Submission #885454

#	Time	Username	Problem	Language	Result	Execution time	Memory
885454		codexistent	Sails (IOI07_sails)	C++14	0 / 100	126 ms	3356 KiB

sails

#include <bits/stdc++.h>
using namespace std;
#define FOR(i, a, b) for(int i = a; i <= b; i++)
#define RFOR(i, a, b) for(int i = a; i >= b; i--)
#define ll long long

struct RangeFenwick {
    vector<int> bit[2];
    int size;

    RangeFenwick(int n){
        size = n + 1;
        bit[0].assign(size + 1, 0), bit[1].assign(size + 1, 0);
    }
    
    void add(bool t, int i, int x){
        for(; i < size; i += i & -i) bit[t][i] += x;
    }

    void range_add(int l, int r, int x){
        add(0, l, x), add(0, r + 1, -x);
        add(1, l, x * (l - 1)), add(1, r + 1, -x * r);
    }

    int pfx_helper(int t, int i){
        int r = 0;
        for(; i > 0; i -= i & -i) r += bit[t][i];

        return r;
    }

    int pfx(int i){
        return pfx_helper(0, i)*i - pfx_helper(1, i);
    }
    int pt(int i){
        return pfx(i) - pfx(i - 1);
    }
};

int main(){
    int N;
    cin >> N;
    pair<int, int> M[N];
    FOR(i, 0, N - 1){
        int h, s;
        cin >> h >> s;
        M[i] = make_pair(h, s);
    }
    sort(M, M + N);

    RangeFenwick T(N);

    FOR(i, 0, N - 1){
        int H = M[i].first, S = M[i].second;
        int PM = T.pt(H - S + 1); // prev max sail

        int a = 1, b = H; // a = lowest index with value <= PM
        while(a < b){
            int m = (a + b) / 2;
            if(PM >= T.pt(m)){
                b = m;
            }else{
                a = m + 1;
            }
        }

        int a2 = 1, b2 = H; // a2 = highest index w value <= PM
        while(a2 < b2){
            int m = (a2 + b2 + 1) / 2;
            if(PM <= T.pt(m)){
                a2 = m;
            }else{
                b2 = m - 1;
            }
        }

        //if(a2 != H) T.range_add(a2 + 1, H, 1);
        //T.range_add(a, a2 - (H - S + 1 - a), 1);
    }

    /*ll R = 0, r = 0, p = -1;
    RFOR(i, N, 1) if(T.pt(i) != 0) {
        if(T.pt(i) - 1 != p) {
            r += T.pt(i) - 1;
            p = T.pt(i) - 1;
        }

        R += r;
    }

    cout << R << endl;*/
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 10
• Subtask 3: 0 / 10
• Subtask 4: 0 / 5
• Subtask 5: 0 / 10
• Subtask 6: 0 / 10
• Subtask 7: 0 / 10
• Subtask 8: 0 / 10
• Subtask 9: 0 / 10
• Subtask 10: 0 / 10
• Subtask 11: 0 / 10