oj.uz

답안 #889095

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
889095 2023-12-18T20:21:02 Z aykhn 벽 (IOI14_wall) C++17
0 / 100
 1 ms 2396 KB 
#include "wall.h"
#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx,avx2,fma")
 
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
 
/* DEFINES */
#define S second
#define F first
#define ll long long
#define ull unsigned long long
#define ld long double
#define npos ULLONG_MAX
#define INF LLONG_MAX
#define vv(a) vector<a>
#define pp(a, b) pair<a, b>
#define pq(a) priority_queue<a>
#define qq(a) queue<a>
#define ss(a) set<a>
#define mm(a, b) map<a, b>
#define ump(a, b) unordered_map<a, b>
#define ANDROID                   \
    ios_base::sync_with_stdio(0); \
    cin.tie(0);                   \
    cout.tie(0);
#define elif else if
#define endl "\n"
#define allc(a) begin(a), end(a)
#define all(a) a, a + sizeof(a) / sizeof(a[0])
#define pb push_back
#define logi(a) __lg(a)
#define sqrt(a) sqrtl(a)
#define mpr make_pair
#define ins insert
using namespace std;
using namespace __gnu_pbds;
using namespace __cxx11;
typedef char chr;
typedef basic_string<chr> str;
template <typename T, typename key = less<T>>
using ordered_set = tree<T, null_type, key, rb_tree_tag, tree_order_statistics_node_update>;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const ll N = 2e6 + 5;
pp(ll, ll) lazy[N << 2], ans[N];
void push(ll v)
{
    if (lazy[v] == mpr(0ll, (ll)1e9))
        return;
    if (lazy[v].F > lazy[v << 1].S)
        lazy[v << 1] = {lazy[v].F, lazy[v].F};
    elif (lazy[v].S < lazy[v << 1].F)
        lazy[v << 1] = {lazy[v].S, lazy[v].S};
    else
        lazy[v << 1].F = max(lazy[v].F, lazy[v << 1].F), lazy[v << 1].S = min(lazy[v << 1].S, lazy[v].S);
    if (lazy[v].F > lazy[v << 1 | 1].S)
        lazy[v << 1 | 1] = {lazy[v].F, lazy[v].F};
    elif (lazy[v].S < lazy[v << 1 | 1].F)
        lazy[v << 1 | 1] = {lazy[v].S, lazy[v].S};
    else
        lazy[v << 1 | 1].F = max(lazy[v].F, lazy[v << 1 | 1].F), lazy[v << 1 | 1].S = min(lazy[v << 1 | 1].S, lazy[v].S);
    lazy[v] = {0ll, (ll)1e9};
}
void modifymin(ll i, ll j, ll val, ll l, ll r, ll v)
{push(v);
    if (max(i, l) > min(j, r))
        return;
    if (i <= l and r <= j)
    {
        // lazy[v].S = min(lazy[v].S, val);
        // if (lazy[v].F > lazy[v].S)
        //     lazy[v].F = lazy[v].S;
        lazy[v] = {(ll)0, val};
        push(v);
        return;
    }
    ll mid = (l + r) >> 1;
    modifymin(i, j, val, l, mid, v << 1);
    modifymin(i, j, val, mid + 1, r, v << 1 | 1);
}
void modifymax(ll i, ll j, ll val, ll l, ll r, ll v)
{push(v);
    if (max(i, l) > min(j, r))
        return;
    if (i <= l and r <= j)
    {
        // lazy[v].F = max(lazy[v].F, val);
        // if (lazy[v].F > lazy[v].S)
        //     lazy[v].S = lazy[v].F;
        lazy[v] = {val, (ll)1e9};
        push(v);
        return;
    }
    ll mid = (l + r) >> 1;
    modifymax(i, j, val, l, mid, v << 1);
    modifymax(i, j, val, mid + 1, r, v << 1 | 1);
}
void build(ll l, ll r, ll v)
{
    if (l == r)
    {
        ans[l] = lazy[v];
        return;
    }
    ll mid = (l + r) >> 1;
    push(v);
    build(l, mid, v << 1);
    build(mid + 1, r, v << 1 | 1);
}
void init(ll l, ll r, ll v)
{
    if (l == r)
    {
        lazy[l] = {0, 0};
        return;
    }
    ll mid = (l + r) >> 1;
    build(l, mid, v << 1);
    build(mid + 1, r, v << 1 | 1);
}
void buildWall(int n, int k, int op[], int left[], int right[], int height[], int finalHeight[])
{
    for (ll i = 0; i <= (n << 2); i++)
        lazy[i] = mpr(0, 1e9);
    init(0, n - 1, 1);
    for (ll i = 0; i < k; i++)
        if (op[i] == 1)
            modifymax(left[i], right[i], height[i], 0, n - 1, 1);
        else
            modifymin(left[i], right[i], height[i], 0, n - 1, 1);
    build(0, n - 1, 1);
    for (ll i = 0; i < n; i++)
        finalHeight[i] = ans[i].F;
}

Subtask #1
0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 2392 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #2
0 / 24.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 2396 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #3
0 / 29.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 2396 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #4
0 / 39.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 0 ms 2396 KB Output isn't correct
2 Halted 0 ms 0 KB -