이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#pragma GCC optimize("Ofast,unroll-loops")
#define bupol __builtin_popcount
#define int long long
#define ll long long
#define ld long double
#define fi first
#define se second
#define pb push_back
#define lf (id<<1)
#define rg ((id<<1)|1)
#define md ((l+r)>>1)
using namespace std;
const int MAXN = 3e5+20;
const int LOG = 60;
const int MOD = 998244353;
const int SQRT = 520;
const int INF = 1e18;
typedef pair<int,int> pii;
typedef pair<pii,int> ipii;
int n, x;
int a[MAXN], pr[MAXN], su[MAXN], num[MAXN];
vector <int> vec;
signed main(){
ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
cin >> n >> x;
for(int i=1; i<=n; i++) cin >> a[i];
for(int i=1; i<=n; i++){
auto it = lower_bound(vec.begin(), vec.end(), a[i]);
if(it == vec.end()){
vec.pb(a[i]);
} else {
int id = it - vec.begin();
vec[id] = a[i];
}
pr[i] = vec.size();
num[i] = vec.back();
}
for(int i=1; i<=n; i++) cout << pr[i] << " \n"[i==n];
int ans = pr[n];
vec.clear();
for(int i=n; i>=2; i--){
auto it = lower_bound(vec.begin(), vec.end(), -a[i]-x);
if(it == vec.end()){
vec.pb(-a[i]-x);
} else {
int id = it - vec.begin();
vec[id] = -a[i]-x;
}
it = lower_bound(vec.begin(), vec.end(), -num[i-1]);
// cout << i << " i\n";
// for(auto in : vec) cout << in << "in";
// cout << " vec" << (it-vec.begin()) << "\n";
ans = max(ans, pr[i-1]+(it-vec.begin()));
}
cout << ans << '\n';
}
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