제출 #90896

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
90896		inom	은행 (IZhO14_bank)	C++14	25 / 100	1081 ms	716 KiB

bank

#include<bits/stdc++.h>
#include<ext/pb_ds/tree_policy.hpp>
#include<ext/pb_ds/assoc_container.hpp>
 
#define fi first
#define se second
#define new new228
#define pb push_back
#define rank rank228
#define int long long
#define sz(c) (int)(c).size()
#define all(c) (c).begin(), (c).end()
#define rall(c) (c).rbegin(), (c).rend()
 
using namespace std;
using namespace __gnu_pbds;
 
#pragma GCC optimize("Ofast")
#pragma GCC optimize("no-stack-protector")
#pragma GCC optimize("unroll-loops")
#pragma GCC target("sse,sse2,sse3,ssse3,popcnt,abm,mmx,tune=native")
#pragma GCC optimize("fast-math")
#pragma warning(disable : 4996)
 
typedef tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set; // st.oreder_of_key();
 
const int N = 100100;
const int INF = 1e15;
const int MAXN = 4 * N;
const int MOD = 998244353;
 
int TN = 1;
 
int n, m, x;
int a[N], b[N];
 
void rec(int cur, int pos) {
    if (cur == x) {
        printf("YES\n"); exit(false);
    }
    if (cur > x) {
        return;
    }
    if (pos > m) {
        return;
    }
    rec(cur + b[pos], pos + 1);
    rec(cur, pos + 1);
}
 
void subtask1() {
    cin >> x;
    for (int i = 1; i <= m; i++) {
        cin >> b[i];
    }
    rec(0, 1);
    printf("NO\n");
    exit(false);
}

void get() {
    int sum = 0, j = 1;
    for (int i = 1; i <= m; i++) {
        sum += b[i];
        if (sum == a[j]) {
            j++; sum = 0;
            if (j == n + 1) {
                cout << "YES\n"; exit(false);
            }
        }
        else if (sum > a[j]) {
            return;
        }
    }
    return;
}

void subtask2() {
    for (int i = 1; i <= n; i++) {
        cin >> a[i];
    }
    for (int i = 1; i <= m; i++) {
        cin >> b[i];
    }
    sort(b + 1, b + 1 + m);
    get();
    while (next_permutation(b + 1, b + 1 + m)) {
        get();
    }
    cout << "NO\n"; exit(false);
}

signed main() {
    // in; out;  // cin >> TN;
    cin >> n >> m;
    /*if (n == 1) {
        subtask1();
    }*/
    subtask2();
    return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

bank.cpp:23:0: warning: ignoring #pragma warning  [-Wunknown-pragmas]
 #pragma warning(disable : 4996)

• Subtask 1: 0 / 19
• Subtask 2: 25 / 25
• Subtask 3: 0 / 27
• Subtask 4: 0 / 29