Submission #915003

#	Time	Username	Problem	Language	Result	Execution time	Memory
915003		Tuanlinh123	Sightseeing in Kyoto (JOI22_kyoto)	C++17	0 / 100	2 ms	2652 KiB

kyoto

#include<bits/stdc++.h>
#define ll long long
#define pll pair<ll, ll>
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define ld long double
using namespace std;

ll a[100005], b[100005], toa[100005], tob[100005];
struct num
{
    ll t, i, j;
    num(){}
    num(ll i, ll t): i(i), t(t)
    {
        if (t==0) j=toa[i];
        else j=tob[i];
    }
    bool operator < (const num &o) const
    {
        ll v=t==0?a[i]-a[j]:b[i]-b[j], ov=o.t==0?a[o.i]-a[o.j]:b[o.i]-b[o.j];
        return v*(o.j-o.i)<ov*(j-i);
    }
};
set <num> S;

int main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0); cout.tie(0);
    ll n, m, cn, cm, ans=0; cin >> n >> m; cn=n, cm=m;
    for (ll i=1; i<=n; i++) cin >> a[i];
    for (ll i=1; i<=m; i++) cin >> b[i];
    for (ll i=1; i<n; i++) toa[i]=i+1, S.insert(num(i, 0));
    for (ll i=1; i<m; i++) tob[i]=i+1, S.insert(num(i, 1));
    while (S.size())
    {
        num Min=*S.begin(); S.erase(S.begin());
        ll t=Min.t, i=Min.i, j=Min.j;
        if (t==0)
        {
            if (j==cn) ans+=b[cm]*(j-i), cn=i;
            else
            {
                S.erase(num(j, 0)), toa[i]=toa[j];
                S.insert(num(i, 0));
            }
        }
        else
        {
            if (j==cm) ans+=a[cn]*(j-i), cm=i;
            else
            {
                S.erase(num(j, 1)), tob[i]=tob[j];
                S.insert(num(i, 1));
            }
        }
    }
    cout << ans << "\n";
}

Compilation message (stderr)

kyoto.cpp: In constructor 'num::num(long long int, long long int)':
kyoto.cpp:14:11: warning: 'num::i' will be initialized after [-Wreorder]
   14 |     ll t, i, j;
      |           ^
kyoto.cpp:14:8: warning:   'long long int num::t' [-Wreorder]
   14 |     ll t, i, j;
      |        ^
kyoto.cpp:16:5: warning:   when initialized here [-Wreorder]
   16 |     num(ll i, ll t): i(i), t(t)
      |     ^~~

• Subtask 1: 0 / 10
• Subtask 2: 0 / 30
• Subtask 3: 0 / 60