제출 #892178

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
892178		Peter2017	Financial Report (JOI21_financial)	C++14	65 / 100	646 ms	198336 KiB

Main

#include <bits/stdc++.h>
#define fi first
#define se second
#define ll long long
#define pii pair<int,int>
#define pll pair<ll,ll>
#define pill pair<int,ll>
#define mem(a, b) memset(a, b, sizeof(a))
#define MASK(i) (1LL << (i))
#define BIT(x, i) (((x) >> (i)) & 1)
#define name "test"

using namespace std;

const int N = 3e5 + 5;
const int mod = 1e9 + 7;
const ll oo = 1e18 + 69;

template <typename T1, typename T2> bool maxi(T1 &a, T2 b){if (a < b){a = b; return 1;} return 0;}
template <typename T1, typename T2> bool mini(T1 &a, T2 b){if (a > b){a = b; return 1;} return 0;}

int n;
int k;
int D;
int a[N];
int f[(int)7e3 + 2][(int)7e3 + 2];
deque <int> dq[(int)7e3 + 2];
vector <int> value;

void load(){
    cin.tie(0)->sync_with_stdio(0);
    if (fopen(name".inp", "r")){
        freopen(name".inp", "r", stdin);
        freopen(name".out", "w", stdout);
    }
}

void input(){
    cin >> n >> D;
    for (int i = 1; i <= n; i++){
        cin >> a[i];
    }
}

void compress(){
    for (int i = 1; i <= n; i++)
        value.push_back(a[i]);
    sort(value.begin(), value.end());
    value.erase(unique(value.begin(), value.end()), value.end());
    for (int i = 1; i <= n; i++)
        a[i] = lower_bound(value.begin(), value.end(), a[i]) - value.begin() + 1;
    k = (int)value.size();
}

namespace subtask3{
    void solve(){
        mem(f, -0x3f);
        for (int i = 1; i <= n; i++){
            f[i][a[i]] = 1;
            for (int j = 1; j <= k; j++){
                if (dq[j].size() && dq[j].front() < i - D) dq[j].pop_front();
                if (dq[j].size()) maxi(f[i][max(a[i], j)], f[dq[j].front()][j] + (j < a[i]));
            }
            for (int j = 1; j <= k; j++){
                while (dq[j].size() && f[dq[j].back()][j] <= f[i][j])
                    dq[j].pop_back();
                dq[j].push_back(i);
            }
        }
        int ans = 0;
        for (int i = 1; i <= k; i++)
            maxi(ans, f[n][i]);
        cout << ans;
    }
}

namespace subtask4{
    stack <int> st;
    void solve(){
        st.push(n);
        int ans = 1;
        for (int i = n - 1; i >= 1; i--){
            while (st.size() && a[st.top()] <= a[i]) st.pop();
            st.push(i);
            maxi(ans, st.size());
        }
        cout << ans;
    }
}

namespace subtask5{
    int b[N];
    void solve(){
        mem(b, 0x3f);
//        f[0] = -mod;
        int ans = 0;
        for (int i = 1; i <= n; i++){
            int id = lower_bound(b + 1, b + n + 1, a[i]) - b;
//            if (i == n) cout << id;
            b[id] = a[i];
            maxi(ans, id);
        }
        cout << ans;
    }
}

int main(){
    load();
    input();
    compress();
    if (n <= (int)7e3){
        subtask3::solve();
        return 0;
    }
    if (D == 1){
        subtask4::solve();
        return 0;
    }
    subtask5::solve();
}

컴파일 시 표준 에러 (stderr) 메시지

Main.cpp: In instantiation of 'bool maxi(T1&, T2) [with T1 = int; T2 = long unsigned int]':
Main.cpp:85:32:   required from here
Main.cpp:19:66: warning: comparison of integer expressions of different signedness: 'int' and 'long unsigned int' [-Wsign-compare]
   19 | template <typename T1, typename T2> bool maxi(T1 &a, T2 b){if (a < b){a = b; return 1;} return 0;}
      |                                                                ~~^~~
Main.cpp: In function 'void load()':
Main.cpp:33:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   33 |         freopen(name".inp", "r", stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
Main.cpp:34:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   34 |         freopen(name".out", "w", stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 14 / 14
• Subtask 2: 14 / 14
• Subtask 3: 20 / 20
• Subtask 4: 12 / 12
• Subtask 5: 5 / 5
• Subtask 6: 0 / 35