제출 #891867

#제출 시각아이디문제언어결과실행 시간메모리
8918678e7앨리스, 밥, 서킷 (APIO23_abc)C++17
24 / 100
49 ms7796 KiB
#include "abc.h" #include <bits/stdc++.h> using namespace std; void debug(){cerr << endl;} template<class T, class ... U> void debug(T a, U ... b){cerr << a << " ", debug(b...);} template<class T> void pary(T l, T r) { while (l != r) cerr << *l << " ", l++; cerr << endl; } #define ll long long #define pii pair<int, int> #define ff first #define ss second // you may find the definitions useful const int OP_ZERO = 0; // f(OP_ZERO, x0, x1) = 0 const int OP_NOR = 1; // f(OP_NOR, x0, x1) = !(x0 || x1) const int OP_GREATER = 2; // f(OP_GREATER, x0, x1) = (x0 > x1) const int OP_NOT_X1 = 3; // f(OP_NOT_X1, x0, x1) = !x1 const int OP_LESS = 4; // f(OP_LESS, x0, x1) = (x0 < x1) const int OP_NOT_X0 = 5; // f(OP_NOT_X0, x0, x1) = !x0 const int OP_XOR = 6; // f(OP_XOR, x0, x1) = (x0 ^ x1) const int OP_NAND = 7; // f(OP_NAND, x0, x1) = !(x0 && x1) const int OP_AND = 8; // f(OP_AND, x0, x1) = (x0 && x1) const int OP_EQUAL = 9; // f(OP_EQUAL, x0, x1) = (x0 == x1) const int OP_X0 = 10; // f(OP_X0, x0, x1) = x0 const int OP_GEQ = 11; // f(OP_GEQ, x0, x1) = (x0 >= x1) const int OP_X1 = 12; // f(OP_X1, x0, x1) = x1 const int OP_LEQ = 13; // f(OP_LEQ, x0, x1) = (x0 <= x1) const int OP_OR = 14; // f(OP_OR, x0, x1) = (x0 || x1) const int OP_ONE = 15; // f(OP_ONE, x0, x1) = 1 const int NUM_LEN = 16; // Alice int // returns la alice( /* in */ const int n, /* in */ const char names[][5], /* in */ const unsigned short numbers[], /* out */ bool outputs_alice[] ) { vector<pair<string, int> > a(n); for (int i = 0;i < n;i++) { a[i].ff = names[i]; a[i].ss = i; } sort(a.begin(), a.end()); int ind = 0; for (int i = 0;i < n;i++) { for (int j = 0;j < NUM_LEN;j++) { outputs_alice[ind++] = (numbers[i]>>j)&1; } } for (int i = 0;i < n;i++) { for (int j = 0;j < n;j++) { if (a[i].ss == j) outputs_alice[ind++] = 1; else outputs_alice[ind++] = 0; } } return ind; } // Bob int // returns lb bob( /* in */ const int m, /* in */ const char senders[][5], /* in */ const char recipients[][5], /* out */ bool outputs_bob[] ) { vector<string> names; for (int i = 0;i < m;i++) { names.push_back(senders[i]); names.push_back(recipients[i]); } sort(names.begin(), names.end()); names.resize(int(unique(names.begin(), names.end()) - names.begin())); int n = names.size(); for (int i = 0;i < n*n;i++) outputs_bob[i] = 0; for (int i = 0;i < m;i++) { int x = lower_bound(names.begin(), names.end(), senders[i]) - names.begin(); int y = lower_bound(names.begin(), names.end(), recipients[i]) - names.begin(); outputs_bob[x*n+y] = 1; } return n*n; } // Circuit int // returns l circuit( /* in */ const int la, /* in */ const int lb, /* out */ int operations[], /* out */ int operands[][2], /* out */ int outputs_circuit[][16] ) { int cur_op = la+lb; int n = sqrt(lb); if (la == 0) return cur_op; auto op = [&] (int type, int a, int b) { operations[cur_op] = type; operands[cur_op][0] = a; operands[cur_op][1] = b; return cur_op++; }; auto mask = [&] (int a, int s) { int ret = cur_op; for (int i = 0;i < NUM_LEN;i++) op(OP_AND, a+i, s); return ret; }; int zero = cur_op; for (int i = 0;i < NUM_LEN;i++) op(OP_ZERO, 0, 0); auto add = [&] (int x, int y) { //adds x and y (size NUM_LEN) vector<int> cins = {zero}; vector<int> gs; for (int i = 0;i < NUM_LEN;i++) { int g1 = op(OP_XOR, x+i, y+i); int c1 = op(OP_AND, x+i, y+i); int c2 = op(OP_AND, cins.back(), g1); if (i < NUM_LEN-1) cins.push_back(op(OP_OR, c1, c2)); gs.push_back(g1); } int ret = cur_op; for (int i = 0;i < NUM_LEN;i++) op(OP_XOR, cins[i], gs[i]); return ret; }; vector<int> ans(n, zero), nums(n); int grid_a = n*NUM_LEN, grid_b = la; for (int i = 0;i < n;i++) nums[i] = i*NUM_LEN; for (int i = 0;i < n;i++) { //send for (int j = 0;j < n;j++) { //rec int val = mask(nums[i], grid_b + i*n+j); ans[j] = add(ans[j], val); } } //permute ans vector<int> out(n, zero); for (int i = 0;i < n;i++) { for (int j = 0;j < n;j++) { int val = mask(ans[i], grid_a + i*n+j); int upd = cur_op; for (int k = 0;k < NUM_LEN;k++) op(OP_OR, out[j]+k, val+k); out[j] = upd; } } for (int i = 0;i < n;i++) { for (int j = 0;j < 16;j++) outputs_circuit[i][j] = out[i]+j; } return cur_op; }
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