이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <iostream>
#include <set>
#include <algorithm>
#include <vector>
using namespace std;
#define ll long long
const ll inf=1e18;
const ll N=200;
ll aps[N];
ll pre[N];
ll dp[N][N];
bool posp[N][N];
int main()
{
int n,a,b;
cin>>n>>a>>b;
for(int i=0;i<n;i++)
{
cin>>aps[i];
pre[i+1]=aps[i]+pre[i];
}
ll pos=(1ll<<21)-1;
for(int i=20;i>=0;i--)
{
ll new_pos=pos-(1ll<<i);
// Can i spilt the array in segement so that the final_or let that be b so that the bit off in pos are off in b
// dp[i][j] let spilt the prefix i into j part so what is the minimum or possible
for(int i=0;i<=n;i++)
for(int j=0;j<=n;j++)
dp[i][j]=inf;
for(int i=0;i<=n;i++)
for(int j=0;j<=n;j++)
posp[i][j]=0;
dp[0][0]=0;
posp[0][0]=1;
bool pos1=0;
for(int i=1;i<=n;i++)
{
for(int j=1;j<=i;j++)
{
for(int k=0;k<i;k++)
{
if(posp[k][j-1])
{
bool das=1;
ll np=(dp[k][j-1]|(pre[i]-pre[k]));
for(int bit=20;bit>=0;bit--)
{
if((np&(1<<bit))>((new_pos&(1<<bit))))
{
das=0;
}
}
if(das)
{
dp[i][j]=min(dp[i][j],(dp[k][j-1]|(pre[i]-pre[k])));
posp[i][j]=1;
}
}
}
if(i==n and a<=j and j<=b and posp[i][j])
{
pos1=1;
}
}
}
if(pos1)
pos=new_pos;
}
cout<<pos<<endl;
return 0;
}
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