Submission #903084

#TimeUsernameProblemLanguageResultExecution timeMemory
903084GrindMachineSynchronization (JOI13_synchronization)C++17
40 / 100
8080 ms22624 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; vector<pll> adj[N]; vector<pll> times[N]; ll ans; void dfs1(ll u, ll p, ll t){ ans++; for(auto [v,id] : adj[u]){ if(v == p) conts; auto &ti = times[id]; // find the biggest l s.t l <= t auto it = upper_bound(all(ti),make_pair(t+1,-1ll)); if(it == ti.begin()) conts; it--; auto [l,r] = *it; dfs1(v,u,min(t,r)); } } void solve(int test_case) { ll n,m,q; cin >> n >> m >> q; vector<pll> edges(n+5); rep1(i,n-1){ ll u,v; cin >> u >> v; adj[u].pb({v,i}), adj[v].pb({u,i}); edges[i] = {u,v}; } vector<bool> curr(n+5); rep1(i,m){ ll id; cin >> id; if(!curr[id]){ curr[id] = 1; times[id].pb({i,m}); } else{ curr[id] = 0; times[id].back().ss = i; } } while(q--){ ll root; cin >> root; ans = 0; dfs1(root,-1,m+1); cout << ans << endl; } } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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