제출 #898340

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
898340		LucaIlie	Festivals in JOI Kingdom 2 (JOI23_festival2)	C++17	0 / 100	2 ms	860 KiB

festival2

#include <bits/stdc++.h>

using namespace std;

const int MAX_N = 20000;
const int MAX_FACT = 3 * MAX_N;
int mod;
int fact[MAX_FACT + 1], invFact[MAX_FACT + 1], countB[MAX_N + 1], countBU[MAX_N + 1];

int lgPut( int x, int n ) {
    if ( n == 0 )
        return 1;

    int p = lgPut( x, n / 2 );
    p = (long long)p * p % mod;
    if ( n % 2 == 1 )
        p = (long long)p * x % mod;

    return p;
}

void initFact( int n ) {
    fact[0] = 1;
    for ( int i = 1; i <= n; i++ )
        fact[i] = (long long)fact[i - 1] * i % mod;
    invFact[n] = lgPut( fact[n], mod - 2 );
    for ( int i = n - 1; i >= 0; i-- )
        invFact[i] = (long long)invFact[i + 1] * (i + 1) % mod;
}

int comb( int n, int k ) {
    return (long long)fact[n] * invFact[n - k] % mod * invFact[k] % mod;
}

int prodCons( int x, int k ) {
    if ( x < 0 )
        return 1;
    if ( x == 0 )
        return fact[x + k - 1];
    return (long long)fact[x + k - 1] * invFact[x - 1] % mod;
}

int main() {
    int n;

    cin >> n >> mod;

    initFact( MAX_FACT );

    countB[1] = 0, countBU[1] = 1;
    countB[2] = 1, countBU[2] = 1;
    for ( int i = 3; i <= n; i++ ) {
        for ( int k = 0; i - k - 1 >= 1; k++ ) {
            //B<--B
            countB[i] = (countB[i] + (long long)countB[i - k - 2] * comb( k + 2, 2 ) % mod * prodCons( 2 * (i - k - 2) - 2, k ) % mod) % mod * 2 % mod;
            //B<--BU
            countB[i] = (countB[i] + (long long)countBU[i - k - 2] * (k + 1) % mod * prodCons( 2 * (i - k - 2) - 1, k ) % mod) % mod;

            if ( i - k - 2 >= 1 ) {
                //BU<--B
                countBU[i] = (countBU[i] + (long long)countB[i - k - 1] * (k + 1) % mod * prodCons( 2 * (i - k - 1) - 2, k ) % mod) % mod;
                //BU<--BU
                countBU[i] = (countBU[i] + (long long)countBU[i - k - 1] * prodCons( 2 * (i - k - 1) - 1, k ) % mod) % mod;
            }
        }
    }

    int tot = 1;
    for ( int i = 3; i < 2 * n; i += 2 )
        tot = (long long)tot * i % mod;
    for ( int i = 1; i <= n; i++ ) {
        int k = n - i;
        tot = (tot - (long long)countB[i] * (k + 1) % mod * prodCons( 2 * i - 2, k ) % mod + mod) % mod;
        tot = (tot - (long long)countBU[i] * prodCons( 2 * i - 1, k ) % mod + mod) % mod;
    }

    cout << tot;

    return 0;
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 5
• Subtask 3: 0 / 27
• Subtask 4: 0 / 14
• Subtask 5: 0 / 36
• Subtask 6: 0 / 13