oj.uz

답안 #907018

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
907018 2024-01-15T05:58:38 Z gaga999 Sandcastle 2 (JOI22_ho_t5) C++17
71 / 100
 5000 ms 20604 KB 
#include <cstdio>
#include <stdio.h>
#include <iostream>
#include <math.h>
#include <vector>
#include <queue>
#include <stack>
#include <deque>
#include <algorithm>
#include <utility>
#include <set>
#include <map>
#include <stdlib.h>
#include <cstring>
#include <string.h>
#include <string>
#include <sstream>
#include <assert.h>
#include <climits>
#include <sstream>
#include <numeric>
#include <time.h>
#include <limits.h>
#include <list>
#include <bitset>
#include <unordered_map>
#include <unordered_set>
#include <random>
#include <iomanip>
#include <complex>
#include <chrono>
#include <fstream>
#include <functional>
#include <unistd.h>
// #pragma GCC optimize("Ofast,no-stack-protector")
// #pragma GCC optimize("O3,unroll-loops")
// #pragma GCC target("avx,avx2,bmi,bmi2,lzcnt,popcnt")
#define lowbit(x) ((x) & -(x))
#define ml(a, b) ((1ll * (a) * (b)) % M)
#define tml(a, b) (a) = ((1ll * (a) * (b)) % M)
#define ad(a, b) ((0ll + (a) + (b)) % M)
#define tad(a, b) (a) = ((0ll + (a) + (b)) % M)
#define mi(a, b) ((0ll + M + (a) - (b)) % M)
#define tmi(a, b) (a) = ((0ll + M + (a) - (b)) % M)
#define tmin(a, b) (a) = min((a), (b))
#define tmax(a, b) (a) = max((a), (b))
#define iter(a) (a).begin(), (a).end()
#define riter(a) (a).rbegin(), (a).rend()
#define init(a, b) memset((a), (b), sizeof(a))
#define cpy(a, b) memcpy((a), (b), sizeof(a))
#define uni(a) a.resize(unique(iter(a)) - a.begin())
#define pb emplace_back
#define mpr make_pair
#define ls(i) ((i) << 1)
#define rs(i) ((i) << 1 | 1)
#define INF 0x3f3f3f3f
#define NIF 0xc0c0c0c0
#define eps 1e-9
#define F first
#define S second
#define AC cin.tie(0)->sync_with_stdio(0)
using namespace std;
typedef long long llt;
typedef pair<int, int> pii;
typedef pair<double, double> pdd;
typedef pair<llt, llt> pll;
typedef complex<double> cd;
// const int M = 998244353;

// random_device rm;
// mt19937 rg(rm());
// default_random_engine rg(rm());
// uniform_int_distribution<int> rd(INT_MIN, INT_MAX);
// uniform_real_distribution<double> rd(0, M_PI);

void db() { cerr << "\n"; }
template <class T, class... U>
void db(T a, U... b) { cerr << a << " ", db(b...); }

inline char gc()
{
    const static int SZ = 1 << 16;
    static char buf[SZ], *p1, *p2;
    if (p1 == p2 && (p2 = buf + fread(p1 = buf, 1, SZ, stdin), p1 == p2))
        return -1;
    return *p1++;
}
void rd() {}
template <typename T, typename... U>
void rd(T &x, U &...y)
{
    x = 0;
    bool f = 0;
    char c = gc();
    while (!isdigit(c))
        f ^= !(c ^ 45), c = gc();
    while (isdigit(c))
        x = (x << 1) + (x << 3) + (c ^ 48), c = gc();
    f && (x = -x), rd(y...);
}

template <typename T>
void prt(T x)
{
    if (x < 0)
        putchar('-'), x = -x;
    if (x > 9)
        prt(x / 10);
    putchar((x % 10) ^ 48);
}

