# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
893041 | 2023-12-26T11:50:56 Z | vjudge1 | Sprinkler (JOI22_sprinkler) | C++17 | 931 ms | 107832 KB |
#include <bits/stdc++.h> #define ff first #define ss second #define pb push_back #define all(x) x.begin(),x.end() #define rall(x) x.rbegin(),x.rend() #define int long long #define rnd(l, r) uniform_int_distribution<int>(l, r)(rng) using namespace std; void fp(string name){freopen((name+".in").c_str(),"r",stdin); freopen((name+".out").c_str(),"w",stdout);} int pow(int a,int b,int m){int ans=1;while(b){if(b&1){ans=(ans*a)%m;}b>>=1;a=(a*a)%m;}return ans;} int binpow(int a,int b){int ans=1;while(b){if(b&1){ans=(ans*a);}b>>=1;a=(a*a);}return ans;} mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const int N = 2e5 + 10, inf = 1e9; vector <int> g[N]; int cost[N]; int h[N][50]; int par[N]; void dfs(int v, int p){ par[v] = p; for(auto to : g[v]){ if(to == p)continue; dfs(to, v); } } main(){ iostream::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); int n, l; cin >> n >> l; for(int i = 0; i < n - 1; i ++){ int a, b; cin >> a >> b; g[a].pb(b); g[b].pb(a); } for(int i = 1; i <= n; i++){ cin >> cost[i]; for(int j = 0; j <= 45; j++){ h[i][j] = 1; } } int q; cin >> q; dfs(1, 1); while(q--){ int tp; cin >> tp; if(tp == 1){ int x, d, w; cin >> x >> d >> w; h[x][d] = (h[x][d] * w) % l; x = par[x]; d--; while(d >= 0){ h[x][d] =( h[x][d] * w) % l; h[x][d + 1] = (h[x][d + 1] * w) % l; if(x == par[x]){ d--; break; } x = par[x]; d--; } while(d >= 0){ h[x][d] =( h[x][d] * w) % l; d--; } }else{ int x; cin >> x; int res = cost[x]; for(int i = 0; i <= 45; i++){ res *= h[x][i]; res %= l; if(x == par[x])break; x = par[x]; } cout << res % l<< endl; } } } /* * Before implementing the problem: Do I understand the problem correctly? Which places are tricky? What do I need to remember to implement them correctly? Which place is the heaviest by implementation? Can I do it simpler? Which place is the slowest? Where do I need to be careful about constant factors and where I can choose slower but simpler implementation? ---------------------------------- If not AC: Did you remember to do everything to handle the tricky places you thought about before? Is the solution correct? Do I understand the problem correctly? ---------------------------------- If you have a test on which the solution gives wrong answer: Is the solution doing what it was supposed to do? Is the problem in the code or in the idea? */
Compilation message
# | 결과 | 실행 시간 | 메모리 | Grader output |
---|---|---|---|---|
1 | Correct | 2 ms | 10332 KB | Output is correct |
2 | Incorrect | 2 ms | 10332 KB | Output isn't correct |
3 | Halted | 0 ms | 0 KB | - |
# | 결과 | 실행 시간 | 메모리 | Grader output |
---|---|---|---|---|
1 | Incorrect | 2 ms | 10332 KB | Output isn't correct |
2 | Halted | 0 ms | 0 KB | - |
# | 결과 | 실행 시간 | 메모리 | Grader output |
---|---|---|---|---|
1 | Incorrect | 2 ms | 10332 KB | Output isn't correct |
2 | Halted | 0 ms | 0 KB | - |
# | 결과 | 실행 시간 | 메모리 | Grader output |
---|---|---|---|---|
1 | Incorrect | 2 ms | 10328 KB | Output isn't correct |
2 | Halted | 0 ms | 0 KB | - |
# | 결과 | 실행 시간 | 메모리 | Grader output |
---|---|---|---|---|
1 | Correct | 2 ms | 10332 KB | Output is correct |
2 | Incorrect | 931 ms | 107832 KB | Output isn't correct |
3 | Halted | 0 ms | 0 KB | - |
# | 결과 | 실행 시간 | 메모리 | Grader output |
---|---|---|---|---|
1 | Correct | 2 ms | 10332 KB | Output is correct |
2 | Incorrect | 2 ms | 10332 KB | Output isn't correct |
3 | Halted | 0 ms | 0 KB | - |