#pragma GCC optimize ("O3")
#include <bits/stdc++.h>
#define endl "\n"
using namespace std;
bitset<200000000>onlyOne,hasOne;
void update_tree(int l,int r,int L,int R,int now){
if(l>R || r<L || onlyOne[now]==1)return ;
if(l>=L && r<=R){
onlyOne[now]=1;
hasOne[now]=1;
return;
}
int mid=(l+r)/2;
update_tree(l,mid,L,R,now*2+1);
update_tree(mid+1,r,L,R,now*2+2);
if(onlyOne[now*2+1]==1 && onlyOne[now*2+2]==1)onlyOne[now]=1;
if(hasOne[now*2+1]==1 || hasOne[now*2+2]==1 || onlyOne[now*2+2]==1 || onlyOne[now*2+1]==1)hasOne[now]=1;
}
int ans_tree(int l,int r,int L,int R,int now){
if(l>=6 && r<=10){
//cout<<l<<" _ "<<r<<": "<<hasOne[now]<<endl;
}
if(l>R || r<L || hasOne[now]==0)return 0;
if(onlyOne[now]==1){
//cout<<l<<" )_( "<<r<<endl;
return (min(r,R)-max(l,L)+1);
}
int mid=(l+r)/2;
return ans_tree(l,mid,L,R,now*2+1)+ans_tree(mid+1,r,L,R,now*2+2);
}
int main(){
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int n,c=0;
cin>>n;
for(int t=0;t<n;t++){
int l,r,type;
cin>>type>>l>>r;
l--;r--;
l+=c;
r+=c;
//cout<<l<<"-"<<r<<endl;
if(type==2)update_tree(0,99999999,l,r,0);
else {
c=ans_tree(0,99999999,l,r,0);
cout<<c<<endl;
}
}
return 0;
}
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Correct |
1 ms |
8540 KB |
Output is correct |
2 |
Correct |
1 ms |
8540 KB |
Output is correct |
3 |
Correct |
1 ms |
8540 KB |
Output is correct |
4 |
Correct |
4 ms |
8796 KB |
Output is correct |
5 |
Correct |
5 ms |
8796 KB |
Output is correct |
6 |
Correct |
4 ms |
8796 KB |
Output is correct |
7 |
Correct |
4 ms |
9048 KB |
Output is correct |
8 |
Correct |
15 ms |
13068 KB |
Output is correct |
9 |
Correct |
29 ms |
15460 KB |
Output is correct |
10 |
Correct |
28 ms |
15448 KB |
Output is correct |
11 |
Correct |
29 ms |
15336 KB |
Output is correct |
12 |
Correct |
27 ms |
15308 KB |
Output is correct |
13 |
Incorrect |
23 ms |
4956 KB |
Output isn't correct |
14 |
Halted |
0 ms |
0 KB |
- |