oj.uz

답안 #905068

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
905068 2024-01-12T13:54:02 Z browntoad Park (BOI16_park) C++14
100 / 100
 676 ms 56396 KB 
#include <bits/stdc++.h>
#pragma GCC optimize ("Ofast", "unroll-loops")
using namespace std;
#define ll long long
#define int ll
#define FOR(i,a,b) for (int i = (a); i<(b); i++)
#define REP(i,n) FOR(i,0,n)
#define REP1(i,n) FOR(i,1,n+1)
#define RREP(i,n) for (int i=(n)-1; i>=0; i--)
#define RREP1(i,n) for (int i=(n); i>=1; i--)
#define f first
#define s second
#define pb push_back
#define ALL(x) x.begin(),x.end()
#define SZ(x) (int)(x.size())
#define SQ(x) (x)*(x)
#define pii pair<int, int>
#define pip pair<int, pii>
#define ppi pair<pii, int>
#define pdd pair<double ,double>
#define pcc pair<char, char>
#define endl '\n'
//#define TOAD
#ifdef TOAD
#define bug(x) cerr<<__LINE__<<": "<<#x<<" is "<<x<<endl
#define IOS()
#else
#define bug(...)
#define IOS() ios::sync_with_stdio(0), cin.tie(0), cout.tie(0)
#endif

const ll inf = 1ll<<60;
const int iinf=2147483647;
const ll mod = 1e9+7;
const ll maxn=2005;
const ll maxm=1e5+5;
const double PI=acos(-1);

ll pw(ll x, ll p, ll m=mod){
    if (p < 0) return 0;
    ll ret=1;
    while (p>0){
        if (p&1){
            ret*=x;
            ret%=m;
        }
        x*=x;
        x%=m;
        p>>=1;
    }
    return ret;
}

ll inv(ll a, ll m=mod){
    return pw(a,m-2,m);
}

vector<bool> ex(16);
struct Point{
    int x, y;
};
int dis2(Point a, Point b){
    return SQ(a.x-b.x)+SQ(a.y-b.y);
}
struct Circ{
    Point a;
    int r, typ, id;
};
bool cmpc(Circ a, Circ b){
    return a.r<b.r;
}
struct Pair{
    int a, b;
    int r; // when it will overlap
};
bool cmpp(Pair a, Pair b){
    return a.r<b.r;
}
struct Quer{
    int r;
    int pos, id;
};
bool cmpq(Quer a, Quer b){
    return a.r<b.r;
}

vector<int> par(maxn), msk(maxn);
int fin(int a){
    if (a == par[a]) return a;
    return par[a] = fin(par[a]);
}
void merg(int a, int b){
    a = fin(a); b = fin(b);
    par[a] = b;
    msk[b] |= msk[a];
    ex[msk[b]] = 1;
}

int n, q, mx, my;
vector<Circ> vc, tmp;
vector<Pair> pr;
vector<Quer> quer;
vector<string> ans(maxm);
bool ex2(int a, int b){
    if (a == 1 && b == 3){
        REP(i, 16){
            if (ex[i] && __builtin_popcount(i) >= 2 && (i != 9 && i != 6)) return 0;
        }
    }
    else {
        REP(i, 16){
            if (ex[i] && __builtin_popcount(i) >= 2 && (i != 12 && i != 3)) return 0;
        }
    }
    return 1;
}
bool ex1(int a, int b){
    // a < b; a and b share an edge
    if (b-a == 2) return ex2(a, b);
    int typ;
    if (a == 1 && b == 2) typ = 2;
    if (a == 2 && b == 3) typ = 1;
    if (a == 3 && b == 4) typ = 0;
    if (a == 1 && b == 4) typ = 3;
    REP(i, 16){
        if (!ex[i]) continue;
        if (i&(1<<typ)){
            if (i != (1<<typ)) return 0;
        }
    }
    return 1;
}


signed main(){
    IOS();
    ex[0] = 1;
    cin>>n>>q>>mx>>my;
    REP(i, n){
        par[i] = i;
    }
    tmp = vector<Circ> (n);
    REP(i, n){
        cin>>tmp[i].a.x>>tmp[i].a.y>>tmp[i].r;
        tmp[i].id = i;
    }
    REP(i, n){
        vc.pb({tmp[i].a, (my-tmp[i].a.y-tmp[i].r)/2+1, 1, tmp[i].id});
        vc.pb({tmp[i].a, (mx-tmp[i].a.x-tmp[i].r)/2+1, 2, tmp[i].id});
        vc.pb({tmp[i].a, (tmp[i].a.y-tmp[i].r)/2+1, 4, tmp[i].id});
        vc.pb({tmp[i].a, (tmp[i].a.x-tmp[i].r)/2+1, 8, tmp[i].id});
    }
    REP(i, n){
        FOR(j, i+1, n){
            int tt = dis2(tmp[i].a, tmp[j].a);
            int l = 1, r = 1000000000,mid;
            while(l < r){
                mid = (l+r)>>1;
                if (tmp[i].r+tmp[j].r+2*mid > 2000000000 || SQ(tmp[i].r+tmp[j].r+2*mid) > tt){
                    r = mid;
                }
                else {
                    l = mid+1;
                }
            }
            pr.pb({i, j, l});
        }
    }
    quer = vector<Quer> (q);
    REP(i, q){
        cin>>quer[i].r>>quer[i].pos;
        quer[i].id = i;
    }

