제출 #885362

#제출 시각아이디문제언어결과실행 시간메모리
885362272hnixihom무지개나라 (APIO17_rainbow)C++14
0 / 100
823 ms1048576 KiB
#include "rainbow.h" #include <bits/stdc++.h> using namespace std; const int MXn = 2e5 + 5; const int dx[] = {1, 0, 1}; const int dy[] = {0, 1, 1}; int n, m; struct PST { int val[43 * MXn], idL[43 * MXn], idR[43 * MXn]; int no = 0; int build(int l = 1, int r = n) { int cur = ++no; val[cur] = 0; if (l == r) return cur; int mid = (l + r) >> 1; idL[cur] = build(l, mid); idR[cur] = build(mid + 1, r); return cur; } int update(int i, int v, int oID, int l = 1, int r = n) { // if (l == 1 && r == m) cerr << i << ' ' << v << '\n'; int nod = ++no; if (l == r) { val[nod] = val[oID] + v; return nod; } int mid = (l + r) >> 1; if (i <= mid) { idL[nod] = update(i, v, idL[oID], l, mid); idR[nod] = idR[oID]; } else { idL[nod] = idL[oID]; idR[nod] = update(i, v, idR[oID], mid + 1, r); } val[nod] = val[idL[nod]] + val[idR[nod]]; return nod; } int get(int Lf, int Rt, int id, int l = 1, int r = n) { if (Lf <= l && r <= Rt) { // cerr << id << ' ' << l << ' ' << r << ' ' << val[id] << '\n'; return val[id]; } int mid = (l + r) >> 1; int res = 0; if (Lf <= mid) res += get(Lf, Rt, idL[id], l, mid); if (Rt > mid) res += get(Lf, Rt, idR[id], mid + 1, r); return res; } } T[4]; int root[4][MXn]; bool onboard(int x, int y) { return 1 <= x && x <= n && 1 <= y && y <= m; } vector<int> river[MXn], v1[MXn], v2[MXn], v3[MXn]; void add(int sr, int sc) { river[sc].emplace_back(sr); if (sc > 1) v1[sc - 1].emplace_back(sr); v1[sc].emplace_back(sr); if (sr > 1) v2[sc].emplace_back(sr - 1); v2[sc].emplace_back(sr); v3[sc].emplace_back(sr); for (int k = 0; k < 3; k++) { int xx = dx[k] + sr, yy = dy[k] + sc; if (onboard(xx, yy)) v3[yy].emplace_back(xx); } } void init(int R, int C, int sr, int sc, int M, char *S) { n = R, m = C; add(sr, sc); for (int i = 0; i < M; i++) { if (S[i] == 'N') sr--; if (S[i] == 'S') sr++; if (S[i] == 'W') sc--; if (S[i] == 'E') sc++; // cerr << "(" << sr << ' ' << sc << ")\n"; add(sr, sc); } // cerr << '\n'; for (int t = 0; t < 4; t++) root[t][0] = T[t].build(); // int ro = T[0].update(4, 1, root[0][0]); // cerr << T[0].get(3, 4, ro) << '\n'; for (int c = 1; c <= C; c++) { root[0][c] = root[0][c - 1]; root[1][c] = root[1][c - 1]; root[2][c] = root[2][c - 1]; root[3][c] = root[3][c - 1]; sort(begin(river[c]), end(river[c])); river[c].resize(unique(begin(river[c]), end(river[c])) - river[c].begin()); sort(begin(v1[c]), end(v1[c])); v1[c].resize(unique(begin(v1[c]), end(v1[c])) - v1[c].begin()); sort(begin(v2[c]), end(v2[c])); v2[c].resize(unique(begin(v2[c]), end(v2[c])) - v2[c].begin()); sort(begin(v3[c]), end(v3[c])); v3[c].resize(unique(begin(v3[c]), end(v3[c])) - v3[c].begin()); for (int r: river[c]) { // cerr << r << ' '; root[0][c] = T[0].update(r, 1, root[0][c]); } for (int r: v1[c]) { root[1][c] = T[1].update(r, 1, root[1][c]); } for (int r: v2[c]) { root[2][c] = T[2].update(r, 1, root[2][c]); } for (int r: v3[c]) { root[3][c] = T[3].update(r, 1, root[3][c]); } // cerr << "---\n" << T[0].get(3, 4, root[0][c]) << '\n'; } // cerr << '\n'; } int colour(int ar, int ac, int br, int bc) { int V = (br - ar + 1) * (bc - ac + 1) - (T[0].get(ar, br, root[0][bc]) - T[0].get(ar, br, root[0][ac - 1])); int E = (bc - ac) * (br - ar + 1) - (T[1].get(ar, br, root[1][bc - 1]) - T[1].get(ar, br, root[1][ac - 1])) + (bc - ac + 1) * (br - ar) - (T[2].get(ar, br - 1, root[2][bc]) - T[2].get(ar, br - 1, root[2][ac - 1])); int F = 0; if (ar < br) F = (br - ar) * (bc - ac) - (T[3].get(ar + 1, br, root[3][bc]) - T[3].get(ar + 1, br, root[3][ac])); // cerr << V << ' ' << E << ' ' << F << '\n'; // cerr << V << ' ' << T[0].get(ar, br, root[0][bc]) << ' ' << T[0].get(ar, br, root[0][ac - 1]) << '\n'; return V - E + F; // return 0; } // static int R, C, M, Q; // static int sr, sc; // static char S[100000 + 5]; // // int main() { // scanf("%d %d %d %d", &R, &C, &M, &Q); // scanf("%d %d", &sr, &sc); // if (M > 0) { // scanf(" %s ", S); // } // // init(R, C, sr, sc, M, S); // // int query; // for (query = 0; query < Q; query++) { // int ar, ac, br, bc; // scanf("%d %d %d %d", &ar, &ac, &br, &bc); // printf("%d\n", colour(ar, ac, br, bc)); // } // // return 0; // }
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