이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/// dwuy: _,\,,,_\,__,\,,_
#include <bits/stdc++.h>
#define fastIO ios_base::sync_with_stdio(false); cin.tie(NULL)
#define file(a) freopen(a".inp","r",stdin); freopen(a".out", "w",stdout)
#define fi first
#define se second
#define endl "\n"
#define len(s) int32_t(s.length())
#define MASK(k)(1LL<<(k))
#define TASK ""
#define int long long
using namespace std;
typedef tuple<int, int, int> tpiii;
typedef pair<double, double> pdd;
typedef pair<int, int> pii;
typedef long long ll;
const long long OO = 1e18;
const int MOD1 = 998244353;
const int MOD2 = 1e9 + 7;
const int INF = 1e9;
const int MX = 200005;
const int base = 307;
int n;
int pf1[MX];
int pf2[MX];
int bp1[MX];
int bp2[MX];
string s;
void nhap(){
cin >> n;
cin >> s;
if(!(n&1)){
cout << "NOT POSSIBLE";
exit(0);
}
}
int add1(int a, int b){
a += b;
return a + (a>=MOD1? -MOD1 : a<0? MOD1 : 0);
}
int mul1(int a, int b){
return a*b%MOD1;
}
int add2(int a, int b){
a += b;
return a + (a>=MOD2? -MOD2 : a<0? MOD2 : 0);
}
int mul2(int a, int b){
return a*b%MOD2;
}
int get1(int l, int r){
return add1(pf1[r], -mul1(pf1[l-1], bp1[r-l+1]));
}
int get2(int l, int r){
return add2(pf2[r], -mul2(pf2[l-1], bp2[r-l+1]));
}
void solve(){
s = ' ' + s;
bp1[0] = bp2[0] = 1;
for(int i=1; i<=n; i++){
bp1[i] = mul1(bp1[i-1], base);
bp2[i] = mul2(bp2[i-1], base);
}
for(int i=1; i<=n; i++){
pf1[i] = add1(mul1(pf1[i-1], base), s[i]);
pf2[i] = add2(mul2(pf2[i-1], base), s[i]);
}
int flag = -1;
int mid = (n+1)>>1;
bool isUnique = 1;
pii p = {-1, -1};
pii pre = {get1(1, mid-1), get2(1, mid-1)};
pii suf = {get1(mid+1, n), get2(mid+1, n)};
for(int i=1; i<=mid; i++){
int cur1 = add1(mul1(get1(1, i-1), bp1[mid-i]), get1(i+1, mid));
int cur2 = add2(mul2(get2(1, i-1), bp2[mid-i]), get2(i+1, mid));
pii cur = {cur1, cur2};
if(cur == suf){
flag = 0;
if(p.fi < 0) p = cur;
if(p != cur) isUnique = 0;
}
}
for(int i=mid+1; i<=n; i++){
int cur1 = add1(mul1(get1(mid, i-1), bp1[n-i]), get1(i+1, n));
int cur2 = add2(mul2(get2(mid, i-1), bp2[n-i]), get2(i+1, n));
pii cur = {cur1, cur2};
if(cur == pre){
flag = 1;
if(p.fi < 0) p = cur;
if(p != cur) isUnique = 0;
}
}
if(flag == -1) cout << "NOT POSSIBLE", exit(0);
if(!isUnique) cout << "NOT UNIQUE", exit(0);
if(!flag) for(int i=mid+1; i<=n; i++) cout << s[i];
else for(int i=1; i<mid; i++) cout << s[i];
}
int32_t main(){
fastIO;
//file(TASK);
nhap();
solve();
return 0;
}
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