이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// #include "wiring.h"
#include <cassert>
#include <cstdio>
#include <vector>
#include <climits>
#include <stdlib.h>
#include <algorithm>
using namespace std;
bool isSubtask1(std::vector<int> r, std::vector<int> b) {return r.size()<=200 && b.size()<=200;}
bool isSubtask2(std::vector<int> r, std::vector<int> b) {return r[r.size()-1]<b[0];}
bool isSubtask3(std::vector<int> r, std::vector<int> b) {
int n=r.size(), m=b.size();
vector<int> a(n+m);
for(int i=0, j=0; i<n || j<m;)
i==n? a[i+j++]=1: j==m? a[j+i++]=0: r[i]<b[j]? a[j+i++]=0:a[i+j++] = 1;
int cnt = 1;
for(int k=1; k<n+m; k++) {
cnt = a[k]==a[k-1]? cnt+1:0;
if (cnt > 6) return false;
}
return true;
}
bool isSubtask4(std::vector<int> r, std::vector<int> b) {
return min(r[0],b[0])==1 && max(r[r.size()-1],b[b.size()-1])==r.size()+b.size();
}
long long subtask1(std::vector<int>, std::vector<int>);
long long subtask2(std::vector<int> &, std::vector<int> &, int, int, int, int);
long long subtask3(std::vector<int>, std::vector<int>);
long long subtask4(std::vector<int>, std::vector<int>);
long long fulltask(std::vector<int>, std::vector<int>);
long long min_total_length(std::vector<int>, std::vector<int> );
long long min_total_length(std::vector<int> r, std::vector<int> b) {
return fulltask(r,b);
// if (isSubtask4(r,b)) return subtask4(r,b);
// else if (isSubtask3(r,b)) return subtask3(r,b);
// else if (isSubtask2(r,b)) return subtask2(r,b,0,r.size()-1,0,b.size()-1);
// else if (isSubtask1(r,b)) return subtask1(r,b);
return 0;
}
long long fulltask(std::vector<int> r, std::vector<int> b) {
int n = r.size(), m = b.size();
vector<pair<int,int>> a(n+m);
for(int i=0, j=0; i<n || j<m;)
i==n? a[i+j++]=make_pair(j,1): j==m? a[j+i++]=make_pair(i,0): r[i]<b[j]? a[j+i++]=make_pair(i,0): a[i+j++]=make_pair(j,1);
vector<long long> dp(n+m,LLONG_MAX);
long long sumL=0, cntL=0, sumR=0, cntR=0, gap=0;
int prev=-1, curr=0, optIdx=0;
for(int i=1; i<n+m; i++) {
vector<int> *left, *right;
if (a[i].second != a[i-1].second) {
prev=curr; curr=i; sumR=cntR=0; sumL=0; optIdx=curr-1;
if (a[prev].second==0) {left=&r; right=&b;}
else {left=&b; right=&r;}
gap = (*right)[a[curr].first]-(*left)[a[curr-1].first];
// gap= a[prev].second==0? b[a[curr].first]-r[a[curr-1].first]: r[a[curr].first]-b[a[curr-1].first];
}
if (prev==-1) continue;
sumR += a[curr].second==0? r[a[i].first]-r[a[curr].first]:b[a[i].first]-b[a[curr].first];
cntR++;
for(int j=optIdx; j>=prev; j--) {
cntL=curr-j;
sumL += a[prev].second==0? r[a[curr-1].first]-r[a[j].first]:b[a[curr-1].first]-b[a[j].first];
if(prev==0 && j!=0) continue;
long long temp = sumL + sumR + max(cntL,cntR)*gap;
if (prev!=0) temp += min(dp[j-1],dp[j]);
if (dp[i]>temp) {dp[i]=temp; optIdx=j;}
else break;
}
for(int k=max(optIdx-1,prev); k<=optIdx; k++)
sumL -= a[prev].second==0? r[a[curr-1].first]-r[a[k].first]:b[a[curr-1].first]-b[a[k].first];
}
return dp[n+m-1];
}
long long subtask4(std::vector<int> r, std::vector<int> b) {
int n = r.size(), m = b.size();
vector<int> a(n+m);
for(int i=0, j=0; i<n || j<m;)
i==n? a[i+j++]=1: j==m? a[j+i++]=0: r[i]<b[j]? a[j+i++]=0: a[i+j++]=1;
long long dp1=LLONG_MAX, dp2=LLONG_MAX;
long long cntL=0, cntR=1;
int prev=-1, curr=0;
for(int i=1; i<n+m; i++) {
if (a[i]!=a[i-1]) {prev=curr; curr=i; cntL=cntR, cntR=0;}
cntR++;
long long cntL1 = cntL/2, cntL2 = (cntL+1)/2;
long long cntR1 = cntR/2, cntR2 = (cntR+1)/2;