    sort(ALL(vc), cmpc); sort(ALL(pr), cmpp); sort(ALL(quer), cmpq);
    /*
    // woo
    REP(i, SZ(vc)){
        if (vc[i].r <= quer[0].r){
            msk[vc[i].id] |= vc[i].typ;
            ex[msk[vc[i].id]] = 1;
        }
    }
    REP(i, SZ(pr)){
        if (pr[i].r <= quer[0].r){
            merg(pr[i].a, pr[i].b);
        }
    }
    string ret;
    REP1(i, quer[0].pos-1){
        if (ex1(i, quer[0].pos)) ret += (char)(i+'0');
    }
    ret += (char)(quer[0].pos+'0');
    FOR(i, quer[0].pos+1, 5){
        if (ex1(quer[0].pos, i)) ret += (char)(i+'0');
    }
    cout<<ret<<endl;
    // woo
    */

    int pa = 0, pb = 0;
    REP(i, q){
        while(pa < SZ(vc) && vc[pa].r <= quer[i].r){
            msk[fin(vc[pa].id)] |= vc[pa].typ;
            ex[msk[fin(vc[pa].id)]] = 1;
            pa++;
        }
        while(pb < SZ(pr) && pr[pb].r <= quer[i].r){
            merg(pr[pb].a, pr[pb].b);
            pb++;
        }
        string ou;
        REP1(j, quer[i].pos-1){
            if (ex1(j, quer[i].pos)) ou += (char)(j+'0');
        }
        ou += (char)(quer[i].pos + '0');
        FOR(j, quer[i].pos+1, 5){
            if (ex1(quer[i].pos, j)) ou += (char)(j+'0');
        }
        ans[quer[i].id] = ou;
    }
    REP(i, q) cout<<ans[i]<<endl;


}
/*
5 3
16 11
11 8 1
6 10 1
7 3 2
10 4 1
15 5 1
1 1
2 2
2 1

5 1
16 11
11 8 1
6 10 1
7 3 2
10 4 1
15 5 1
2 1
*/

Subtask #1
27.0 / 27.0

# 결과 실행 시간 메모리 Grader output
1 Correct 602 ms 54236 KB Output is correct
2 Correct 616 ms 54056 KB Output is correct
3 Correct 607 ms 54824 KB Output is correct
4 Correct 604 ms 55592 KB Output is correct
5 Correct 617 ms 55012 KB Output is correct
6 Correct 624 ms 54312 KB Output is correct
7 Correct 576 ms 54056 KB Output is correct
8 Correct 567 ms 53388 KB Output is correct
9 Correct 2 ms 3416 KB Output is correct
10 Correct 2 ms 3420 KB Output is correct

Subtask #2
31.0 / 31.0

# 결과 실행 시간 메모리 Grader output
1 Correct 41 ms 6884 KB Output is correct
2 Correct 53 ms 7908 KB Output is correct
3 Correct 41 ms 7904 KB Output is correct
4 Correct 47 ms 7904 KB Output is correct
5 Correct 46 ms 7908 KB Output is correct
6 Correct 40 ms 7924 KB Output is correct
7 Correct 39 ms 7252 KB Output is correct
8 Correct 46 ms 7252 KB Output is correct

Subtask #3
42.0 / 42.0

# 결과 실행 시간 메모리 Grader output
1 Correct 602 ms 54236 KB Output is correct
2 Correct 616 ms 54056 KB Output is correct
3 Correct 607 ms 54824 KB Output is correct
4 Correct 604 ms 55592 KB Output is correct
5 Correct 617 ms 55012 KB Output is correct
6 Correct 624 ms 54312 KB Output is correct
7 Correct 576 ms 54056 KB Output is correct
8 Correct 567 ms 53388 KB Output is correct
9 Correct 2 ms 3416 KB Output is correct
10 Correct 2 ms 3420 KB Output is correct
11 Correct 41 ms 6884 KB Output is correct
12 Correct 53 ms 7908 KB Output is correct
13 Correct 41 ms 7904 KB Output is correct
14 Correct 47 ms 7904 KB Output is correct
15 Correct 46 ms 7908 KB Output is correct
16 Correct 40 ms 7924 KB Output is correct
17 Correct 39 ms 7252 KB Output is correct
18 Correct 46 ms 7252 KB Output is correct
19 Correct 648 ms 55560 KB Output is correct
20 Correct 645 ms 54976 KB Output is correct
21 Correct 656 ms 55792 KB Output is correct
22 Correct 646 ms 56396 KB Output is correct
23 Correct 676 ms 56332 KB Output is correct
24 Correct 647 ms 55152 KB Output is correct