Submission #904071

#	Time	Username	Problem	Language	Result	Execution time	Memory
904071		vjudge1	Odašiljači (COCI20_odasiljaci)	C++17	0 / 70	121 ms	18880 KiB

odasiljaci

#include <bits/stdc++.h>

using namespace std;

struct Dsu {
    vector<int> parent, rank, size;
    Dsu(int N) {
        parent.resize(N);
        rank.resize(N);
        size.resize(N, 1);
        for (int i = 0; i < N; i++){
            parent[i] = i;
        }
    }
    bool isSameSet(int i, int j){
        return findSet(i) == findSet(j);
    }
    int findSet(int i) {
        if(parent[i] == i){
            return i;
        }else{
            return parent[i] = findSet(parent[i]);
        }
    }
    void unionSet(int i, int j){
        int x = findSet(i);
        int y = findSet(j);
        if (x != y){
            if (rank[x] > rank[y]){
                parent[y] = x;
                size[x] += size[y];
            }else if(rank[x] < rank[y]){
                parent[x] = y;
                size[y] += size[x];
            }else{
                parent[x] = y;
                size[y] += size[x];
                rank[y]++;
            }
        }
    }

    int getSize(int i){
        return size[findSet(i)];
    }
};






int main(){
int n;
cin >> n;
pair<long double, long double> ubicaciones[n];
long double x,y;
	for (int i = 0; i<n; i++){
		cin >> x >> y;
		ubicaciones[i].first = x;
		ubicaciones[i].second = y;
	}

vector<pair<double,pair<int,int>>> edges;
for (int i = 0; i<n; i++){
	for(int j = 0; j<n; j++){
            if(i == j) continue;
		double distancia = sqrt((ubicaciones[i].first-ubicaciones[j].first) * (ubicaciones[i].first-ubicaciones[j].first) + (ubicaciones[i].second-ubicaciones[j].second)*(ubicaciones[i].second-ubicaciones[j].second));
		 edges.push_back({distancia,{i,j}});
	}
}

sort(edges.begin(), edges.end());

    Dsu dsu(n);

    // Kruskal
    long double costo_total = 0;
    for(int i = 0; i < n; i++){
        double w = edges[i].first;
        int a = edges[i].second.first;
        int b = edges[i].second.second;

        if(!dsu.isSameSet(a, b)){   // Si a y b no estan en la misma componente conexa
            dsu.unionSet(a, b);     // entonces las uno
            costo_total = w;

        }
    }
costo_total /= 2;
cout << fixed<< setprecision(7)<< costo_total << endl;


return 0;
}

• Subtask 1: 0 / 70