long long sumL = cntL*(cntL-1)/2, sumR = cntR*(cntR-1)/2;
long long sumL1 = cntL1*(cntL1-1)/2, sumL2 = cntL2*(cntL2-1)/2;
long long sumR1 = cntR1*(cntR1-1)/2, sumR2 = cntR2*(cntR2-1)/2;
if(i==n+m-1) {
if(prev==0) // subtask2와 동일하므로 생략가능
return sumL + max(cntL,cntR) + sumR;
else
return min(dp1 + sumL2 + max(cntL2,cntR), dp2 + sumL1 + max(cntL1,cntR)) + sumR;
}
else if (a[i]!= a[i+1]) {
if (prev==0) {
dp1 = sumL + max(cntL,cntR1) + sumR1;
dp2 = sumL + max(cntL,cntR2) + sumR2;
}
else {
long long new_dp1 = min(dp1 + sumL2 + max(cntL2,cntR1), dp2 + sumL1 + max(cntL1,cntR1)) + sumR1;
long long new_dp2 = min(dp1 + sumL2 + max(cntL2,cntR2), dp2 + sumL1 + max(cntL1,cntR2)) + sumR2;
dp1 = new_dp1; dp2 = new_dp2;
}
}
}
}
long long subtask3(std::vector<int> r, std::vector<int> b) {
int n = r.size(), m = b.size();
vector<pair<int,int>> a(n+m);
for(int i=0, j=0; i<n || j<m;) // make_pair 내부에서 ++ 하면 안됨
i==n? a[i+j++]=make_pair(j,1): j==m? a[j+i++]=make_pair(i,0): r[i]<b[j]? a[j+i++]=make_pair(i,0): a[i+j++]=make_pair(j,1);
vector<long long> dp(n+m,LLONG_MAX);
long long sumL=0, cntL=0, sumR=0, cntR=0, gap=0;
int prev=-1, curr=0;
for(int i=1; i<n+m; i++) {
if (a[i].second != a[i-1].second) {
prev=curr; curr=i; sumR=cntR=0;
gap= a[prev].second==0? b[a[curr].first]-r[a[curr-1].first]: r[a[curr].first]-b[a[curr-1].first];
}
if (prev==-1) continue;
sumR += a[curr].second==0? r[a[i].first]-r[a[curr].first]:b[a[i].first]-b[a[curr].first];
cntR++;
for(int j=curr-1; j>=prev; j--) {
cntL++;
sumL += a[prev].second==0? r[a[curr-1].first]-r[a[j].first]:b[a[curr-1].first]-b[a[j].first];
if (prev==0 && j!=0) continue;
long long temp = sumL + sumR + max(cntL,cntR)*gap;
if (prev!=0) temp += min(dp[j-1],dp[j]);
dp[i] = min(dp[i], temp);
}
sumL=cntL=0;
}
return dp[n+m-1];
}
long long subtask2(std::vector<int> &arr1, std::vector<int> &arr2, int s1, int e1, int s2, int e2) {
long long sum1=0, sum2=0, n = e1-s1+1, m=e2-s2+1;
for(int i=s1; i<=e1; i++) sum1 += arr1[e1] - arr1[i];
for(int i=s2; i<=e2; i++) sum2 += arr2[i] - arr2[s2];
return sum1+sum2+max(n,m)*(arr2[s2]-arr1[e1]);
}
long long subtask1(std::vector<int> r, std::vector<int> b) {
int n = r.size(), m = b.size();
long long dp[n][m];
dp[0][0] = abs(r[0]-b[0]);
for(int i=1; i<n; i++) dp[i][0] = dp[i-1][0] + abs(r[i]-b[0]);
for(int j=1; j<m; j++) dp[0][j] = dp[0][j-1] + abs(r[0]-b[j]);
for(int i=1; i<n; i++)
for(int j=1; j<m; j++)
dp[i][j] = min(min(dp[i-1][j],dp[i][j-1]),dp[i-1][j-1]) + abs(r[i]-b[j]);
return dp[n-1][m-1];
}
컴파일 시 표준 에러 (stderr) 메시지
wiring.cpp: In function 'bool isSubtask4(std::vector<int>, std::vector<int>)':
wiring.cpp:28:65: warning: comparison of integer expressions of different signedness: 'const int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
28 | return min(r[0],b[0])==1 && max(r[r.size()-1],b[b.size()-1])==r.size()+b.size();
| ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~~~~~~~~~~~~~~~~~~
wiring.cpp: In function 'long long int subtask1(std::vector<int>, std::vector<int>)':
wiring.cpp:182:7: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
182 | for(int j=1; j<m; j++)
| ^~~
wiring.cpp:185:2: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
185 | return dp[n-1][m-1];
| ^~~~~~
wiring.cpp: In function 'long long int subtask4(std::vector<int>, std::vector<int>)':
wiring.cpp:93:22: warning: control reaches end of non-void function [-Wreturn-type]
93 | vector<int> a(n+m);
| ^
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