이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define problem "test"
#define ll long long
#define pii pair<int,int>
#define pll pair<ll,ll>
#define fi first
#define se second
#define ALL(v) (v).begin(),(v).end()
#define UNIQUE(v) (v).resize(unique(ALL(v)) - (v).begin())
#define BIT(x,i) (((x) >> (i)) & 1)
#define MASK(i) (1LL << (i))
using namespace std;
const int N = 2000;
struct State{
ll c,f,v;
State (ll _c = 0,ll _f = 0,ll _v = 0){
c = _c, f = _f, v = _v;
}
void input(){
cin>>c>>f>>v;
}
bool operator < (const State &other) const{
return f > other.f;
}
};
int n,m;
State cpt[N + 5],person[N + 5];
ll maxCore;
namespace subtask3{
const int nMax = 2000;
ll dp[nMax + 5][nMax + 5],oo;
void process(){
memset(dp,-0x3f,sizeof(dp));
oo = dp[0][0];
dp[0][0] = 0;
for (int i=0;i<= nMax;i++ )
dp[i][0] = dp[0][i] = 0;
for (int i=1;i<= n;i++ )
for (int j=1;j<= m;j++ ){
dp[i][j] = max({dp[i][j - 1],dp[i - 1][j],dp[i - 1][j - 1]});
if (cpt[i].f >= person[j].f)
dp[i][j] = max(dp[i][j],dp[i - 1][j - 1] + person[j].v - cpt[i].v);
}
cout<<dp[n][m];
}
}
int main(){
ios_base :: sync_with_stdio(false);
cin.tie(NULL); cout.tie(NULL);
// freopen(problem".inp","r",stdin);
// freopen(problem".out","w",stdout);
cin>>n;
for (int i=1;i<= n;i++ ){
cpt[i].input();
maxCore = max(maxCore,cpt[i].c);
}
cin>>m;
for (int i=1;i<= m;i++ ){
person[i].input();
maxCore = max(maxCore,person[i].c);
}
sort(cpt + 1,cpt + n + 1);
sort(person + 1,person + m + 1);
// if (maxCore == 1)
subtask3 :: process();
}
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