Submission #906298

#	Time	Username	Problem	Language	Result	Execution time	Memory
906298		vjudge1	Job Scheduling (IOI19_job)	C++17	12 / 100	67 ms	6104 KiB

job

#include "job.h"
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>

#define endl '\n'
#define K first
#define V second

using namespace std;
using namespace __gnu_pbds;


template<typename T>
ostream_iterator<T> oit(const string &s = " "){
    return ostream_iterator<T>(cout,s.c_str());
}

struct chash {
    static uint64_t splitmix64(uint64_t x) {
        // http://xorshift.di.unimi.it/splitmix64.c
        x += 0x9e3779b97f4a7c15;
        x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;
        x = (x ^ (x >> 27)) * 0x94d049bb133111eb;
        return x ^ (x >> 31);
    }

    size_t operator()(uint64_t x) const {
        static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();
        return splitmix64(x + FIXED_RANDOM);
    }
};

template<typename T, typename U> using pb_map = gp_hash_table<T, U, chash>;
template<typename T> using pb_set = gp_hash_table<T, null_type, chash>;

typedef long long ll;
typedef long double ld;

typedef vector<int> vi;
typedef vector<vector<int>> vii;
typedef vector<ll> vll;
typedef pair<ll,ll> pll;
typedef pair<int,int> pii;

constexpr ll NN = 2e5;
constexpr ll M = 1000000007;



long long scheduling_cost(std::vector<int> p, std::vector<int> u, std::vector<int> d) {
	ll ans = 0;
    int n = (int)p.size();
    bool case1 = true,case2 = true;


    for(int i=1;i<n;i++){
        case1 &= p[i]==i-1;

        case2 &= p[i]==0;
        case2 &= d[i]==1;
    }

    if(case1){
        ll time = 0;
        for(int i=0;i<n;i++){
            time += d[i];
            ans += time*u[i];
        }
        return ans;
    }

    if(case2){
        ll time = d[0];
        ans += time*u[0];

        vi ord(n-1); iota(ord.begin(),ord.end(),1);

        sort(ord.begin(),ord.end(), [&](int i,int j){
            return -u[i]*d[i] < -u[j]*d[j];
        });

        for(int i : ord){
            time += d[i];
            ans += time*u[i];
        }

        return ans;
    }

    return ans;
}

• Subtask 1: 5 / 5
• Subtask 2: 7 / 7
• Subtask 3: 0 / 12
• Subtask 4: 0 / 18
• Subtask 5: 0 / 21
• Subtask 6: 0 / 37