vector<vector<int>> gd, v[3][3][3][3], v1[3][3], v2[3][3], vr;
#define p1 [x - 1][y]
#define p2 [x][y - 1]
#define p3 [x][y + 1]
#define p4 [x + 1][y]
#define c1 x != l
#define c2 y != u
#define c3 y != d
#define c4 x != r
int gv(int x, int y, int l, int r, int u, int d)
{
    int mn = INF, cr = gd[x][y], res = 0;
    if (c1 && gd p1 > cr && gd p1 < mn)
        mn = gd p1, res = 1;
    if (c2 && gd p2 > cr && gd p2 < mn)
        mn = gd p2, res = 2;
    if (c3 && gd p3 > cr && gd p3 < mn)
        mn = gd p3, res = 3;
    if (c4 && gd p4 > cr && gd p4 < mn)
        mn = gd p4, res = 4;
    return res;
}
#define pp l, r, u, d
int slv(int x, int y, int l, int r, int u, int d)
{
    int res = 0;
    if (c1 && gv(x - 1, y, pp) == 4)
        res++;
    if (c2 && gv(x, y - 1, pp) == 3)
        res++;
    if (c3 && gv(x, y + 1, pp) == 2)
        res++;
    if (c4 && gv(x + 1, y, pp) == 1)
        res++;
    return !res;
}
inline int grc(int l, int r, int i, int j)
{
    return vr[l][i] + vr[r][j] - vr[l][j] - vr[r][i];
}
#define vt(i, j) vector<vector<int>>(i, vector<int>(j))
signed main()
{
    int n, m;
    rd(n, m);
    if (n > m)
    {
        swap(n, m);
        gd = vt(n, m);
        for (int i = 0; i < m; i++)
            for (int j = 0; j < n; j++)
                rd(gd[j][i]);
    }
    else
    {
        gd = vt(n, m);
        for (int i = 0; i < n; i++)
            for (int j = 0; j < m; j++)
                rd(gd[i][j]);
    }
    for (int l = 0; l < 3; l++)
    {
        for (int r = 0; r < 3; r++)
        {
            for (int u = 0; u < 3; u++)
            {
                for (int d = 0; d < 3; d++)
                {
                    v[l][r][u][d] = vt(n, m);
                    for (int i = 0; i < n; i++)
                        for (int j = 0; j < m; j++)
                            v[l][r][u][d][i][j] =
                                slv(i, j, max(0, i - l), min(n - 1, i + r), max(0, j - u), min(m - 1, j + d));
                }
            }
        }
    }
    for (int l = 0; l < 3; l++)
    {
        for (int r = 0; r < 3; r++)
        {
            v1[l][r] = v2[l][r] = vt(n, m);
            for (int i = 0; i < n; i++)
            {
                v1[l][r][i][0] = v[l][r][2][2][i][0];
                for (int j = 1; j < m; j++)
                    v1[l][r][i][j] = v[l][r][2][2][i][j] + v1[l][r][i][j - 1];
            }
            for (int j = 0; j < m; j++)
            {
                v2[l][r][0][j] = v[2][2][l][r][0][j];
                for (int i = 1; i < n; i++)
                    v2[l][r][i][j] = v[2][2][l][r][i][j] + v2[l][r][i - 1][j];
            }
        }
    }
    vr = vt(n, m);
    for (int i = 0; i < m; i++)
        vr[0][i] = v[2][2][2][2][0][i];
    for (int i = 1; i < n; i++)
    {
        vr[i][0] = v[2][2][2][2][0][i];
        for (int j = 1; j < m; j++)
        {
            vr[i][j] = vr[i - 1][j] + vr[i][j - 1] -
                       vr[i - 1][j - 1] + v[2][2][2][2][i][j];
        }
    }
    llt ans = 0;
    for (int l = 0; l < n; l++)
    {
        for (int r = 0; r < n; r++)
        {
            if (r - l < 4)
            {
                for (int i = 0; i < m; i++)
                {
                    for (int j = i; j < m; j++)
                    {
                        if (j - i < 4)
                        {
                            int tp = 0;
                            for (int a = l; a <= r; a++)
                                for (int b = i; b <= j; b++)
                                    tp += v[min(2, a - l)][min(2, r - a)][min(2, b - i)][min(2, j - b)][a][b];
                            if (tp == 1)
                                ans++;
                        }
                        else
                        {
                            int tp = 0;
