// Success consists of going from failure to failure without loss of enthusiasm
#include <bits/stdc++.h>
using namespace std;
#define nl '\n'
using ll = long long;
template<class T> using V = vector<T>;
using vi = V<int>;
using vl = V<ll>;
int main() {
cin.tie(0)->sync_with_stdio(0);
int N; cin >> N;
vl A(N), B(N); for(int i = 0; i < N; i++) cin >> A[i] >> B[i];
for(int t = 0; t < 300; t++) {
// move all not used money (it halfs each time hence i only need to repeat ~60 times)
for(int x = 0; x < N; x++) {
ll amt = (max(0LL, A[x] - B[x]) / 2) * 2;
// cout << x << " " << amt << nl;
A[x] -= amt;
A[(x + 1) % N] += amt / 2;
}
}
cout << (A == B ? "Yes" : "No") << nl;
exit(0-0);
}
