Submission #915144

#	Time	Username	Problem	Language	Result	Execution time	Memory
915144		mychecksedad	Collecting Stamps 3 (JOI20_ho_t3)	C++17	5 / 100	118 ms	185236 KiB

ho_t3

/* Author : Mychecksdead  */
#include<bits/stdc++.h>
using namespace std;
#define ll long long int
#define MOD (1000000000+7)
#define MOD1 (998244353)
#define pb push_back
#define all(x) x.begin(), x.end()
#define en cout << '\n'
const int N = 200+100, M = 1e5+10, K = 52, MX = 30;


int n;
ll L, dp[N][N][N][2];
array<ll, 2> a[N];
void solve(){
  cin >> n >> L;
  for(int i = 1; i <= n; ++i) cin >> a[i][0];
  for(int i = 1; i <= n; ++i) cin >> a[i][1];

  sort(a+1, a+1+n);

  for(int i = 0; i <= n; ++i) for(int j = 0; j <= n; ++j) for(int l = 0; l <= n; ++l) dp[i][j][l][0] = dp[i][j][l][1] = (ll)1e18;

  a[0] = {0, 0};
  a[n + 1] = {L, 0};
  dp[0][0][0][0] = dp[0][0][0][1] = 0;

  for(int k = 0; k <= n; ++k){
    for(int i = 0; i <= n; ++i){
      for(int j = 0; j <= n; ++j){
        if(i+j < k) continue;
        if(i==0&&j==0) continue;

        if(i == 0){
          dp[i][j][k][1] = min(dp[i][j - 1][k][0] + abs(a[i][0] + L - a[n - j + 1][0]), dp[i][j - 1][k][1] + abs(a[n - j + 1][0] - a[n - j + 2][0]));
          if(k > 0){
            if(min(dp[i][j - 1][k - 1][0] + abs(a[i][0] + L - a[n - j + 1][0]), dp[i][j - 1][k - 1][1] + abs(a[n - j + 1][0]- a[n - j + 2][0])) <= a[n - j + 1][1]){
              dp[i][j][k][1] = min(
                dp[i][j][k][1], 
                min(
                  dp[i][j - 1][k - 1][0] + abs(a[i][0] + L - a[n - j + 1][0]), 
                  dp[i][j - 1][k - 1][1] + abs(a[n - j + 1][0] - a[n - j + 2][0])
                )
              );
            }
          }
        }else if(j == 0){
          dp[i][j][k][0] = min(dp[i - 1][j][k][0] + abs(a[i][0] - a[i - 1][0]), dp[i - 1][j][k][1] + abs(a[i][0] + L - a[n - j + 1][0]));
          if(k > 0){
            if(min(dp[i - 1][j][k - 1][0] + abs(a[i][0] - a[i - 1][0]), dp[i - 1][j][k - 1][1] + abs(a[i][0] + L - a[n - j + 1][0])) <= a[i][1]){
              dp[i][j][k][0] = min(
                dp[i][j][k][1], 
                min(
                  dp[i - 1][j][k - 1][0] + abs(a[i][0] - a[i - 1][0]), 
                  dp[i - 1][j][k - 1][1] + abs(a[i][0] + L - a[n - j + 1][0])
                )
              );
            }
          }
        }else{
          dp[i][j][k][0] = min(dp[i - 1][j][k][0] + abs(a[i][0] - a[i - 1][0]), dp[i - 1][j][k][1] + abs(a[i][0] + L - a[n - j + 1][0]));
          dp[i][j][k][1] = min(dp[i][j - 1][k][0] + abs(a[i][0] + L - a[n - j + 1][0]), dp[i][j - 1][k][1] + abs(a[n - j + 1][0] - a[n - j + 2][0]));
          if(k > 0){
            if(min(dp[i - 1][j][k - 1][0] + abs(a[i][0] - a[i - 1][0]), dp[i - 1][j][k - 1][1] + abs(a[i][0] + L - a[n - j + 1][0])) <= a[i][1]){
              dp[i][j][k][0] = min(dp[i][j][k][1], min(dp[i - 1][j][k - 1][0] + abs(a[i][0] - a[i - 1][0]), dp[i - 1][j][k - 1][1] + abs(a[i][0] + L - a[n - j + 1][0])));
            }
            if(min(dp[i][j - 1][k - 1][0] + abs(a[i][0] + L - a[n - j + 1][0]), dp[i][j - 1][k - 1][1] + abs(a[n - j + 1][0]- a[n - j + 2][0])) <= a[n - j + 1][1]){
              dp[i][j][k][1] = min(dp[i][j][k][1], min(dp[i][j - 1][k - 1][0] + abs(a[i][0] + L - a[n - j + 1][0]), dp[i][j - 1][k - 1][1] + abs(a[n - j + 1][0] - a[n - j + 2][0])));
            }
          }
        }
      }
    }
  }


  int ans = 0;
  for(int i = 0; i <= n; ++i){
    for(int k = 0; k <= n; ++k){
      if(dp[i][n-i][k][0] < 1e18 || dp[i][n-i][k][1] < 1e18) ans=max(ans,k);
    }
  }
  cout << ans;
}



int main(){
  cin.tie(0); ios::sync_with_stdio(0);
  int tt = 1, aa;
  // freopen("in.txt", "r", stdin);
  // freopen("out.txt", "w", stdout);
  // cin >> tt;
  while(tt--){
    solve();
    // en;
    en;
  }
  cerr<<"time taken : "<<(float)clock()/CLOCKS_PER_SEC<<" seconds\n";
  return 0;
} 

Compilation message (stderr)

ho_t3.cpp: In function 'int main()':
ho_t3.cpp:91:15: warning: unused variable 'aa' [-Wunused-variable]
   91 |   int tt = 1, aa;
      |               ^~

• Subtask 1: 5 / 5
• Subtask 2: 0 / 10
• Subtask 3: 0 / 10
• Subtask 4: 0 / 75