                            for (int a = l; a <= r; a++)
                            {
                                int x = min(2, a - l), y = min(2, r - a);
                                tp += v[x][y][0][2][a][i];
                                tp += v[x][y][1][2][a][i + 1];
                                tp += v[x][y][2][0][a][j];
                                tp += v[x][y][2][1][a][j - 1];
                                tp += v1[x][y][a][j - 2] - v1[x][y][a][i + 1];
                            }
                            if (tp == 1)
                                ans++;
                        }
                    }
                }
            }
            else
            {
                for (int i = 0; i < m; i++)
                {
                    for (int j = i; j < m; j++)
                    {
                        if (j - i < 4)
                        {
                            int tp = 0;
                            for (int b = i; b <= j; b++)
                            {
                                int x = min(b - i, 2), y = min(j - b, 2);
                                tp += v[0][2][x][y][l][b];
                                tp += v[1][2][x][y][l + 1][b];
                                tp += v[2][0][x][y][r][b];
                                tp += v[2][1][x][y][r - 1][b];
                                tp += v2[x][y][r - 2][b] - v2[x][y][l + 1][b];
                            }
                            if (tp == 1)
                                ans++;
                        }
                        else
                        {
                            int tp = 0;
                            tp += v[0][2][0][2][l][i];
                            tp += v[1][2][0][2][l + 1][i];
                            tp += v[0][2][1][2][l][i + 1];
                            tp += v[1][2][1][2][l + 1][i + 1];
                            //-0-------------
                            tp += v[2][0][2][0][r][j];
                            tp += v[2][1][2][0][r - 1][j];
                            tp += v[2][0][2][1][r][j - 1];
                            tp += v[2][1][2][1][r - 1][j - 1];
                            //-0-------------
                            tp += v[2][0][0][2][r][i];
                            tp += v[2][0][1][2][r][i + 1];
                            tp += v[2][1][0][2][r - 1][i];
                            tp += v[2][1][1][2][r - 1][i + 1];
                            //-----------------
                            tp += v[0][2][2][0][l][j];
                            tp += v[1][2][2][0][l + 1][j];
                            tp += v[0][2][2][1][l][j - 1];
                            tp += v[1][2][2][1][l + 1][j - 1];
                            //---------------------
                            tp += v2[0][2][r - 2][i] - v2[0][2][l + 1][i];
                            tp += v2[1][2][r - 2][i + 1] - v2[1][2][l + 1][i + 1];
                            tp += v2[2][0][r - 2][j] - v2[2][0][l + 1][j];
                            tp += v2[2][1][r - 2][j - 1] - v2[2][1][l + 1][j - 1];
                            //---------------
                            tp += v1[0][2][l][j - 2] - v1[0][2][l][i + 1];
                            tp += v1[1][2][l + 1][j - 2] - v1[1][2][l + 1][i + 1];
                            tp += v1[2][0][r][j - 2] - v1[2][0][r][i + 1];
                            tp += v1[2][1][r - 1][j - 2] - v1[2][1][r - 1][i + 1];
                            //--------------
                            tp += grc(l + 1, r - 2, i + 1, j - 2);
                            if (tp == 1)
                                ans++;
                        }
                    }
                }
            }
        }
    }
    prt(ans), putchar('\n');
}

