이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
using namespace std;
#define optimizar_io ios_base::sync_with_stdio(0);cin.tie(0);
typedef pair<int, int> pii;
typedef pair<long long, int> pli;
typedef pair<pii, int> piii;
typedef pair<long long, long long> pll;
typedef pair<pll, long long> plll;
typedef vector<int> vi;
typedef vector<bool> vb;
typedef vector<vector<int>> vvi;
typedef vector<long long> vl;
typedef vector<vector<long long>> vvl;
typedef vector<pii> vpii;
typedef vector<piii> vpiii;
typedef vector<pli> vpli;
typedef vector<pll> vpll;
typedef vector<plll> vplll;
typedef vector<vector<plll>> vvplll;
typedef vector<vector<pll>> vvpll;
typedef vector<vector<piii>> vvpiii;
typedef vector<vector<pii>> vvpii;
typedef vector<vector<pli>> vvpli;
using namespace __gnu_pbds;
template <typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#define fi first
#define se second
#define pb push_back
#define mp make_pair
#define data data_
#define endl "\n"
#define isOn(S, j) (S & (1ll << (j)))
#define setBit(S, j) (S |= (1ll << (j)))
#define clearBit(S, j) (S &= ~(1ll << (j)))
#define toggleBit(S, j) (S ^= (1ll << (j)))
#define bzero(b,len) (memset((b), '\0', (len)), (void) 0)
#define all(x) x.begin(),x.end()
#define sz(x) x.size()
int main(){
optimizar_io;
int n, m;
cin >> n >> m;
int a[n+1];
int total = 0;
for (int i = 1; i <= n; i++){
cin >> a[i];
total += a[i];
}
int who[total+1];
int idx = 1;
who[0] = 0;
for (int i = 1; i <= n; i++){
for (int j = 0; j < a[i]; j++){
who[idx++] = i;
}
}
int b[m];
for (int i = 0; i < m; i++){
cin >> b[i];
}
bool dp[1<<m]; //Is it valid to use the set to pay the first people
bzero(dp, sizeof(dp));
dp[0] = true;
bool found = false;
for (int i = 1; i < (1<<m); i++){
dp[i] = false;
int amount = 0;
for (int j = 0; j < m; j++){
if (isOn(i, j)){
amount += b[j];
}
}
if (amount > total) continue;
for (int j = 0; j < m; j++){
if (isOn(i, j)){
int amount2 = amount - b[j];
int bm = i ^ (1<<j);
if ((dp[bm]) && ((who[amount] == who[amount2]) || ((who[amount2] != who[amount2+1]) && (who[amount] == who[amount2+1])))){
dp[i] = true;
if (amount == total){
found = true;
}
}
}
}
}
if (found){
cout << "YES" << endl;
} else {
cout << "NO" << endl;
}
return 0;
}
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