hh, int l, int r) {
	while (l < r) {
		int i = l, j = l, k = r, h = hh[l + rand_() % (r - l)], tmp;

		while (j < k) {
			int c = ll[hh[j]] != ll[h] ? ll[hh[j]] - ll[h] : rr[h] - rr[hh[j]];

			if (c == 0)
				j++;
			else if (c < 0) {
				tmp = hh[i], hh[i] = hh[j], hh[j] = tmp;
				i++, j++;
			} else {
				k--;
				tmp = hh[j], hh[j] = hh[k], hh[k] = tmp;
			}
		}
		sort(hh, l, i);
		l = k;
	}
}

int main() {
	static int xx[N], yy[N];
	int n, m, h, h_, h1, i, j, tmp, x, y;

	scanf("%d", &n);
	for (i = 0; i < n; i++)
		scanf("%d%d", &xx[i], &yy[i]);
	for (i = -1, j = 0; j < n; j++)
		if ((yy[j] < 0) != (yy[(j + 1) % n] < 0))
			i = j;
	m = 0;
	for (i = -1, j = 0; j < n; j++)
		if ((yy[j] < 0) != (yy[(j + 1) % n] < 0)) {
			if (yy[j] > 0) {
				ll[m] = xx[i], rr[m] = xx[j];
				if (ll[m] > rr[m])
					tmp = ll[m], ll[m] = rr[m], rr[m] = tmp;
				m++;
			}
			i = j;
		}
	for (h = 0; h < m; h++)
		hh[h] = h;
	sort(hh, 0, m);
	x = 0;
	for (h = 0, h1 = -1; h < m; h++) {
		h_ = hh[h];
		if (h1 == -1 || rr[h1] < rr[h_])
			h1 = h_, x++;
	}
	y = 0;
	for (h = m - 1, h1 = -1; h >= 0; h--) {
		h_ = hh[h];
		if (h1 == -1 || rr[h1] > rr[h_])
			h1 = h_, y++;
	}
	printf("%d %d\n", x, y);
	return 0;
}

Compilation message

cut.cpp: In function 'int main()':
cut.cpp:39:7: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   39 |  scanf("%d", &n);
      |  ~~~~~^~~~~~~~~~
cut.cpp:41:8: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   41 |   scanf("%d%d", &xx[i], &yy[i]);
      |   ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
0 / 11.0

# Verdict Execution time Memory Grader output
1 Correct 1 ms 8540 KB Output is correct
2 Correct 1 ms 8540 KB Output is correct
3 Incorrect 2 ms 8840 KB Output isn't correct
4 Halted 0 ms 0 KB -

Subtask #2
0 / 24.0

# Verdict Execution time Memory Grader output
1 Correct 1 ms 8540 KB Output is correct
2 Correct 1 ms 8540 KB Output is correct
3 Incorrect 2 ms 8840 KB Output isn't correct
4 Halted 0 ms 0 KB -

Subtask #3
0 / 65.0

# Verdict Execution time Memory Grader output
1 Correct 1 ms 8540 KB Output is correct
2 Correct 1 ms 8540 KB Output is correct
3 Incorrect 2 ms 8840 KB Output isn't correct
4 Halted 0 ms 0 KB -