Subtask #1
0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 348 KB Output is correct
2 Execution timed out 5088 ms 20380 KB Time limit exceeded
3 Halted 0 ms 0 KB -

Subtask #2
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 348 KB Output is correct
2 Correct 1 ms 348 KB Output is correct
3 Correct 1 ms 348 KB Output is correct
4 Correct 1 ms 348 KB Output is correct
5 Correct 1 ms 348 KB Output is correct
6 Correct 1 ms 348 KB Output is correct

Subtask #3
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 348 KB Output is correct
2 Correct 1 ms 348 KB Output is correct
3 Correct 1 ms 348 KB Output is correct
4 Correct 1 ms 348 KB Output is correct
5 Correct 1 ms 348 KB Output is correct
6 Correct 1 ms 348 KB Output is correct
7 Correct 9 ms 860 KB Output is correct
8 Correct 11 ms 1044 KB Output is correct
9 Correct 15 ms 1144 KB Output is correct
10 Correct 13 ms 1116 KB Output is correct
11 Correct 12 ms 1112 KB Output is correct
12 Correct 10 ms 860 KB Output is correct
13 Correct 12 ms 1116 KB Output is correct
14 Correct 8 ms 860 KB Output is correct
15 Correct 15 ms 1116 KB Output is correct
16 Correct 16 ms 1116 KB Output is correct

Subtask #4
56.0 / 56.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 348 KB Output is correct
2 Correct 1 ms 348 KB Output is correct
3 Correct 1 ms 348 KB Output is correct
4 Correct 1 ms 348 KB Output is correct
5 Correct 1 ms 348 KB Output is correct
6 Correct 1 ms 348 KB Output is correct
7 Correct 9 ms 860 KB Output is correct
8 Correct 11 ms 1044 KB Output is correct
9 Correct 15 ms 1144 KB Output is correct
10 Correct 13 ms 1116 KB Output is correct
11 Correct 12 ms 1112 KB Output is correct
12 Correct 10 ms 860 KB Output is correct
13 Correct 12 ms 1116 KB Output is correct
14 Correct 8 ms 860 KB Output is correct
15 Correct 15 ms 1116 KB Output is correct
16 Correct 16 ms 1116 KB Output is correct
17 Correct 179 ms 3412 KB Output is correct
18 Correct 241 ms 3408 KB Output is correct
19 Correct 239 ms 3156 KB Output is correct
20 Correct 232 ms 3668 KB Output is correct
21 Correct 227 ms 3420 KB Output is correct
22 Correct 222 ms 3420 KB Output is correct
23 Correct 215 ms 3420 KB Output is correct
24 Correct 184 ms 3192 KB Output is correct
25 Correct 277 ms 3668 KB Output is correct
26 Correct 247 ms 3420 KB Output is correct
27 Correct 239 ms 3420 KB Output is correct
28 Correct 245 ms 3668 KB Output is correct

Subtask #5
0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 348 KB Output is correct
2 Correct 1 ms 348 KB Output is correct
3 Correct 1 ms 348 KB Output is correct
4 Correct 1 ms 348 KB Output is correct
5 Correct 1 ms 348 KB Output is correct
6 Correct 1 ms 348 KB Output is correct
7 Correct 9 ms 860 KB Output is correct
8 Correct 11 ms 1044 KB Output is correct
9 Correct 15 ms 1144 KB Output is correct
10 Correct 13 ms 1116 KB Output is correct
11 Correct 12 ms 1112 KB Output is correct
12 Correct 10 ms 860 KB Output is correct
13 Correct 12 ms 1116 KB Output is correct
14 Correct 8 ms 860 KB Output is correct
15 Correct 15 ms 1116 KB Output is correct
16 Correct 16 ms 1116 KB Output is correct
17 Correct 179 ms 3412 KB Output is correct
18 Correct 241 ms 3408 KB Output is correct
19 Correct 239 ms 3156 KB Output is correct
20 Correct 232 ms 3668 KB Output is correct
21 Correct 227 ms 3420 KB Output is correct
22 Correct 222 ms 3420 KB Output is correct
23 Correct 215 ms 3420 KB Output is correct
24 Correct 184 ms 3192 KB Output is correct
25 Correct 277 ms 3668 KB Output is correct
26 Correct 247 ms 3420 KB Output is correct
27 Correct 239 ms 3420 KB Output is correct
28 Correct 245 ms 3668 KB Output is correct
29 Execution timed out 5041 ms 20604 KB Time limit exceeded
30 Halted 0 ms 0 KB -