이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "bits/stdc++.h"
using namespace std;
#define FOR(i, a, b) for (int i = (a); i < (b); i++)
#define F0R(i, a) FOR(i, 0, a)
#define ROF(i, a, b) for (int i = (b)-1; i >= (a); i--)
#define R0F(i, a) ROF(i, 0, a)
#define ar array
#define all(v) (v).begin(), (v).end()
#define sz(v) static_cast<int>(v.size())
typedef vector<int> vi;
typedef long long ll;
const int N = 5e5, N_ = 1 << 19, MD = 1e9 + 7;
struct ST {
ar<int, 26> t[N_ * 2];
bool on[N_ * 2];
void bld(int k, int l, int r) {
fill(all(t[k]), 0);
on[k] = 1;
if (l < r) {
int m = (l + r) / 2;
bld(k << 1 | 0, l, m), bld(k << 1 | 1, m + 1, r);
}
}
void upd(int k, int l, int r, int i, ar<int, 26>& x) {
F0R(c, 26)
t[k][c] = (t[k][c] + x[c]) % MD;
if (l < r) {
int m = (l + r) / 2;
if (i <= m)
upd(k << 1 | 0, l, m, i, x);
else
upd(k << 1 | 1, m + 1, r, i, x);
}
}
void clr(int k, int l, int r, int ql, int qr) {
if (!on[k] || ql > r || qr < l) return;
if (ql <= l && qr >= r) {
if (l < r) {
int m = (l + r) / 2;
clr(k << 1 | 0, l, m, ql, qr);
clr(k << 1 | 1, m + 1, r, ql, qr);
}
fill(all(t[k]), 0);
on[k] = 0;
return;
}
int m = (l + r) / 2;
clr(k << 1 | 0, l, m, ql, qr);
clr(k << 1 | 1, m + 1, r, ql, qr);
F0R(c, 26) t[k][c] = (t[k << 1 | 0][c] + t[k << 1 | 1][c]) % MD;
}
ar<int, 26>& root() { return t[1]; }
} t1, t2;
int32_t main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
cin.exceptions(cin.failbit);
int n, m;
cin >> n >> m;
static vi v1[N], v2[N];
F0R(h, m) {
int l, r;
cin >> l >> r, l--, r--;
if (l < r)
v1[l].push_back(r); // s_i > s_{i+1}
else
v2[r].push_back(l); // s_i < s_{i+1}
}
t1.bld(1, 0, n - 1);
t2.bld(1, 0, n - 1);
ar<int, 26> dp;
R0F(i, n) {
if (i == n - 1)
fill(all(dp), 1);
else {
for (int j : v1[i]) t1.clr(1, 0, n - 1, i + 1, j);
for (int j : v2[i]) t2.clr(1, 0, n - 1, i + 1, j);
F0R(c, 26) {
dp[c] = 1;
FOR(b, 0, c) dp[c] = (dp[c] + t1.root()[b]) % MD;
FOR(b, c + 1, 26) dp[c] = (dp[c] + t2.root()[b]) % MD;
}
}
t1.upd(1, 0, n - 1, i, dp);
t2.upd(1, 0, n - 1, i, dp);
}
int ans = 0;
F0R(c, 26) ans = (ans + dp[c]) % MD;
cout << ans << '\n';
}
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