oj.uz

답안 #907014

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
907014 2024-01-15T05:55:55 Z gaga999 Sandcastle 2 (JOI22_ho_t5) C++17
15 / 100
 5000 ms 20388 KB 
#include <cstdio>
#include <stdio.h>
#include <iostream>
#include <math.h>
#include <vector>
#include <queue>
#include <stack>
#include <deque>
#include <algorithm>
#include <utility>
#include <set>
#include <map>
#include <stdlib.h>
#include <cstring>
#include <string.h>
#include <string>
#include <sstream>
#include <assert.h>
#include <climits>
#include <sstream>
#include <numeric>
#include <time.h>
#include <limits.h>
#include <list>
#include <bitset>
#include <unordered_map>
#include <unordered_set>
#include <random>
#include <iomanip>
#include <complex>
#include <chrono>
#include <fstream>
#include <functional>
#include <unistd.h>
// #pragma GCC optimize("Ofast,no-stack-protector")
// #pragma GCC optimize("O3,unroll-loops")
// #pragma GCC target("avx,avx2,bmi,bmi2,lzcnt,popcnt")
#define lowbit(x) ((x) & -(x))
#define ml(a, b) ((1ll * (a) * (b)) % M)
#define tml(a, b) (a) = ((1ll * (a) * (b)) % M)
#define ad(a, b) ((0ll + (a) + (b)) % M)
#define tad(a, b) (a) = ((0ll + (a) + (b)) % M)
#define mi(a, b) ((0ll + M + (a) - (b)) % M)
#define tmi(a, b) (a) = ((0ll + M + (a) - (b)) % M)
#define tmin(a, b) (a) = min((a), (b))
#define tmax(a, b) (a) = max((a), (b))
#define iter(a) (a).begin(), (a).end()
#define riter(a) (a).rbegin(), (a).rend()
#define init(a, b) memset((a), (b), sizeof(a))
#define cpy(a, b) memcpy((a), (b), sizeof(a))
#define uni(a) a.resize(unique(iter(a)) - a.begin())
#define pb emplace_back
#define mpr make_pair
#define ls(i) ((i) << 1)
#define rs(i) ((i) << 1 | 1)
#define INF 0x3f3f3f3f
#define NIF 0xc0c0c0c0
#define eps 1e-9
#define F first
#define S second
#define AC cin.tie(0)->sync_with_stdio(0)
using namespace std;
typedef long long llt;
typedef pair<int, int> pii;
typedef pair<double, double> pdd;
typedef pair<llt, llt> pll;
typedef complex<double> cd;
// const int M = 998244353;

// random_device rm;
// mt19937 rg(rm());
// default_random_engine rg(rm());
// uniform_int_distribution<int> rd(INT_MIN, INT_MAX);
// uniform_real_distribution<double> rd(0, M_PI);

void db() { cerr << "\n"; }
template <class T, class... U>
void db(T a, U... b) { cerr << a << " ", db(b...); }

inline char gc()
{
    const static int SZ = 1 << 16;
    static char buf[SZ], *p1, *p2;
    if (p1 == p2 && (p2 = buf + fread(p1 = buf, 1, SZ, stdin), p1 == p2))
        return -1;
    return *p1++;
}
void rd() {}
template <typename T, typename... U>
void rd(T &x, U &...y)
{
    x = 0;
    bool f = 0;
    char c = gc();
    while (!isdigit(c))
        f ^= !(c ^ 45), c = gc();
    while (isdigit(c))
        x = (x << 1) + (x << 3) + (c ^ 48), c = gc();
    f && (x = -x), rd(y...);
}

template <typename T>
void prt(T x)
{
    if (x < 0)
        putchar('-'), x = -x;
    if (x > 9)
        prt(x / 10);
    putchar((x % 10) ^ 48);
}

