제출 #905227

#제출 시각아이디문제언어결과실행 시간메모리
905227qinFinancial Report (JOI21_financial)C++17
100 / 100
767 ms48464 KiB
#include <bits/stdc++.h> #define fi first #define se second #define ssize(x) int(x.size()) #define pn printf("\n") #define all(x) x.begin(),x.end() using namespace std; typedef long long ll; typedef pair<int, int> pii; int inf = 2e09; ll infll = 2e18; int base = 1; struct seg{ struct Node{ int mn1, mn2, mx, p; Node(){ mn1 = inf-1, mn2 = inf, mx = 0, p = 0; } // mn1 < mn2 Node(int m1, int m2, int mxx, int pp) { mn1 = m1, mn2 = m2, mx = mxx, p = pp; } }; vector<Node> t; void init(int n){ while(base < n) base <<= 1; t.resize(base<<1); } void merge(int i){ t[i].mx = max(t[i<<1].mx, t[i<<1|1].mx); if(t[i<<1].mn1 < t[i<<1|1].mn1) t[i].mn1 = t[i<<1].mn1, t[i].mn2 = min(t[i<<1].mn2, t[i<<1|1].mn1); else if(t[i<<1].mn1 > t[i<<1|1].mn1) t[i].mn1 = t[i<<1|1].mn1, t[i].mn2 = min(t[i<<1].mn1, t[i<<1|1].mn2); else t[i].mn1 = t[i<<1].mn1, t[i].mn2 = min(t[i<<1].mn2, t[i<<1|1].mn2); } void max_node(int i, int val){ t[i].mn1 = val, t[i].p = max(t[i].p, val); } void push(int i){ if(t[i].p){ if(t[i<<1].mn1 < t[i].p) max_node(i<<1, t[i].p); if(t[i<<1|1].mn1 < t[i].p)max_node(i<<1|1, t[i].p); t[i].p = 0; } } void upd_point(int i, int s, int e, int x, int val, int time){ if(s == e) return void(t[i] = Node(time, inf, val, 0)); int mid = (s+e)>>1; push(i); if(x <= mid) upd_point(i<<1, s, mid, x, val, time); else upd_point(i<<1|1, mid+1, e, x, val, time); merge(i); } void update(int x, int val, int time){ upd_point(1, 1, base, x, val, time); } void purge_point(int i, int &time){ if(base <= i) return void(t[i] = Node()); push(i); if(t[i<<1].mn1 < time) purge_point(i<<1, time); if(t[i<<1|1].mn1 < time) purge_point(i<<1|1, time); merge(i); } void zero(int time){ purge_point(1, time); } int qr(int i, int s, int e, int x, int y){ if(x <= s && e <= y) return t[i].mx; int mid = (s+e)>>1, ret = 0; push(i); if(x <= mid) ret = max(ret, qr(i<<1, s, mid, x, y)); if(mid < y) ret = max(ret, qr(i<<1|1, mid+1, e, x, y)); merge(i); return ret; } int query(int x, int y){ if(x <= y) return qr(1, 1, base, max(1, x), min(base, y)); return 0; } void mx_time(int i, int s, int e, int x, int y, int time){ if(x <= s && e <= y && t[i].mn1 <= time && time < t[i].mn2) return void(max_node(i, time)); int mid = (s+e)>>1; push(i); if(x <= mid && t[i<<1].mn1 <= time) mx_time(i<<1, s, mid, x, y, time); if(mid < y && t[i<<1|1].mn1 <= time) mx_time(i<<1|1, mid+1, e, x, y, time); merge(i); } void max_time(int l, int r, int time){ mx_time(1, 1, base, l, r, time); } }; void answer(){ int n, d; scanf("%d%d", &n, &d); set<int> sc; vector<int> t(n+1); for(int i = 1; i <= n; ++i) scanf("%d", &t[i]), sc.emplace(t[i]); unordered_map<int, int> mp; int it = 0; for(int u : sc) mp[u] = ++it; for(int i = 1; i <= n; ++i) t[i] = mp[t[i]]; seg seg; seg.init(n); int result = 0; deque<int> dq; for(int i = 1; i <= n; ++i){ if(ssize(dq) && dq.front() < i-d) dq.pop_front(); int mn = ssize(dq) ? t[dq.front()] : inf, mn_time = ssize(dq) ? dq.front() : 0; while(ssize(dq) && t[i] <= t[dq.back()]) dq.pop_back(); dq.emplace_back(i); //~ printf("%d %d\n", mn, mn_time); if(mn != inf) seg.max_time(mn, base, mn_time), seg.zero(i-d); if(i != n) seg.update(t[i], max(seg.query(1, t[i]-1)+1, seg.query(t[i], t[i])), i); else result = max(seg.query(1, t[i]-1)+1, seg.query(t[i], base)); //~ for(int j = 1; j <= n; ++j) printf("%d %d, ", seg.query(j, j), seg.t[j+base-1].mn1); //~ pn; } printf("%d\n", result); } int main(){ int T = 1; for(++T; --T; ) answer(); return 0; }

컴파일 시 표준 에러 (stderr) 메시지

Main.cpp: In function 'void answer()':
Main.cpp:75:18: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   75 |   int n, d; scanf("%d%d", &n, &d);
      |             ~~~~~^~~~~~~~~~~~~~~~
Main.cpp:78:36: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   78 |   for(int i = 1; i <= n; ++i) scanf("%d", &t[i]), sc.emplace(t[i]);
      |                               ~~~~~^~~~~~~~~~~~~
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