제출 #916966

#제출 시각아이디문제언어결과실행 시간메모리
916966NK_The short shank; Redemption (BOI21_prison)C++17
15 / 100
157 ms44856 KiB
// Success consists of going from failure to failure without loss of enthusiasm #include <bits/stdc++.h> using namespace std; #define nl '\n' #define pb push_back #define sz(x) int(x.size()) #define mp make_pair template<class T> using V = vector<T>; template<class T> using pq = priority_queue<T, vector<T>, less<T>>; using vi = V<int>; using pi = pair<int, int>; int main() { cin.tie(0)->sync_with_stdio(0); int N, D, T; cin >> N >> D >> T; vi A(N); for(auto& x : A) cin >> x; V<vi> E(N); for(int i = 0; i < N; i++) { A[i] = max(T + 1 - A[i], 0); // cout << i << " => " << A[i] << endl; int r = i + A[i]; if (r < N) E[r].pb(i); } // cout << endl; set<int> R; int ans = 0; vi LX, RX; for(int i = 0; i < N; i++) { R.insert(i); for(auto& x : E[i]) R.erase(x); if (A[i] == 0) { if (sz(R)) { LX.pb(*rbegin(R)); RX.pb(max(LX.back(), (sz(RX) ? RX.back() : -1))); // cout << i << " => " << LX.back() << " " << RX.back() << endl; } else { // cout << i << " => {}" << endl; ans++; } } // else { // // cout << i << " " << A[i] << endl; // } } int M = sz(LX); vi P, C, I, stk = {-1}; // parent, count for(int i = 0; i < M; i++) { if (i && mp(LX[i], RX[i]) == mp(LX[i-1], RX[i-1])) C.back()++; else { int u = sz(C); while(stk.back() != -1 && LX[I[stk.back()]] > LX[i]) stk.pop_back(); if (i && RX[i - 1] == RX[i]) P.back() = u; if (stk.back() != -1 && LX[I[stk.back()]] == LX[i]) P[stk.back()] = u; C.pb(1); I.pb(i); P.pb(-1); stk.pb(u); } } int K = sz(P); V<vi> chd(K); for(int i = 0; i < K; i++) { if (P[i] != -1) { chd[P[i]].pb(i); // cout << i << " <--> " << P[i] << endl; } } vi mx(K), vis(K), taken(K, 0), rem(K, 0), S(K, 0); function<void(int)> dfs = [&](int u) { S[u] += C[u]; mx[u] = u; vis[u] = 1; for(auto& v : chd[u]) { S[v] += S[u]; dfs(v); if (S[mx[u]] < S[mx[v]]) mx[u] = mx[v]; } }; pq<pi> q; for(int i = 0; i < K; i++) if (P[i] == -1) { dfs(i); q.push(mp(S[mx[i]], mx[i])); // cout << i << " --> " << mx[i] << endl; } while(D && sz(q)) { auto [amt, u] = q.top(); q.pop(); D--; ans += max(amt, 0); // cout << "T: " << amt << " " << u << endl; while(u != -1) { taken[u] = 1; for(auto& v : chd[u]) if (!taken[v]) { P[v] = -1; rem[v] += rem[u] + S[u]; // cout << "ROOT: " << v << " => " << mx[v] << " " << S[mx[v]] - rem[v] << endl; q.push(mp(S[mx[v]] - rem[v], mx[v])); } u = P[u]; } } // cout << ans << endl; cout << N - ans << nl; exit(0-0); }
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