제출 #89141

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
89141		SpeedOfMagic	Global Warming (CEOI18_glo)	C++17	58 / 100	881 ms	263168 KiB

glo

/** MIT License Copyright (c) 2018 Vasilyev Daniil **/
#include <bits/stdc++.h>
using namespace std;
template<typename T> using v = vector<T>;
typedef long long longlong;
#define int longlong
typedef long double ld;
typedef string str;
typedef vector<int> vint;
#define rep(a, l, r) for(int a = (l); a < (r); a++)
#define pb push_back
#define fs first
#define sc second
#define sz(a) ((int) a.size())
const long long inf = 4611686018427387903; //2^62 - 1
#if 0  //FileIO
const string fileName = "";
ifstream fin ((fileName == "" ? "input.txt"  : fileName + ".in" ));
ofstream fout((fileName == "" ? "output.txt" : fileName + ".out"));
#define get fin>>
#define put fout<<
#else
#define get cin>>
#define put cout<<
#endif
#define eol put endl
void read() {} template<typename Arg,typename... Args> void read (Arg& arg,Args&... args){get (arg)     ;read(args...) ;}
void print(){} template<typename Arg,typename... Args> void print(Arg  arg,Args...  args){put (arg)<<" ";print(args...);}
int getInt(){int a; get a; return a;}
//code goes here
inline int lsb(int a) { return a & -a; }

const int N = 262144;
int segTree[N * 2];
void update(int p, int val, int cur = 1, int ll = 1, int rr = N) {
    if (ll == rr) {
        segTree[cur] = max(segTree[cur], val);
        return;
    }
    int mid = (ll + rr) / 2;
    if (p <= mid)
        update(p, val, cur * 2, ll, mid);
    else
        update(p, val, cur * 2 + 1, mid + 1, rr);
    segTree[cur] = max(segTree[cur * 2], segTree[cur * 2 + 1]);
}

int query(int l, int r, int cur = 1, int ll = 1, int rr = N) {
    if (l > r)
        return 0;
    else if (l == ll && r == rr)
        return segTree[cur];
    else {
        int mid = (ll + rr) / 2;
        int res = max(query(l, min(r, mid), cur * 2, ll, mid),
                      query(max(l, mid + 1), r, cur * 2 + 1, mid + 1, rr));
        return res;
    }
}

void run() {
    memset(segTree, 0, sizeof segTree);
    int n, k;
    read(n, k);
    int a[n];
    set<int> d;
    rep(i, 0, n) {
        get a[i];
        d.insert(a[i]);
        d.insert(a[i] - k);
    }
    map<int, int> inv;
    int p = 2;
    for (int j : d)
        inv[j] = p++;

    int v[n];
    rep(i, 0, n)
        v[i] = inf;
    int dp[n][2];
    rep(i, 0, n) {
        dp[i][0] = (lower_bound(v, v + n, a[i]) - v) + 1;
        v[dp[i][0] - 1] = a[i];
        dp[i][1] = query(1, inv[a[i]] - 1) + 1;
        update(inv[a[i] - k], dp[i][0]);
        update(inv[a[i]], dp[i][1]);
    }
    int ans = 0;
    rep(i, 0, n)
        ans = max(ans, dp[i][1]);
    put ans;
}
signed main() {srand(time(0)); ios::sync_with_stdio(0); cin.tie(0); put fixed << setprecision(12); run(); return 0;}

• Subtask 1: 5 / 5
• Subtask 2: 10 / 10
• Subtask 3: 13 / 13
• Subtask 4: 10 / 10
• Subtask 5: 20 / 20
• Subtask 6: 0 / 17
• Subtask 7: 0 / 25