Submission #900190

#	Time	Username	Problem	Language	Result	Execution time	Memory
900190		aykhn	Foehn Phenomena (JOI17_foehn_phenomena)	C++17	100 / 100	233 ms	16468 KiB

foehn_phenomena

#include <bits/stdc++.h>

// author: aykhn

using namespace std;
typedef long long ll;

#define all(v) v.begin(), v.end()
#define pii pair<int, int>
#define mpr make_pair
#define eb emplace_back
#define pb push_back
#define ts to_string
#define fi first
#define se second
#define ins insert
#define int ll
#define inf 0x3F3F3F3F
#define infll 0x3F3F3F3F3F3F3F3FLL
#define bpc __builtin_popcount

const int MXN = 2e5 + 5;

int n, sz = 1;
int q, s, t;
int st[4 * MXN], a[MXN];

void build(int l, int r, int x)
{
    if (l + 1 == r)
    {
        st[x] = a[l];
        return;
    }
    int mid = (l + r) >> 1;
    build(l, mid, 2*x + 1), build(mid, r, 2*x + 2);
}
void add(int l, int r, int x, int lx, int rx, int val)
{
    if (l >= rx || r <= lx) return;
    if (l >= lx && r <= rx) 
    {
        st[x] += val;
        return;
    }
    int mid = (l + r) >> 1;
    add(l, mid, 2*x + 1, lx, rx, val), add(mid, r, 2*x + 2, lx, rx, val);
}
int get(int l, int r, int x, int ind)
{
    if (l + 1 == r) return st[x];
    int mid = (l + r) >> 1;
    if (ind < mid) return st[x] + get(l, mid, 2*x + 1, ind);
    else return st[x] + get(mid, r, 2*x + 2, ind);
}

signed main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(nullptr);
    int n, q, s, t;
    cin >> n >> q >> s >> t;
    n++;
    while (sz < n) sz <<= 1;
    int res = 0;
    for (int i = 0; i < n; i++) 
    {
        cin >> a[i];
        if (!i) continue;
        if (a[i - 1] < a[i]) res += (a[i - 1] - a[i]) * s;
        else res += (a[i - 1] - a[i]) * t;
    }
    build(0, sz, 0);
    while (q--)
    {
        int l, r, val;
        cin >> l >> r >> val;
        int a = get(0, sz, 0, l - 1), b = get(0, sz, 0, l), c = get(0, sz, 0, r), d = get(0, sz, 0, r + 1);
        if (a < b) res -= (a - b) * s;
        else res -= (a - b) * t;
        if (r + 1 < n && c < d) res -= (c - d) * s;
        else if (r + 1 < n) res -= (c - d) * t;
        add(0, sz, 0, l, r + 1, val);
        b = get(0, sz, 0, l), c = get(0, sz, 0, r);
        if (a < b) res += (a - b) * s;
        else res += (a - b) * t;
        if (r + 1 < n && c < d) res += (c - d) * s;
        else if (r + 1 < n) res += (c - d) * t;
        cout << res << '\n';
    }
}

• Subtask 1: 30 / 30
• Subtask 2: 10 / 10
• Subtask 3: 60 / 60