제출 #891917

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
891917		aliarapov	Jail (JOI22_jail)	C++17	5 / 100	3173 ms	67148 KiB

jail

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

#define int long long
#define pb push_back
#define ff first
#define ss second
#define all(v) v.begin(), v.end()
#define rall(v) v.rbegin(), v.rend()
#define ordered_set tree<ll, null_type, less<ll>, rb_tree_tag, tree_order_statistics_node_update>
#define ordered_multiset tree<type1, null_type, less_equal<type1>, rb_tree_tag, tree_order_statistics_node_update>;

using namespace std;
using namespace __gnu_pbds;

const int mod = 1e9+7;
const double PI = acos(-1.0);
const double epsilon = 1e-6;
const int N = 1.2e5+5;
vector<int> g[N];
int n;

int sz[N], d[N], h[N], up[20][N];
int top[N], chain[N], tin[N], tout[N], rt, timer, pos[N];

void clean(){
	d[1] = 0;
	for(int i = 0; i < N; i++){
		pos[i] = 0;
		g[i].clear();
		for(int j = 0; j < 20; j++) up[j][i] = 0;
	}
}

struct SegmentTree{
	int tree[N * 4];
	int lazy[N * 4];
	function<int(int,int)> f;
	int type;
	
	SegmentTree(function<int(int,int)> func, int ty){
		f = func;
		type = ty;
	}
	
	void build(const vector<int> &a,int v, int l, int r){
		if(l == r){
			tree[v] = a[l];
			return;
		}
		int mid = (l + r) >> 1;
		build(a,v * 2, l, mid);
		build(a,v * 2 + 1, mid + 1, r);
		tree[v] = f(tree[v * 2], tree[v * 2 + 1]);
	}
	
	void push(int v, int tl, int tr) {
		if (lazy[v] == 0) return;
		if (tl != tr) {
			lazy[v * 2] += lazy[v];
			lazy[v * 2 + 1] += lazy[v];
		}
		tree[v] += lazy[v];
		lazy[v] = 0;
	}
	 
	void update(int l, int r, int x, int v, int tl, int tr) {
		push(v, tl, tr);
		if (l > tr || tl > r) return ;
		if (l <= tl && tr <= r) {
			lazy[v] = x;
			push(v, tl, tr);
			return;
		}
		int tm = (tl + tr) / 2;
		update(l, r, x, v * 2, tl, tm);
		update(l, r, x, v * 2 + 1, tm + 1, tr);
		tree[v] = f(tree[v * 2], tree[v * 2 + 1]);
	}
	 
	int get(int v, int tl, int tr, int l, int r) {
		push(v, tl, tr);
		if (l > tr || tl > r) return type;
		if (l <= tl && tr <= r) return tree[v];
		int tm = (tl + tr) / 2;
		return f(get(v * 2, tl, tm, l, r), get(v * 2 + 1, tm + 1, tr, l, r));
	}
	
	void clean(){
		for(int i = 0; i < N * 4; i++) tree[i] = 0,lazy[i] = 0;
	}
	
	int search(int v,int tl,int tr){
		push(v, tl, tr);
		if(tl == tr){
			return pos[tl];
		}
		int tm = (tl + tr) / 2;
		if(tree[v * 2] + lazy[v * 2] == tree[v]) return search(v*2,tl,tm);
		else return search(v*2+1,tm+1,tr);
	}
};

function<int(int,int)> minm = [](int a,int b){
	return min(a,b);
};

function<int(int,int)> summ = [](int a,int b){
	return a + b;
};

SegmentTree seg(summ,0),T(minm,1e18),quer(summ,0);

void dfs(int u, int p){
    up[0][u] = p;
    for ( int i = 1; i < 20; i++ ){
        up[i][u] = up[i - 1][up[i - 1][u]];
    }
    sz[u] = 1;
    for ( auto &v: g[u] ){
        if ( v != p ){
            d[v] = d[u] + 1;
            dfs(v, u);
            sz[u] += sz[v];
        }
    }
    for ( auto &v: g[u] ){
        if ( v != p ){
            if ( h[u] == -1 || sz[h[u]] < sz[v] ){
                h[u] = v;
            }
        }
    }
}

