Submission #910125

#	Time	Username	Problem	Language	Result	Execution time	Memory
910125		Alphanumeric	Fountain (eJOI20_fountain)	C++14	100 / 100	321 ms	37780 KiB

fountain

/*
⣿⣿⡿⣫⣾⠏⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⢀⣀⣀⣀⣀⠄⠄⠄⠄⠄⠄
⣿⡇⠱⠉⠁⠄⠄⠄⠄⠄⠄⢀⣀⣤⣶⣶⣿⣿⣿⣿⣿⣿⣿⣦⠄⠄⠄⠄⠄
⣿⡇⠄⠄⠄⠄⠄⢀⣠⣛⡩⣩⣭⡹⣿⣿⣿⣿⠞⣛⣛⣛⡲⣿⡇⠄⠄⠄⠄
⣿⡇⠄⠄⠄⡾⣡⣾⣿⣷⣹⣿⣿⡿⣪⡻⠟⣱⣿⣿⣿⣿⣿⣷⡹⠄⠄⠄⠄
⣿⡇⠄⠄⣼⡇⣿⣻⣿⠟⡛⢿⣿⣾⣿⡇⢰⣍⢻⡿⠛⢿⣿⡭⣿⣷⠄⠄⠄
⣿⣧⣄⡀⣿⡇⣮⣽⣿⣮⣉⣾⣿⣿⣿⣇⡸⣿⣿⣆⠛⣰⣿⣾⡿⣿⠄⠄⠄
⣿⣇⡼⣄⣿⣿⡄⠙⢿⣏⣿⣿⡮⠁⣉⣾⣷⡈⠃⢿⣿⣬⡭⠝⣀⣿⠄⠄⠐
⡆⡇⣹⣿⣿⣿⣿⡿⠓⠛⣉⣉⣉⣉⣙⣛⠓⠾⣟⢿⣿⣿⣿⣿⣿⣿⣿⠇⠄⠙
⠁⡇⣞⣿⡿⠋⠁⠄⠄⠈⠉⠙⠛⠛⠻⠿⠿⠿⣶⣌⠻⣿⣿⣿⣿⣿⢗⢴⣆⢣
⠸⣇⡻⠈⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⠈⢻⣷⡌⢿⣿⣿⣿⢸⠼⣣⣾
⣦⡀⠄⠄⠄⠄⠄⠄⠄⠄⠄⢀⠄⠄⠄⠄⠄⠄⠄⠄⠙⠛⠈⣿⡫⡼⢠⣾⣿⣿
⣿⣇⠄⣀⣠⡀⠄⠄⠴⠾⠿⠿⠶⠶⣦⣤⡀⠄⠄⠄⠄⠄⠄⢨⠯⢁⣿⣿⣿⣿
⣿⣿⣦⢒⠤⣅⡶⣶⣶⣾⣿⣿⣿⣷⣶⣮⣍⠢⠄⠄⠄⠄⠄⠐⢠⣾⣿⣿⣿⣿
⣿⣿⣿⣧⡐⠫⣉⡿⣬⡞⢿⣿⢯⠽⣶⡽⢟⣛⢖⣨⣛⠛⢃⣴⣿⣿⣿⣿⣿⣿
*/

// beichen is a classic problem in china
// map<pair<int,pair<int,int>>,priority_queue<pair<int, pair<int,int>>, vector<pair<int, pair<int,int>>>, greater<pair<int, pair<int,int>>>>> m;
// ^^ useless ds for good luck

#include <bits/stdc++.h>

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

#pragma GCC optimize("O3,unroll-loops")
// #pragma GCC target("avx2,bmi,bmi2,lzworks,popworks")

using namespace std;
#define int long long

#define inp(arr) \
  for (auto &it : arr) cin >> it;
#define outp(arr) \
  for (auto it : arr) cout << it << " ";
#define inppair(arr) \
  for (pair<int, int> & it : arr) cin >> it.first >> it.second;
#define outppair(arr) \
  for (pair<int, int> it : arr) cout << it.first << " " << it.second << "\n";
#define for0(n) for (int i = 0; i < n; ++i)
#define for0j(n) for (int j = 0; j < n; ++j)
#define for0k(n) for (int k = 0; k < n; ++k)
#define for1(n) for (int i = 1; i <= n; ++i)
#define for1j(n) for (int j = 1; j <= n; ++j)
#define for1k(n) for (int k = 1; k <= n; ++k)
#define for1b(n) for (int i = n; i > 0; --i)
#define for1bj(n) for (int j = n; j > 0; --j)
#define for0b(n) for (int i = n - 1; i >= 0; --i)
#define for0bj(n) for (int j = n - 1; j >= 0; --j)
#define forself(start, end) for (int i = start; i < end; ++i)
#define vecall(v) v.begin(), v.end()
#define srt(arr) sort(arr, arr + (sizeof(arr) / sizeof(arr[0])))
#define srtvc(arr) sort(arr.begin(), arr.end())
#define bcsrt(arr) sort(arr, arr + (sizeof(arr) / sizeof(arr[0])), greater<int>())
#define bcsrtvc(arr) sort(arr.begin(), arr.end(), greater<int>())
#define pub push_back
#define puf push_front
#define pob pop_back
#define pof pop_front
#define pq priority_queue
#define pii pair<int, int>
#define bkpqi priority_queue<int, vector<int>, greater<int>>
#define bkpqpii priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>>
#define setzero(arr) memset(arr, 0, sizeof(arr));
#define setone(arr) memset(arr, 1, sizeof(arr));
#define setneg(arr) memset(arr, -1, sizeof(arr));
#define mod1 998244353
#define mod2 1000000007

using namespace __gnu_pbds;
#define ordered_set tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update>
#define ordered_multiset tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update>

int n, q;
int mem[100005][20];
int pre[100005][20];

int32_t main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  cin >> n >> q;
  int a, b;
  stack<pii> st;
  for0(n) {
    cin >> a >> b;
    pre[i+1][0] = b;
    while (st.size() && st.top().first < a) {
      mem[st.top().second][0] = i + 1;
      st.pop();
    }
    st.push({a, i + 1});
  }
  while (st.size()) {
    mem[st.top().second][0] = 0;
    st.pop();
  }
  mem[0][0] = 0;
  pre[0][0] = 0;
  for1j(19) {
    for0(n + 1) {
      mem[i][j] = mem[mem[i][j - 1]][j - 1];
      pre[i][j] = pre[i][j - 1] + pre[mem[i][j - 1]][j - 1];
    }
  }
  while(q--){
    cin>>a>>b;
    for0b(20){
      if(pre[a][i]<b){
        b-=pre[a][i];
        a=mem[a][i];
      }
    }
    cout<<a<<"\n";
  }
}

• Subtask 1: 30 / 30
• Subtask 2: 30 / 30
• Subtask 3: 40 / 40