답안 #910230

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
910230 2024-01-18T02:29:32 Z gaga999 Teams (CEOI11_tea) C++17
70 / 100
2500 ms 38704 KB
#include <cstdio>
#include <stdio.h>
#include <iostream>
#include <math.h>
#include <vector>
#include <queue>
#include <stack>
#include <deque>
#include <algorithm>
#include <utility>
#include <set>
#include <map>
#include <stdlib.h>
#include <cstring>
#include <string.h>
#include <string>
#include <sstream>
#include <assert.h>
#include <climits>
#include <sstream>
#include <numeric>
#include <time.h>
#include <limits.h>
#include <list>
#include <bitset>
#include <unordered_map>
#include <unordered_set>
#include <random>
#include <iomanip>
#include <complex>
#include <chrono>
#include <fstream>
#include <functional>
#include <unistd.h>
// #pragma GCC optimize("Ofast,no-stack-protector")
// #pragma GCC optimize("O3,unroll-loops")
// #pragma GCC target("avx,avx2,bmi,bmi2,lzcnt,popcnt")
#define lowbit(x) ((x) & -(x))
#define ml(a, b) ((1ll * (a) * (b)) % M)
#define tml(a, b) (a) = ((1ll * (a) * (b)) % M)
#define ad(a, b) ((0ll + (a) + (b)) % M)
#define tad(a, b) (a) = ((0ll + (a) + (b)) % M)
#define mi(a, b) ((0ll + M + (a) - (b)) % M)
#define tmi(a, b) (a) = ((0ll + M + (a) - (b)) % M)
#define tmin(a, b) (a) = min((a), (b))
#define tmax(a, b) (a) = max((a), (b))
#define iter(a) (a).begin(), (a).end()
#define riter(a) (a).rbegin(), (a).rend()
#define init(a, b) memset((a), (b), sizeof(a))
#define cpy(a, b) memcpy((a), (b), sizeof(a))
#define uni(a) a.resize(unique(iter(a)) - a.begin())
#define pb emplace_back
#define mpr make_pair
#define ls(i) ((i) << 1)
#define rs(i) ((i) << 1 | 1)
#define INF 0x3f3f3f3f
#define NIF 0xc0c0c0c0
#define eps 1e-9
#define F first
#define S second
#define AC cin.tie(0)->sync_with_stdio(0)
using namespace std;
typedef long long llt;
typedef pair<int, int> pii;
typedef pair<double, double> pdd;
typedef pair<llt, llt> pll;
typedef complex<double> cd;
// const int M = 998244353;

// random_device rm;
// mt19937 rg(rm());
// default_random_engine rg(rm());
// uniform_int_distribution<int> rd(INT_MIN, INT_MAX);
// uniform_real_distribution<double> rd(0, M_PI);

void db() { cerr << "\n"; }
template <class T, class... U>
void db(T a, U... b) { cerr << a << " ", db(b...); }

inline char gc()
{
    const static int SZ = 1 << 16;
    static char buf[SZ], *p1, *p2;
    if (p1 == p2 && (p2 = buf + fread(p1 = buf, 1, SZ, stdin), p1 == p2))
        return -1;
    return *p1++;
}
void rd() {}
template <typename T, typename... U>
void rd(T &x, U &...y)
{
    x = 0;
    bool f = 0;
    char c = gc();
    while (!isdigit(c))
        f ^= !(c ^ 45), c = gc();
    while (isdigit(c))
        x = (x << 1) + (x << 3) + (c ^ 48), c = gc();
    f && (x = -x), rd(y...);
}

template <typename T>
void prt(T x)
{
    if (x < 0)
        putchar('-'), x = -x;
    if (x > 9)
        prt(x / 10);
    putchar((x % 10) ^ 48);
}

const int N = 1e6 + 6;
int ar[N], br[N], dp[N], fr[N];
pii tr[N << 1];

signed main()
{
    int n;
    rd(n);
    for (int i = 1; i <= n; i++)
        rd(ar[i]);
    iota(br + 1, br + n + 1, 1);
    sort(br + 1, br + n + 1, [&](int a, int b)
         { return ar[a] < ar[b]; });
    auto pul = [&](int p) -> void
    {
        tr[p] = max(tr[ls(p)], tr[rs(p)]);
    };
    auto qy = [&](int l, int r) -> pii
    {
        pii res(-INF, -INF);
        for (l += n + 1, r += n + 1; l <= r; l >>= 1, r >>= 1)
        {
            if (l & 1)
                res = max(res, tr[l++]);
            if (~r & 1)
                res = max(res, tr[r--]);
        }
        return res;
    };
#define f(i) ar[br[i]]
    auto slv = [&](int lm) -> int
    {
        for (int i = 0; i <= n; i++)
            tr[i + n + 1] = mpr(-i, i);
        for (int i = n; i > 0; i--)
            pul(i);
        for (int i = 1; i <= n; i++)
        {
            if (i - f(i) < 0)
                continue;
            tie(dp[i], fr[i]) = qy(max(0, i - lm), i - f(i));
            tr[i + n + 1].F = ++dp[i];
            for (int p = (i + n + 1) >> 1; p; p >>= 1)
                pul(p);
        }
        return dp[n];
    };
    int ans = slv(INF);
    prt(ans), putchar('\n');
    int l = ar[br[n]], r = n;
    while (l < r)
    {
        int m = (l + r) >> 1;
        if (slv(m) < ans)
            l = m + 1;
        else
            r = m;
    }
    slv(l);
    for (int i = n; i; i = fr[i])
    {
        prt(i - fr[i]);
        for (int j = i; j > fr[i]; j--)
            putchar(' '), prt(br[j]);
        putchar('\n');
    }
}
# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 8540 KB Output is correct
2 Correct 2 ms 8540 KB Output is correct
3 Correct 1 ms 8540 KB Output is correct
4 Correct 1 ms 8540 KB Output is correct
5 Correct 2 ms 8540 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 8536 KB Output is correct
2 Correct 2 ms 8536 KB Output is correct
3 Correct 2 ms 8540 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 8540 KB Output is correct
2 Correct 2 ms 8540 KB Output is correct
3 Correct 2 ms 8540 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 12 ms 8540 KB Output is correct
2 Correct 13 ms 8540 KB Output is correct
3 Correct 13 ms 8540 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 11 ms 8536 KB Output is correct
2 Correct 11 ms 8536 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 181 ms 11176 KB Output is correct
2 Correct 235 ms 11176 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 272 ms 11432 KB Output is correct
2 Correct 214 ms 11176 KB Output is correct
3 Correct 283 ms 11448 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Execution timed out 2559 ms 29388 KB Time limit exceeded
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Execution timed out 2526 ms 31784 KB Time limit exceeded
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 2155 ms 38704 KB Output is correct
2 Correct 65 ms 34384 KB Output is correct
3 Execution timed out 2543 ms 31788 KB Time limit exceeded
4 Halted 0 ms 0 KB -