vector<vector<int>> gd, v[3][3][3][3], v1[3][3], v2[3][3], vr;
#define p1 [x - 1][y]
#define p2 [x][y - 1]
#define p3 [x][y + 1]
#define p4 [x + 1][y]
#define c1 x != l
#define c2 y != u
#define c3 y != d
#define c4 x != r
int gv(int x, int y, int l, int r, int u, int d)
{
    int mn = INF, cr = gd[x][y], res = 0;
    if (c1 && gd p1 > cr && gd p1 < mn)
        mn = gd p1, res = 1;
    if (c2 && gd p2 > cr && gd p2 < mn)
        mn = gd p2, res = 2;
    if (c3 && gd p3 > cr && gd p3 < mn)
        mn = gd p3, res = 3;
    if (c4 && gd p4 > cr && gd p4 < mn)
        mn = gd p4, res = 4;
    return res;
}
#define pp l, r, u, d
int slv(int x, int y, int l, int r, int u, int d)
{
    int res = 0;
    if (c1 && gv(x - 1, y, pp) == 4)
        res++;
    if (c2 && gv(x, y - 1, pp) == 3)
        res++;
    if (c3 && gv(x, y + 1, pp) == 2)
        res++;
    if (c4 && gv(x + 1, y, pp) == 1)
        res++;
    return !res;
}
inline int grc(int l, int r, int i, int j)
{
    return vr[l][i] + vr[r][j] - vr[l][j] - vr[r][i];
}
#define vt(i, j) vector<vector<int>>(i, vector<int>(j))
signed main()
{
    int n, m;
    rd(n, m);
    if (n > m)
    {
        swap(n, m);
        gd = vt(n, m);
        for (int i = 0; i < m; i++)
            for (int j = 0; j < n; j++)
                rd(gd[j][i]);
    }
    else
    {
        gd = vt(n, m);
        for (int i = 0; i < n; i++)
            for (int j = 0; j < m; j++)
                rd(gd[i][j]);
    }
    for (int l = 0; l < 3; l++)
    {
        for (int r = 0; r < 3; r++)
        {
            for (int u = 0; u < 3; u++)
            {
                for (int d = 0; d < 3; d++)
                {
                    v[l][r][u][d] = vt(n, m);
                    for (int i = 0; i < n; i++)
                        for (int j = 0; j < m; j++)
                            v[l][r][u][d][i][j] =
                                slv(i, j, max(0, i - l), min(n - 1, i + r), max(0, j - u), min(m - 1, j + d));
                }
            }
        }
    }
    for (int l = 0; l < 3; l++)
    {
        for (int r = 0; r < 3; r++)
        {
            v1[l][r] = v2[l][r] = vt(n, m);
            for (int i = 0; i < n; i++)
            {
                v1[l][r][i][0] = v[l][r][2][2][i][0];
                for (int j = 1; j < m; j++)
                    v1[l][r][i][j] = v[l][r][2][2][i][j] + v1[l][r][i][j - 1];
            }
            for (int j = 0; j < m; j++)
            {
                v2[l][r][0][j] = v[2][2][l][r][0][j];
                for (int i = 1; i < n; i++)
                    v2[l][r][i][j] = v[2][2][l][r][i][j] + v2[l][r][i - 1][j];
            }
        }
    }
    vr = vt(n, m);
    for (int i = 0; i < m; i++)
        vr[0][i] = v[2][2][2][2][0][i];
    for (int i = 1; i < n; i++)
    {
        vr[i][0] = v[2][2][2][2][0][i];
        for (int j = 1; j < m; j++)
        {
            vr[i][j] = vr[i - 1][j] + vr[i][j - 1] -
                       vr[i - 1][j - 1] + v[2][2][2][2][i][j];
        }
    }
    llt ans = 0;
    for (int l = 0; l < n; l++)
    {
        for (int r = 0; r < n; r++)
        {
            if (r - l < 4)
            {
                for (int i = 0; i < m; i++)
                {
                    for (int j = i; j < m; j++)
                    {
                        if (j - i < 4)
                        {
                            int tp = 0;
                            for (int a = l; a <= r; a++)
                                for (int b = i; b <= j; b++)
                                    tp += v[min(2, a - l)][min(2, r - a)][min(2, b - i)][min(2, j - b)][a][b];
                            if (tp == 1)
                                ans++;
                        }
                        else
                        {
                            int tp = 0;
                            for (int a = l; a <= r; a++)
                            {
                                int x = min(2, a - l), y = min(2, r - a);
                                tp += v[x][y][0][2][a][i];
                                tp += v[x][y][1][2][a][i + 1];
                                tp += v[x][y][2][0][a][j];
                                tp += v[x][y][2][1][a][j - 1];
                                tp += v1[x][y][a][j - 2] - v1[x][y][a][i + 1];
                            }
                            if (tp == 1)
                                ans++;
                        }
                    }
                }
            }
            else
            {
                for (int i = 0; i < m; i++)
                {
                    for (int j = i; j < m; j++)
                    {
                        int tp = 0;
                        for (int a = l; a <= r; a++)
                            for (int b = i; b <= j; b++)
                                tp += v[min(2, a - l)][min(2, r - a)][min(2, b - i)][min(2, j - b)][a][b];
                        if (tp == 1)
                            ans++;
                    }
                }
            }
        }
    }
    prt(ans), putchar('\n');
}

