Submission #88697

#	Time	Username	Problem	Language	Result	Execution time	Memory
88697		jasony123123	Kronican (COCI16_kronican)	C++11	100 / 100	1425 ms	4876 KiB

kronican

#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <sstream>
#include <queue>
#include <deque>
#include <bitset>
#include <iterator>
#include <list>
#include <stack>
#include <map>
#include <set>
#include <functional>
#include <numeric>
#include <utility>
#include <limits>
#include <time.h>
#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
//#include <ext/pb_ds/tree_policy.hpp>
//#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
//using namespace __gnu_pbds;
#define FOR(i,start,end) for(int i=start;i<(int)(end);i++)
#define FORE(i,start,end) for(int i=start;i<=(int)end;i++)
#define RFOR(i,start,end) for(int i = start; i>end; i--)
#define RFORE(i,start,end) for(int i = start; i>=end; i--)
#define all(a) a.begin(), a.end()
#define mt make_tuple
#define v vector
#define sf scanf
#define pf printf
#define dvar(x) cout << #x << " := " << x << "\n"
#define darr(x,n) FOR(i,0,n) cout << #x << "[" << i << "]" << " := " << x[i] << "\n"
typedef long long ll;
typedef long double ld;
typedef pair<int, int > pii;
typedef pair<ll, ll> pll;
const ll MOD = 1000000007LL;
const ll PRIME = 105943LL;
const int INF = 1e6;
//template <class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template<class T> void minn(T &a, T b) { a = min(a, b); }
template<class T> void maxx(T &a, T b) { a = max(a, b); }
void io() {
#ifdef LOCAL_PROJECT 
	freopen("input.in", "r", stdin); freopen("output.out", "w", stdout);
#else 
	/* online submission */
#endif 
	ios_base::sync_with_stdio(false); cin.tie(NULL);
}
/*************************COCI 16-17 R3 #3*************************/

//int __builtin_popcount(int s) {
//	int cnt = 0;
//	FORE(i, 0, 31) if (s&(1 << i)) cnt++;
//	return cnt;
//}

int N, K;
int cost[20][20];
int dp[1 << 20];

int main() {
	io();
	cin >> N >> K;
	FOR(i, 0, N) FOR(j, 0, N)
		cin >> cost[i][j];
	FOR(s, 0, 1 << N) {
		dp[s] = INF;
		if (__builtin_popcount(s) <= K) {
			dp[s] = 0;
			continue;
		}
		FOR(i, 0, N) FOR(j, 0, N) if (i!=j && (s&(1 << i)) > 0 && (s & (1 << j)) > 0) {
			minn(dp[s], cost[i][j] + dp[s ^ (1 << i)]);
		}
	}
	cout << dp[(1 << N) - 1] << "\n";
	return 0;
}

• Subtask 1: 100 / 100