Submission #89464

#	Time	Username	Problem	Language	Result	Execution time	Memory
89464		updown1	Sailing Race (CEOI12_race)	C++17	40 / 100	279 ms	9844 KiB

race

/*
dp[node 1][node 2][0/1] = max edges in the range starting at node 1/2 (based on the third dimension)
*/
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define For(i, a, b) for(int i=a; i<b; i++)
#define ffi For(i, 0, N)
#define ffj For(j, 0, N)
#define ffa ffi ffj
#define s <<" "<<
#define c <<" : "<<
#define w cout
#define e endl//"\n"
#define pb push_back
#define mp make_pair
#define a first
#define b second
#define int ll
const int MAXN=500, INF=1000000000000000000;
///500,000,000
int N, K, dp[MAXN][MAXN][2], out, loc;
vector<int> adj[MAXN];

bool in (int x, int y, int z) {
    if (y < z) return y < x && x < z;
    return x > y || x < z;
}

int solve(int n1, int n2, int at) {
    if (dp[n1][n2][at] != -1) return dp[n1][n2][at];
    dp[n1][n2][at] = 0;
    //w<< n1 s n2 s at<<e;
    /// range is n1+1 to n2-1  (n1+1)%N to (n2-1+N)%N
    if ((n1+1)%N == n2) {dp[n1][n2][at] = 0; return dp[n1][n2][at];}
    if (at == 0) {
        /// at n1
        for (int i: adj[n1]) if (in(i, n1, n2)) {
            dp[n1][n2][0] = max(dp[n1][n2][0], max(solve(n1, i, 1), solve(i, n2, 0))+1);
        }
        return dp[n1][n2][0];
    }
    /// at n2
    for (int i: adj[n2]) if (in(i, n1, n2)) {
        dp[n1][n2][1] = max(dp[n1][n2][1], max(solve(i, n2, 0), solve(n1, i, 1))+1);
    }
    return dp[n1][n2][1];
}

main() {
    //ifstream cin("test.in");
	ios_base::sync_with_stdio(0); cin.tie(0);
	cin >> N >> K;
	ffi {int a; cin >> a; while (a != 0) {adj[i].pb(a-1); cin >> a;}}
	ffa dp[i][j][0] = dp[i][j][1] = -1;
	ffi solve(i, i, 0);
	if (K == 0) ffi{
        if (dp[i][i][0] > out) {out = dp[i][i][0]; loc = i+1;}
	}
	else {
        assert(false);
	}
	//ffa w<< i+1 s j+1 c solve(i, j, 0) s solve(i, j, 1)<<e;
	w<< out s loc<<e;
}

Compilation message (stderr)

race.cpp:50:6: warning: ISO C++ forbids declaration of 'main' with no type [-Wreturn-type]
 main() {
      ^

• Subtask 1: 40 / 100