Subtask #1
0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 348 KB Output is correct
2 Execution timed out 5082 ms 20388 KB Time limit exceeded
3 Halted 0 ms 0 KB -

Subtask #2
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 348 KB Output is correct
2 Correct 1 ms 348 KB Output is correct
3 Correct 1 ms 348 KB Output is correct
4 Correct 1 ms 756 KB Output is correct
5 Correct 1 ms 348 KB Output is correct
6 Correct 1 ms 348 KB Output is correct

Subtask #3
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 348 KB Output is correct
2 Correct 1 ms 348 KB Output is correct
3 Correct 1 ms 348 KB Output is correct
4 Correct 1 ms 756 KB Output is correct
5 Correct 1 ms 348 KB Output is correct
6 Correct 1 ms 348 KB Output is correct
7 Correct 10 ms 860 KB Output is correct
8 Correct 10 ms 856 KB Output is correct
9 Correct 207 ms 1120 KB Output is correct
10 Correct 227 ms 1112 KB Output is correct
11 Correct 10 ms 860 KB Output is correct
12 Correct 11 ms 860 KB Output is correct
13 Correct 200 ms 1116 KB Output is correct
14 Correct 74 ms 860 KB Output is correct
15 Correct 222 ms 1116 KB Output is correct
16 Correct 217 ms 1120 KB Output is correct

Subtask #4
0 / 56.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 348 KB Output is correct
2 Correct 1 ms 348 KB Output is correct
3 Correct 1 ms 348 KB Output is correct
4 Correct 1 ms 756 KB Output is correct
5 Correct 1 ms 348 KB Output is correct
6 Correct 1 ms 348 KB Output is correct
7 Correct 10 ms 860 KB Output is correct
8 Correct 10 ms 856 KB Output is correct
9 Correct 207 ms 1120 KB Output is correct
10 Correct 227 ms 1112 KB Output is correct
11 Correct 10 ms 860 KB Output is correct
12 Correct 11 ms 860 KB Output is correct
13 Correct 200 ms 1116 KB Output is correct
14 Correct 74 ms 860 KB Output is correct
15 Correct 222 ms 1116 KB Output is correct
16 Correct 217 ms 1120 KB Output is correct
17 Correct 176 ms 3164 KB Output is correct
18 Execution timed out 5091 ms 3200 KB Time limit exceeded
19 Halted 0 ms 0 KB -

Subtask #5
0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 348 KB Output is correct
2 Correct 1 ms 348 KB Output is correct
3 Correct 1 ms 348 KB Output is correct
4 Correct 1 ms 756 KB Output is correct
5 Correct 1 ms 348 KB Output is correct
6 Correct 1 ms 348 KB Output is correct
7 Correct 10 ms 860 KB Output is correct
8 Correct 10 ms 856 KB Output is correct
9 Correct 207 ms 1120 KB Output is correct
10 Correct 227 ms 1112 KB Output is correct
11 Correct 10 ms 860 KB Output is correct
12 Correct 11 ms 860 KB Output is correct
13 Correct 200 ms 1116 KB Output is correct
14 Correct 74 ms 860 KB Output is correct
15 Correct 222 ms 1116 KB Output is correct
16 Correct 217 ms 1120 KB Output is correct
17 Correct 176 ms 3164 KB Output is correct
18 Execution timed out 5091 ms 3200 KB Time limit exceeded
19 Halted 0 ms 0 KB -