Submission #891340

#	Time	Username	Problem	Language	Result	Execution time	Memory
891340		iskhakkutbilim	Council (JOI23_council)	C++17	100 / 100	2707 ms	58408 KiB

council

#include <bits/stdc++.h>
using namespace std;

#define ff first
#define ss second
#define all(a) a.begin(), a.end()
const int N = 3e5;

signed main(){
	ios::sync_with_stdio(0);
	cin.tie(0); cout.tie(0);
	int n, m; cin >> n >> m;
	int a[n][m];
	pair<int, int> dp[2][1024][1024];
	for(int i = 0;i < n; i++){
		for(int j = 0;j < m; j++){
			cin >> a[i][j];
		}
	}
	vector<int> cnt(m,0);
	vector<int> bits(n, 0);
	int bpc[1<<20];
	
	for(int i = 0;i < 1<<20; i++){
		bpc[i] = __builtin_popcount(i);
	}
	for(int i = 0;i < 2; i++){
		for(int j = 0;j < 1024; j++){
			for(int k = 0;k < 1024; k++){
				dp[i][j][k] = {-1, -1};
			}
		}
	}
	for(int i = 0;i < n; i++){
		for(int j = 0;j < m; j++){
			bits[i]+= (a[i][j] << j);
			cnt[j]+= a[i][j];
		}
		int m0  = bits[i] & 1023;
		int m1 = bits[i]>>10;		
		for(int j = 0;j < 1024; j++){
			int c = bpc[m1 & j];
			if(dp[0][m0][j].ff == -1){
				dp[0][m0][j] = {c, i};
			}else{
				if(dp[0][m0][j].ff >= c){
					dp[1][m0][j] = dp[0][m0][j];
					dp[0][m0][j] = {c, i};
				}else if(dp[1][m0][j].ff == -1 || dp[1][m0][j].ff >= c){
					dp[1][m0][j] = {c, i};
				}
			}
		}
		
	}
	
	for(int i = 0;i < n; i++){
		int mask = 0, bc = 0;
		for(int j = 0;j < m; j++){
			if(bits[i] & (1<<j)){
				if(cnt[j] == n/2 + 1){
					bc++;
					mask+= (1<<j);
				}else if(cnt[j] > n/2+1){
					bc++;
				}
			}else{
				if(cnt[j] > n / 2) bc++;
				else if(cnt[j] == n / 2){
					mask+= (1<<j);
					bc++;
				}
			}
		}
		int mn = m;
		int m0 = mask & 1023;
		int m1 = mask >> 10;
		for(int j = 0;j < 1024; j++){
			int c = bpc[m0 & j];
			if(dp[0][j][m1].ff == -1) continue;
			int kek = 20;
			if(dp[0][j][m1].ss != i && dp[0][j][m1].ss != -1){
				kek = min(kek, dp[0][j][m1].ff);
			}
			else if(dp[1][j][m1].ss != i && dp[1][j][m1].ss != -1){
				kek = min(kek, dp[1][j][m1].ff);
			}
			mn = min(mn, kek + c);
		}
		cout << bc-mn << '\n';
	}
	
	return 0;
}

• Subtask 1: 8 / 8
• Subtask 2: 8 / 8
• Subtask 3: 6 / 6
• Subtask 4: 19 / 19
• Subtask 5: 15 / 15
• Subtask 6: 22 / 22
• Subtask 7: 22 / 22