제출 #888956

#제출 시각아이디문제언어결과실행 시간메모리
888956JakobZorz휴가 (IOI14_holiday)C++17
24 / 100
427 ms65536 KiB
#include"holiday.h" #include<iostream> #include<vector> #include<algorithm> #include<set> using namespace std; typedef long long ll; const int TREE_SIZE=1<<17; struct SegTree{ int rl,rr; SegTree*ch1,*ch2; ll sum; // sum of active int num; // num of active SegTree(int l,int r){ rl=l; rr=r; ch1=nullptr; ch2=nullptr; sum=0; num=0; } }; ll get_sum(SegTree*node){ if(node==nullptr) return 0; return node->sum; } int get_num(SegTree*node){ if(node==nullptr) return 0; return node->num; } SegTree*activate(SegTree*node,int idx,int val){ SegTree*node2=new SegTree(node->rl,node->rr); node2->ch1=node->ch1; node2->ch2=node->ch2; if(node2->rl==node2->rr-1){ node2->sum=val; node2->num=1; return node2; } int mid=(node2->rl+node2->rr)/2; if(idx<mid){ if(node2->ch1==nullptr) node2->ch1=new SegTree(node2->rl,mid); node2->ch1=activate(node2->ch1,idx,val); }else{ if(node2->ch2==nullptr) node2->ch2=new SegTree(mid,node2->rr); node2->ch2=activate(node2->ch2,idx,val); } node2->sum=get_sum(node2->ch1)+get_sum(node2->ch2); node2->num=get_num(node2->ch1)+get_num(node2->ch2); return node2; } // get sum of biggest k cities ll get(SegTree*node,int k){ //cout<<node<<" "<<node->ch1<<" "<<node->ch2<<" "<<k<<endl; k=min(k,get_num(node)); if(k==0) return 0; if(k==get_num(node)) return get_sum(node); if(get_num(node->ch1)<=k) return get_sum(node->ch1)+get(node->ch2,k-get_num(node->ch1)); return get(node->ch1,k); } vector<SegTree*>gen_trees(vector<int>arr){ int n=(int)arr.size(); vector<pair<int,int>>sorted(n); for(int i=0;i<n;i++) sorted[i]={arr[i],i}; sort(sorted.begin(),sorted.end()); reverse(sorted.begin(),sorted.end()); vector<int>in_sorted(n); for(int i=0;i<n;i++) in_sorted[sorted[i].second]=i; vector<SegTree*>trees; trees.push_back(new SegTree(0,TREE_SIZE)); for(int i=0;i<n;i++) trees.push_back(activate(trees.back(),in_sorted[i],sorted[in_sorted[i]].first)); return trees; } vector<ll>res3; vector<SegTree*>trees3; void gen3(int l,int r,int tl,int tr){ int d=(l+r)/2; // r = how far you go ll res=0; int mid=0; for(int r=tl;r<=d&&r<=tr;r++){ // c = how many cities you actually visit int c=d-r; ll curr=get(trees3[r],c); if(curr>res){ res=curr; mid=r; } } res3[d]=res; if(l<r-1){ gen3(l,d,tl,mid); gen3(d,r,mid,tr); } } // if you can only walk in one direction // return a[d] = most score if you have d days vector<ll>get3(vector<int>arr){ int n=(int)arr.size(); trees3=gen_trees(arr); res3.resize(2*n+1); gen3(0,2*n+1,0,(int)trees3.size()-1); /*vector<ll>res; for(int d=0;d<=2*n;d++){ // r = how far you go ll res1=0; for(int r=0;r<=d&&r<=n;r++){ // c = how many cities you actually visit int c=d-r; res1=max(res1,get(trees[r],c)); } res.push_back(res1); } return res;*/ return res3; } // if you can only walk in one direction and have to go back // return a[d] = most score if you have d days vector<ll>get2(vector<int>arr){ int n=(int)arr.size(); vector<SegTree*>trees=gen_trees(arr); vector<ll>res; for(int d=0;d<=3*n;d++){ // r = how far you go ll res1=0; for(int r=0;2*(r-1)<=d&&r<=n;r++){ // c = how many cities you actually visit int c=d-2*(r-1); res1=max(res1,get(trees[r],c)); } res.push_back(res1); } return res; } // if you first start walking to the left and then right ll get1(vector<int>arr,int d,int s){ int n=(int)arr.size(); vector<int>arr1,arr2; for(int i=s;i>=0;i--) arr1.push_back(arr[i]); for(int i=s+1;i<n;i++) arr2.push_back(arr[i]); vector<ll>val1=get2(arr1),val2=get3(arr2); /*if(n==5){ cout<<"val1 "; for(ll i:val1) cout<<i<<" "; cout<<"\n"; cout<<"val2 "; for(ll i:val2) cout<<i<<" "; cout<<"\n"; }*/ ll res=0; for(int d1=0;d1<=d;d1++){ int d2=d-d1; res=max(res,val1[min(d1,(int)val1.size()-1)]+val2[min(d2,(int)val2.size()-1)]); } return res; } ll findMaxAttraction(int n,int start,int d,int attraction[]){ vector<int>arr; for(int i=0;i<n;i++) arr.push_back(attraction[i]); ll res=get1(arr,d,start); reverse(arr.begin(),arr.end()); return max(res,get1(arr,d,n-start-1)); }
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