Submission #892387

#	Time	Username	Problem	Language	Result	Execution time	Memory
892387		quochuy147	Financial Report (JOI21_financial)	C++14	17 / 100	84 ms	33320 KiB

Main

#include <bits/stdc++.h>

using namespace std;

#define fi first
#define se second
#define ll long long
#define mp make_pair
#define pb push_back
#define pii pair<int, int>
#define pll pair<ll, ll>
#define MASK(i) (1LL << (i))
#define BIT(x, i) (((x) >> (i)) & 1)
#define all(x) (x).begin() , (x).end()
#define TIME  (1.0 * clock() / CLOCKS_PER_SEC)
#define file "name"
template <typename T1, typename T2> bool minimize(T1 &a, T2 b){if (a > b) {a = b; return true;} return false;}
template <typename T1, typename T2> bool maximize(T1 &a, T2 b){if (a < b) {a = b; return true;} return false;}

const int inf = 1e9 + 5;
const ll linf = 1e17;
const int mod = 1e9 + 7;
const int N = 3e5 + 5;
const int LOG = 20;

int n, d, res;
int a[N], f[N];
int rmq[N][LOG + 5], lg[N];

void inp()
{
    cin >> n >> d;
    for(int i = 1; i <= n; ++i) cin >> a[i];
}

void prepare() {
        for(int i = 2; i <= n; ++i) lg[i] = lg[i / 2] + 1;

        for(int i = 1; i <= n; ++i) rmq[i][0] = a[i];
        for(int j = 1; j <= LOG; ++j)
            for(int i = 1; i + MASK(j) - 1 <= n; ++i) rmq[i][j] = max(rmq[i][j - 1], rmq[i + MASK(j - 1)][j - 1]);
    }

int get(int l, int r) {
    int k = lg[r - l + 1];
    return max(rmq[l][k], rmq[r - MASK(k) + 1][k]);
}

namespace sub4 {
    void prepare() {
        for(int i = 2; i <= n; ++i) lg[i] = lg[i / 2] + 1;

        for(int i = 1; i <= n; ++i) rmq[i][0] = a[i];
        for(int j = 1; j <= LOG; ++j)
            for(int i = 1; i + MASK(j) - 1 <= n; ++i) rmq[i][j] = max(rmq[i][j - 1], rmq[i + MASK(j - 1)][j - 1]);
    }

    int get(int l, int r) {
        int k = lg[r - l + 1];
        return max(rmq[l][k], rmq[r - MASK(k) + 1][k]);
    }

    void solve() {
        prepare();
        for(int i = n; i >= 1; --i) {
            int l = i + 1, r = n, id = n + 1;
            while(l <= r) {
                int m = (l + r) >> 1;
                if(get(i, m) > a[i]) {
                    id = m;
                    r = m - 1;
                }
                else l = m + 1;
            }
            f[i] = f[id] + 1;
            maximize(res, f[i]);
        }
        cout << res;
    }
}

namespace sub5 {
    int x[N];
    void solve() {
        for(int i = 1; i <= n; ++i) x[i] = inf;
        x[0] = 0;
        for(int i = 1; i <= n; ++i) {
            int l = 1, r = n, id = 0;
            while(l <= r) {
                int m = (l + r) >> 1;
                if(x[m] >= a[i]) {
                    id = m;
                    r = m - 1;
                }
                else l = m + 1;
            }
            x[id] = a[i];
            maximize(res, id);
        }
        cout << res;
    }
}

namespace sub3 {
    void prepare() {
        for(int i = 2; i <= n; ++i) lg[i] = lg[i / 2] + 1;

        for(int i = 1; i <= n; ++i) rmq[i][0] = a[i];
        for(int j = 1; j <= LOG; ++j)
            for(int i = 1; i + MASK(j) - 1 <= n; ++i) rmq[i][j] = min(rmq[i][j - 1], rmq[i + MASK(j - 1)][j - 1]);
    }

    int get(int l, int r) {
        int k = lg[r - l + 1];
        return min(rmq[l][k], rmq[r - MASK(k) + 1][k]);
    }

    void solve() {
        prepare();
        for(int i = 1; i <= n; ++i) {
            f[i] = 1;
            if(a[i] > a[i - 1]) f[i] = f[i - 1] + 1;
            for(int j = 1; j < i - 1; ++j) {
                if(a[j] >= a[i]) continue;
                int l = max(j + 1, i - d), r = min(i - 1, j + d);
                if(l <= r && get(l, r) <= a[j]) maximize(f[i], f[j] + 1);
            }
            maximize(res, f[i]);
        }
        cout << res;
    }
}

void solve()
{
    if(d == 1) return void(sub4::solve());
    if(d == n) return void(sub5::solve());
    if(n <= 7000) return void(sub3::solve());
}

int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0);
//	freopen(file".inp" , "r" , stdin);
//	freopen(file".out" , "w" , stdout);
    inp();
    solve();
    return 0;
}

• Subtask 1: 0 / 14
• Subtask 2: 0 / 14
• Subtask 3: 0 / 20
• Subtask 4: 12 / 12
• Subtask 5: 5 / 5
• Subtask 6: 0 / 35