Submission #908573

#TimeUsernameProblemLanguageResultExecution timeMemory
908573GrindMachineGift (IZhO18_nicegift)C++17
30 / 100
2111 ms389304 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; void solve(int test_case) { ll n,k; cin >> n >> k; vector<ll> a(n+5); rep1(i,n) cin >> a[i]; ll sum = 0; rep1(i,n) sum += a[i]; if(sum%k){ cout << -1 << endl; return; } ll mx = *max_element(all(a)); if(mx > sum/k){ cout << -1 << endl; return; } priority_queue<pll> pq; rep1(i,n) pq.push({a[i],i}); vector<vector<ll>> ans; rep1(ops,sum/k){ vector<ll> curr; rep1(iter,k){ auto [val,i] = pq.top(); pq.pop(); curr.pb(i); } ans.pb(curr); trav(i,curr){ a[i]--; pq.push({a[i],i}); } } rep1(i,n){ assert(a[i] == 0); } cout << sz(ans) << endl; trav(ar,ans){ cout << 1 << " "; trav(i,ar){ cout << i << " "; } cout << endl; } } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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