int lca(int u, int v){
    if ( d[u] < d[v] ) swap(u, v);
    int df = d[u] - d[v];
    for ( int i = 0; i < 20; i++ ){
        if ( df >> i & 1 ){
            u = up[i][u];
        }
    }
    if ( u == v ){
        return u;
    }
    for ( int i = 19; i >= 0; i-- ){
        if ( up[i][u] != up[i][v] ){
            u = up[i][u];
            v = up[i][v];
        }
    }
    return up[0][u];
};

void HLD(int u, int p){
    tin[u] = ++timer;
    pos[timer] = u;
    chain[u] = rt;
    if ( top[rt] == -1 ){
        top[rt] = u;
    }
    if ( h[u] != -1 ) HLD(h[u], u);
    for ( auto &v: g[u] ){
        if ( v != p && h[u] != v ){
            rt++; HLD(v, u);
        }
    }
    tout[u] = timer;
}

void upd(int u,int v,int val){
	if ( d[u] < d[v] ) swap(u, v);
    while ( chain[u] != chain[v] ){
        int nxt = top[chain[u]];
        seg.update(tin[nxt],tin[u],val,1,1,n);
        T.update(tin[nxt],tin[u],val,1,1,n);
        u = up[0][nxt];
    }
    seg.update(tin[v],tin[u],val,1,1,n);
    T.update(tin[v],tin[u],val,1,1,n);
}

void update(int u,int v, int val){
	int lc = lca(u,v);
	upd(u,lc,val); upd(v,lc,val);
    seg.update(tin[lc],tin[lc],-val,1,1,n);
    T.update(tin[lc],tin[lc],-val,1,1,n);
}

int qry(int u,int v){
	if ( d[u] < d[v] ) swap(u, v);
	int res = 0;
    while ( chain[u] != chain[v] ){
        int nxt = top[chain[u]];
        res += quer.get(1,1,n,tin[nxt],tin[u]);
        u = up[0][nxt];
    }
    res += quer.get(1,1,n,tin[v],tin[u]);
    return res;
}

int query(int u,int v){
	int lc = lca(u,v);
	return qry(u,lc) + qry(v,lc);
}

void solve(){
	cin >> n;
	for(int i = 1; i < n; i++){
		int u,v; cin >> u >> v;
		g[u].pb(v); g[v].pb(u);
	}
    int m; cin >> m;
    vector<pair<int,int> > qr(m);
    for(auto &[l,r] : qr) cin >> l >> r;
    quer.clean();
    seg.clean();
    T.clean();
    for(int i = 0; i < N; i++) top[i] = -1, h[i] = -1;
    rt = 0; timer = 0;
    dfs(1,1); HLD(1,1);
    
    vector<int> vec(n+1);
    for(int i = 0; i < m; i++) vec[qr[i].ss] = i;
    
    vector<int> A(n+1,1e9);
    for(auto [u,v] : qr) A[tin[v]] = 0;
    T.build(A,1,1,n);
    
    for(auto [u,v] : qr) quer.update(tin[u],tin[u],1,1,1,n);
    
    for(auto [u,v] : qr) update(u,v,1);
    
    for(int time = 0; time < m; time++){
		if(T.tree[1] != 1){
			cout << "No\n";
			return;
		}
		
		int i = vec[T.search(1,1,n)];
		auto [u,v] = qr[i];
		update(u,v,-1);
		quer.update(tin[u],tin[u],-1,1,1,n);
		if(!(query(u,v) == 0 && seg.get(1,1,n,tin[v],tin[v]) == 0)){
			cout << "No\n";
			return;
		}
		T.update(tin[v],tin[v],1e9,1,1,n);
		
	}
	cout << "Yes\n";
}

main(){
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);

    int tt = 1;
    cin >> tt;
    while (tt--) {
        solve();
        clean();
    }
}

/*
1
8
1 2
2 3
2 4
3 5
3 6
3 7
7 8
4
1 5
4 6
7 3
8 7
*/

컴파일 시 표준 에러 (stderr) 메시지

jail.cpp:256:1: warning: ISO C++ forbids declaration of 'main' with no type [-Wreturn-type]
  256 | main(){
      | ^~~~

• Subtask 1: 5 / 5
• Subtask 2: 0 / 5
• Subtask 3: 0 / 16
• Subtask 4: 0 / 28
• Subtask 5: 0 / 12
• Subtask 6: 0 / 11
• Subtask 7: 0 / 23